anksingla

Below program is to print the values of 2d array s. int s[][2]={12,1,13,214,3}; int i,j; int (*p)[2]; int *pint; For(i=0;i<3;++i) { p=&s; pint=(int*)p; for(j=0;j<2;++j) printf("%d",*(pint+j)); } This will print values...

Shashank MogheExplicit typecasting, I believe? The question to follow is, whether it is necessary.i also think so..but in a below program i got confused.. int s[4][2]

int s[][2]={12,1,13,214,3}; int i,j; int (*p)[2]; int *pint; For(i=0;i<3;++i) { p=&s; pint=(int*)p; for(j=0;j<2;++j) printf("%d",*(pint+j)); } This will print values stored in array s. But in printf statement instead of *(pint+j)...

A.V.RamaniOne way of looking at multiplying by 11 is 'Shift and Add'. In effect adding ten times the number to the number. Put zero in front and at the end...

Anoop KumarOops.... next number will be 161051. #-Link-Snipped-# , has provided you the right solution. 😉I forgot to mention that question is not multiplication of 11.. the question I asked...

Manish GoyalVery Simple Program, Simple Loop, and then a single line if you know multiplicationYeah this program is a simple multiplication of 11 but I was asked this in different...

Sanyam KhuranaFirst show us what you have done so far?i am using net on my phone...can't show you the code that i tried..

Yeah right Anoop KumarWhat is next number?? is it 15101051?

1 11 121 1331 14641 can anyone tell the code of this pattern.??

Which would be the good book for data structure for beginners...??