HR asked problem... Try to solve

Replies

• 

  makru921

  Simple. First, empty the 3L tank and fill the 3L tank using the 5L. This leaves 2L in the 5L tank.
  Now Empty 3L tank.
  Pour the 2L from the 5L tank into the 3L tank. This leaves 1L of spare capacity in the 3L tank.
  Fill the 5L tank again
  Fill the 3L tank from the 5L one. This leaves 4L in the 5L tank.😀
• 

  chirag_kotadia

  yes good u got it man!!!!!!!!
• 

  narayana murthy

  nice answer makru
• 

  makru921

  Thanks.. There are many similar measurement questions. You may want to try this:
  
  You have a 4 litre and a 9 litre bucket - and you have to get exactly 6 litres of water, with minimum number of transfers.. How do you get it?? 😀
• 

  Kaustubh Katdare

  Strange, Persistent folks ask such questions in HR round! 😐
• 

  narayana murthy

  take 9l bucket empty fill it with 4l bucket
  now fill 4l bucket half and it becomes 2l pour this in 9l bucket totally 6l
  am i right
• 

  makru921

  narayana murthy

  take 9l bucket empty fill it with 4l bucket
  now fill 4l bucket half and it becomes 2l pour this in 9l bucket totally 6l
  am i right

  Nope, there are no measurements on the buckets which tell you half or quarter. So you cannot take half of a bucket😀 I'm sure you can get it. Use the same principle used for the first one😀
• 

  Sachin Jain

  1. Firstly fill the 9L bucket.
  2. 9L bucket -> 4l bucket and then empty it
  3. Repeat the step 2 and then transfer the remaining 1L from 9L bucket to 4L bucket.
  4. Now the status is : 9L bucket empty and 4l bucket has 1L.
  5. Now Fill the 9L bucket and transfer 3L from 9 -> 4.
  6. Now the 9L bucket contains 6 litres.
• 

  makru921

  Well done blunderboy! That's right😀
• 

  aj_onduty

  Makru, more questions please 😁
• 

  chirag_kotadia

  The_Big_K

  Strange, Persistent folks ask such questions in HR round! 😐

  I didn't get you biggy! Is it so easy or li'l tough?
• 

  Kaustubh Katdare

  chirag_kotadia

  I didn't get you biggy! Is it so easy or li'l tough?

  HR rounds are not supposed to be 'puzzle' rounds. That's what I think.
• 

  chirag_kotadia

  The_Big_K

  HR rounds are not supposed to be 'puzzle' rounds. That's what I think.

  O thats right bigK but you may be surprised to know that I was only asked this puzzle and nothing else. Strange but true!!!!!
• 

  shreyasm89

  Great answer buddy!
• 

  rgc437@gmail.com

  hey first take all the water of both the tanks and pour them in the 3rd tank. then take a bucket and take the water and pour it in to the 2nd tank until the water in the 3rd tank gets half.
  
  hope it could be the answer?😕
• 

  rgc437@gmail.com

  her the water in two tanks 5+3=8.if you do the above process we can two half's of 8 Lt so that we can get the required 4 Lts.
• 

  chirag_kotadia

  rgc437@gmail.com

  her the water in two tanks 5+3=8.if you do the above process we can two half's of 8 Lt so that we can get the required 4 Lts.

  I just answered that in first 2 minutes but he said no half measures are there!!!!!!!!!
• 

  chirag_kotadia

  I took 25 minutes for this problem... so silly!!
• 

  rgc437@gmail.com

  kk then how to do it.
• 

  rashboyz25

  i dont know dude please tell me the answer
• 

  arunorious

  Superb!!!!
• 

  rgc437@gmail.com

  nice answer makur............😀
• 

  chirag_kotadia

  makru has answered it!! on first page!! check it out..
• 

  makru921

  aj_onduty

  Makru, more questions please 😁

  Here is one which got me pondering for hours, but when i got the answer i almost banged my head on the wall..😀
  
  I have 10 bunches of banknotes. Each bunch contains 100 notes, and one of the bunches is entirely of fake notes. Now original notes weigh 1 gram, and fake notes weigh 1.1 grams. You have a weighing scale (capable of weighing upto 1 kg). How can you find out which of the 10 bunches contain the fake notes, by using the weighing scale ONLY ONCE?
• 

  Sachin Jain

  At one time, we can weigh about 1000 original notes as the max weight which can be measured is 1kg.
  Now, here is the solution :-
  
