puzzle..

Replies

• 

  sookie

  Given :
  C1(Condition 1): difference-in height amongst the first three men is two inches
  C2(Condition 2): difference between the third and fourth is six inches
  Average height= 74
  
  Solution:
  Let first man's height= x
  Second man's height= x+2 (as per C1)
  Third man's height= (x+2)+2= x+4 (as per C1)
  Fourth man's height= (x+4)+ 6 = x+10(as per C2)
  
  Average = (First man's height+ Second man's height+ Third man's height+ Fourth man's height)/Total no of men
  
  Average = (x+(x+2)+(x+4)+(x+10))/4 = 74
  Solving it we get x=70
  so now
  First man's height= 70
  Second man's height= x+2 = 70+2=72
  Third man's height= x+4 = 70+4= 74
  Fourth man's height= x+10 = 70+10=80
  
  Was this so simple or still any other thing for puzzling us is there 😔 ..Please tell
• 

  sherya mathur

  lets the height of third person is=x
  therefore the height of the forth person will be=x-6
  from the first condition
  the second person will be=x+2
  the first person will be=x+4
  given average height=74
  hence total height will be =74 x4=296
  which will be equal to
  (x+4)+(x+2)+(x)+(x-6)=296
  4x=296
  x=74
  therefore answers are
  first=78
  second=76
  third=74
  fourth=68