VM5  Square of any no.
Now till now you know the square of the no. having 5 and 0 at their end...
Now some other...
Square of the no just 2 next to them..(having 0 and 5 as last digit) means 27,32,37,42,47....like that
Easy....
The fanda here is ...
Add the square of the previous no + nth odd no.
For eg . 32^2
= (30)^2 + 31st Odd no. (which is 2n1, where n starts from 1...means 61) + 32nd Odd no. (which is 2n+1, where n starts from 1...means 61)so square of 31 is 900 + 61+63 = 1024...
or simply add sqaure of 30 + 4n  ??? think why 4n (its 2n1 +2n+1)
from my side.Next lesson will be on monday..... JJ
till than bbye
Now some other...
Square of the no just 2 next to them..(having 0 and 5 as last digit) means 27,32,37,42,47....like that
Easy....
The fanda here is ...
Add the square of the previous no + nth odd no.
For eg . 32^2
= (30)^2 + 31st Odd no. (which is 2n1, where n starts from 1...means 61) + 32nd Odd no. (which is 2n+1, where n starts from 1...means 61)so square of 31 is 900 + 61+63 = 1024...
or simply add sqaure of 30 + 4n  ??? think why 4n (its 2n1 +2n+1)
from my side.Next lesson will be on monday..... JJ
till than bbye
Replies

integratdbrainsi would prefer a diff technique!
for numbers ending in 1 i would rather prefer (a+b)^2 formula!
as u will be knowing this most loved and basic formula in algebra
(a+b)^2=a^2+2ab+b^2
so any number ending in 1
for eg:31^2 the formula will go this way (30+1)^2=30^2+2*30*1+1=900+60+1=961
in short square the round figure number and add twice the round figure and at last add 1 ! same is applicable for numbers ending in 9 but instead of the '+' formula use ''.!
for eg:29^2=(301)^2=30^22*30+1=841 ๐ 
aashimakool ones....
nice techniques ... wud be helful a long way ... am sure...
well with that note i have an easy way of MULTIPLYING ANY NUMBER WITH 11...
we know the table till 10... for higher numbers... foe e.g. any 2 digit number... ad the two digits of the number and put the sum berween the digits....
it goes like... for 35... 3+5=8
then 11*35 will be 385..
simple... 
integratdbrainshello ashima
check out the vedic mathematics workshop3. 
aashimahmm....
well wherz dat???integratdbrainscheck out the vedic mathematics workshop3. 
crooklink
here is the link to #LinkSnipped#
Great job crazyboy, integratdbrains, aashima !
I am sure this is going to be useful to lot of ceans.
I will try to add something too ๐ 
Anil Jain
Means 73*11= 7 (7+3=10)3=7103..is it so???aashimanice techniques ... wud be helful a long way ... am sure...
well with that note i have an easy way of MULTIPLYING ANY NUMBER WITH 11...
we know the table till 10... for higher numbers... foe e.g. any 2 digit number... ad the two digits of the number and put the sum berween the digits....
it goes like... for 35... 3+5=8
then 11*35 will be 385..
simple...
which is wrong
Or it is 1 carry over so it will make it ??
7+1=803???
Do let me correct if i am wrong... 
integratdbrainsCome on!
Come on buddy i don't think there's need of this post.. cuz u already know the answer and she may have been fallen short of explaining in detail! 
Anil JainintegratdbrainsCome on buddy i don't think there's need of this post.. cuz u already know the answer and she may have been fallen short of explaining in detail!
Crazy 
Kaustubh Katdareeasy !
Easy there everyone!
Keep up the good work, crazyboy, Integratdbrains, aashima !
The Big K 
aashimacrazyboyMeans 73*11= 7 (7+3=10)3=7103..is it so???
which is wrong
Or it is 1 carry over so it will make it ??
7+1=803???
Do let me correct if i am wrong...
well i guess thats pertty obvious that in case of a sum resulting in two digit ... it shud be trasferred as a carry to get the right solution and u very well solved it too....
so is there any point of correcting u??? 
aashimaoops....
i just did not notice this before... its absolutely same ๐ well wont let it go this way again ๐integratdbrainscheck out the vedic mathematics workshop3.
thanks for the updation newaz 
aditihere is another method to find square of a no..
2 digit number :
For example: To find the square of 34, start from left hand and following r the steps.
34
1)3^2 = 9
2)2*(3*4) = 24
3)4^2 = 16
4) now we write 9/24/16 ( start writing number from right hand taking only unit's digit and others as carry)
5)the result is 1156
3 digit number :
Example 234, steps are
1) 2^2 = 4
2)2*(2*3) = 12
3)2*(2*4) + 3^2 = 25
4)2*(3*4) = 24
5)4^2 = 16
so we write result as 4/12/25/24/16 and adding by same method
result is 54756
Similarly square of 345 :
9/24/46/40/25 = 119025
square of 4 digit number :
1234
1) 1^2 = 1
2) 2*(1*2) = 4
3) 2*(1*3) + 2^2 = 10
4) 2*{ 1*4 + 2*3 }= 20
5) 2*(2*4) + 3^2 = 25
6) 2*(3*4) = 24
7) 4^2 = 16
so write as 1/4/10/20/25/24/16 = 1522756
similarly square of 4512 : 16/40/33/26/21/4/4 = 20358144
So U can proceed same rule to find squares of other numbers also 
Kaustubh KatdareGood job, Aditi ๐
Can we have more workshops on VM !
The Big K 
aashimagood one
Nice information by aditi. Keep it up. Looking forward to some more knowledgeable stuff in this thread. I wish i could have a maths subject in my curriculum once again ๐ 
Anil JainBumping this thread.
For sure  CEan's who likes maths would love this thread.
CB
You are reading an archived discussion.
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