Greatest number

What is the biggest number that can be made by using 1,1,1,1?
Any one dare to solve it?
I think biggie will...lol πŸ˜€

Replies

  • vipandeep
    vipandeep
    2^0+2^1+2^2+2^3 = 15
  • Ankita Katdare
    Ankita Katdare
    11 raised to 11? 😲
  • Kaustubh Katdare
    Kaustubh Katdare
    I'm not math expert. But I think 11[sup]11[/sup] would be quite a big number.
  • ISHAN TOPRE
    ISHAN TOPRE
    Phew! both of you.You were really quick.Hats off...
    correct answer AKD,Biggie.

    @Vipandeep:This is a wrong answer as you have used '2' also.Answer is 11^11.

    😁
  • CIVILPRINCESS
    CIVILPRINCESS
    Okie can you use three zeros and get 6:?:
  • ISHAN TOPRE
    ISHAN TOPRE
    CIVILPRINCESS
    Okie can you use three zeros and get 6:?:
    But why do you want to use 0? when you can get biggest number greater than 6?
    😁

    @CP,Biggie,AKd and all ceans: What do you think about 1111! i.e; 1111factorial?
  • Kaustubh Katdare
    Kaustubh Katdare
    CIVILPRINCESS
    Okie can you use three zeros and get 6:?:
    (0! + 0! + 0!)! => 3! = 3x2x1 = 6.
  • Kaustubh Katdare
    Kaustubh Katdare
    ishutopre
    But why do you want to use 0? when you can get biggest number greater than 6?
    😁

    @CP,Biggie,AKd and all ceans: What do you think about 1111! i.e; 1111factorial?
    I guess the number of operators need to be defined in this case. I can go on adding factorial signs and keep expanding the number.
  • PraveenKumar Purushothaman
    PraveenKumar Purushothaman
    Yes then what about 11! x 11! ??? Goes somewhere more than 11[SUP]11[/SUP]!
  • Kaustubh Katdare
    Kaustubh Katdare
    praveenscience
    Yes then what about 11! x 11! ??? Goes somewhere more than 11[SUP]11[/SUP]!
    That's my point, the number of operators need to be restricted.πŸ˜‰
  • PraveenKumar Purushothaman
    PraveenKumar Purushothaman
    Oki! Even though it can be only upto max of 3... My point is proved! Lolz 😁
  • harshajd
    harshajd
    if the factorial can be used then (11!)^(11!) will be the biggest number

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