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@mohit-n7d2qt • Feb 21, 2019
6.6A is the right answer.
@vontari-Sryisp • Feb 21, 2019
@thebigk • Feb 21, 2019
#-Link-Snipped-#Â - Better approach would be to explain how you arrived at two different answers. Could you give it a try?
@vontari-Sryisp • Feb 21, 2019
As they are in series I1 and I3 adds.
But as there is tapping im a little bit confused.
So can you help me out of it.
@vontari-Sryisp • Feb 22, 2019
#-Link-Snipped-#Â please suggest what is the correct answer and complete solution.
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I have got 4.9A, but my friend is saying that it may be 6.6A.
@vontari-Sryisp • Feb 22, 2019
#-Link-Snipped-#Â Thanks for your answer
@ramani-VR4O43 • Feb 23, 2019
#-Link-Snipped-# , you were right.  The tapping at the middle two resistors joining the middle of the two battery banks can be ignored because there is no potential difference between the two ends of the wire.
Therefore, the total current will be the sum of the currents in the two parallel lines.
The current through the two resistors in series will be 31/(9.05+9.05)=1.713 A, the current in the other line is 31/9.5=3.26 A totaling 4.976 A.
@vontari-Sryisp • Feb 23, 2019
Thank you sir #-Link-Snipped-#Â
