Load on a column
Columns are vertical members, For example: pillars.
As far as beams are concerned. it is easy to represent the type of loads acting on them by means of free body diagrams. but how can this be done in the case of columns. ?
Now consider this example:
There is a clock hanging on the wall. considering the wall to be a column, how can the free body diagram of the system be drawn, to represent that the clock exerts a load on the wall, by virtue of its weight.
The approach which i considered was, first to resolve the weight component of the clock into the two rectangular components( W*sin Theta and W*cos theta).
How to proceed after this.
As far as beams are concerned. it is easy to represent the type of loads acting on them by means of free body diagrams. but how can this be done in the case of columns. ?
Now consider this example:
There is a clock hanging on the wall. considering the wall to be a column, how can the free body diagram of the system be drawn, to represent that the clock exerts a load on the wall, by virtue of its weight.
The approach which i considered was, first to resolve the weight component of the clock into the two rectangular components( W*sin Theta and W*cos theta).
How to proceed after this.
Replies
-
sweet_honeyno answers yet!!😔
plz answer this...
me too waiting for the answer.. -
zaveri
Do you have any ideas about this ? share them out , even if they are wrong.sweet_honeyno answers yet!!😔
plz answer this...
me too waiting for the answer.. -
sweet_honeyi discussed it with my friend also and we were confused if the clock hung on the wall with a nail shud be considered or not..
since its not mentioned -
zaveri
Yeah the nail should be considered as well. the weight of the nail can be compounded with that of the clock.sweet_honeyi discussed it with my friend also and we were confused if the clock hung on the wall with a nail shud be considered or not..
since its not mentioned -
sweet_honey
i didnt undrstand it because the weight of the clock wud be downwards and the angle wud be zero than how come u resolve it?zaveriThe approach which i considered was, first to resolve the weight component of the clock into the two rectangular components( W*sin Theta and W*cos theta).
may be m wrong.. plz correct me with your thoughts.. -
zaverisweet_honeyi didnt undrstand it because the weight of the clock wud be downwards and the angle wud be zero than how come u resolve it?
may be m wrong.. plz correct me with your thoughts..
no i was wrong. the weight acting would be downwards, and parallel to the column, so hence there is no point in resolving it. -
sweet_honey
may be some concept of action and reaction wud work..zaverino i was wrong. the weight acting would be downwards, and parallel to the column, so hence there is no point in resolving it. -
zaverisweet_honeymay be some concept of action and reaction wud work..
this concept works everywhere, when it comes to any solid mechanics problem.
what i want to know is , what the free body diagram of this system would look like -
sweet_honey
i actually didnt know the answer but tried to solve and didnt reach anywhere..zaverithis concept works everywhere, when it comes to any solid mechanics problem.
what i want to know is , what the free body diagram of this system would look like
so m looking forward for an appropriate answer.. -
SaugataColumns are placed directly under a load. The free body diagram will be most probably a straight-line in downward direction representing a compressive load which you can calculate by rankine's formula. Further depending on the length of the column you have to consider the buckling effect. In case of the wall the portion just underneath the clock will support the load as a column in addition to the rest portion of the wall which will act as a load bearing beam. This is just a proposition.
You are reading an archived discussion.
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