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T(n)=T(n-1)+1/n
put n= n-1
T(n)=T(n-2)+1/(n-1)+1/n
and so on
............
solve the total it will give sum of nth terms in harmonic series
T(n)=1+1/2+1/3+.....+1/(n-3)+1/(n-2)+1/(n-1)+1/n
approximately sum of n terms in harmonic series is ln(n)+.5772156649...
T(n)=ln(n)+.5772156649 timecomplextiy is O(ln(n))
hi, this problem uses log n series ....i can evalute only up to sum of n term ...........thanx for reply to this question........i already posted one question .......... average paged m/y access time question........till anyone cant solve the problem?....u solve the problem
Suppose the cache and main memory access times are 100 ns and 1200 ns respectively. The cache is used for paging and the hit ratio of finding the page table entry in the cache is 98%, what is the effective paged memory access time?