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  • Banashree Patra
    Banashree Patra

    Member • Sep 2, 2011

    sets

    85 are married, 80 have cars, 75 have phones, and 70 have houses. How many minimumpersons are married, have phone, car and houses on a scale of 100.
    ......................show me the steps for solving this.😕
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  • Ramani Aswath

    Member • Sep 2, 2011

    Banashree Patra
    85 are married, 80 have cars, 75 have phones, and 70 have houses. How many minimumpersons are married, have phone, car and houses on a scale of 100.
    ......................show me the steps for solving this.😕
    If the total number of people is 100,
    then the minimum number of those who are both married and have houses is 85 + 70 - 100 = 55 ...(1)
    and the minimum number of those who have both car and phone is 80 + 75 - 100 = 55...(2)
    From this, the number of those who are married and have house and car and phone is 55 + 55 - 100 = 10

    I am sorry that this is not a formal way of doing it. However, I had not done any course on set theory. I am sure there are many CEans, who can give you a structured answer.
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