Puzzlefor you all!!!!
So here comes a new puzzle for everyone....
you have to use the mathematical operators in between the numbers to get the correct output....
1 1 1 =6
2 2 2 =6
3 3 3 =6
4 4 4 =6
5 5 5 =6
6 6 6 =6
7 7 7 =6
8 8 8 =6
9 9 9 =6
its very simple ,you all can easily solve it....
you have to use the mathematical operators in between the numbers to get the correct output....
1 1 1 =6
2 2 2 =6
3 3 3 =6
4 4 4 =6
5 5 5 =6
6 6 6 =6
7 7 7 =6
8 8 8 =6
9 9 9 =6
its very simple ,you all can easily solve it....
Replies

Kaustubh Katdare(1+1+1)! = 6
2+2+2 = 6
3x33 = 6
4+4(sqrt 4) = 6 [positive square root]
(5/5)+5 = 6
66+6 = 6
7(7/7) = 6
 bah 
(squrt 9) x (sqrt 9)  (sqrt 9) =6 
mahulI hope to answer the 8,
8sqrt(8/(cube root(8))) = 6 
Kaustubh Katdare
If I were not bored, I'd do mahulI hope to answer the 8,
8sqrt(8/(cube root(8))) = 6
cuberoot (8) + cuberoot (8) + cuberoot (8) = 6 ๐ 
mahulWow! that's a lot better.... ๐

deveshwow...
such quick replies..
CE rocks!!!! 
Kaustubh KatdareAyan, take this as yetanother warning. Further spamming will lead to banning. If you want to make test posts, go here 
#LinkSnipped#
of course, instead of posting 'jdfsdlks...', try posting something that makes sense. 
apple6#LinkSnipped#,i think i am so late but..,
(1!+1!+1!)! =6
2+ 2+ 2 =6
3 *3 3 =6
4 +4sqrt(4) =6
(5/5)+ 5 =6
6 +6 6 =6
7(7/7) =6
cuberoot(8)+cuberoot(8)+cuberoot(8) =6
sqrt(9)*sqrt(9) sqrt(9)=6 
apple6#LinkSnipped#, thank you..
You are reading an archived discussion.
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