  Arrange the bags in an order.
  Now take 1 note from 1st bag, 2 notes from 2nd bag and so on...10 notes from 10th bag. (Bag or bunch i mean same)
  Now weigh it. There are total 55 notes now.
  Now,
  say x=weight measured-55
  If (x==0.1) Bag1 is of fake notes
  if (x==0.2) Bag2 is of fake notes
  If (x==0.3) Bag3 is of fake notes
  if (x==0.4) Bag4 is of fake notes
  If (x==0.5) Bag5 is of fake notes
  if (x==0.6) Bag6 is of fake notes
  If (x==0.7) Bag7 is of fake notes
  if (x==0.8) Bag8 is of fake notes
  If (x==0.9) Bag9 is of fake notes
  if (x==1) Bag10 is of fake notes
  
  I hope the solution is clear....
  I had already done the similar question earlier...
  Thanks Makru for reminding me the concept.
• 

  makru921

  blunderboy

  At one time, we can weigh about 1000 original notes as the max weight which can be measured is 1kg.
  Now, here is the solution :-
  
  Arrange the bags in an order.
  Now take 1 note from 1st bag, 2 notes from 2nd bag and so on...10 notes from 10th bag. (Bag or bunch i mean same)
  Now weigh it. There are total 55 notes now.
  Now,
  say x=weight measured-55
  If (x==0.1) Bag1 is of fake notes
  if (x==0.2) Bag2 is of fake notes
  If (x==0.3) Bag3 is of fake notes
  if (x==0.4) Bag4 is of fake notes
  If (x==0.5) Bag5 is of fake notes
  if (x==0.6) Bag6 is of fake notes
  If (x==0.7) Bag7 is of fake notes
  if (x==0.8) Bag8 is of fake notes
  If (x==0.9) Bag9 is of fake notes
  if (x==1) Bag10 is of fake notes
  
  I hope the solution is clear....
  I had already done the similar question earlier...
  Thanks Makru for reminding me the concept.

  BB, spot on!
• 

  ISHAN TOPRE

  3\5/inf
  0/5/3
  3/2/3
  0/2/6
  2/0/6
  2/5/1
  3/4/1
  😁
• 

  shreyasm89

  blunderboy

  At one time, we can weigh about 1000 original notes as the max weight which can be measured is 1kg.
  Now, here is the solution :-
  
  Arrange the bags in an order.
  Now take 1 note from 1st bag, 2 notes from 2nd bag and so on...10 notes from 10th bag. (Bag or bunch i mean same)
  Now weigh it. There are total 55 notes now.
  Now,
  say x=weight measured-55
  If (x==0.1) Bag1 is of fake notes
  if (x==0.2) Bag2 is of fake notes
  If (x==0.3) Bag3 is of fake notes
  if (x==0.4) Bag4 is of fake notes
  If (x==0.5) Bag5 is of fake notes
  if (x==0.6) Bag6 is of fake notes
  If (x==0.7) Bag7 is of fake notes
  if (x==0.8) Bag8 is of fake notes
  If (x==0.9) Bag9 is of fake notes
  if (x==1) Bag10 is of fake notes
  
  I hope the solution is clear....
  I had already done the similar question earlier...
  Thanks Makru for reminding me the concept.

  how can we measure the difference in weights? Which weighing scale will give us the difference in two weights?
• 

  shreyasm89

  ishutopre

  3\5/inf
  0/5/3
  3/2/3
  0/2/6
  2/0/6
  2/5/1
  3/4/1
  😁

  What are we supposed to do?Find the next sequence?
• 

  makru921

  shreyasm89

  how can we measure the difference in weights? Which weighing scale will give us the difference in two weights?

  You just have to weigh once. For example if the scale shows 55.1 grams, we can understand it is the first bunch. If the scale shows 55.2 grams, it is the second bunch which has the fake notes, and so on. Hope the concept is clear..
• 

  shreyasm89

  YEah!got it you were talking about a digital weighing meter!..😉
• 

  makru921

  shreyasm89

  YEah!got it you were talking about a digital weighing meter!..😉

  It need not be a digital weighing scale😀 The question says it weighs upto 1 kg only. So even if it is a normal weighing scale, you can easily find out the 0.1 marks
• 

  Sachin Jain

  shreyasm89

  how can we measure the difference in weights? Which weighing scale will give us the difference in two weights?

  Hey you can do this manually.
  Just measure the weight using device and subtract 55 from it manually.
• 

  Kaustubh Katdare

  Guys, please start new threads for the new puzzles. It makes them easier to find by titles 😀