PHP Version of FLAMES Ready!
Question asked by Praveen Kumar Purushothaman in #PHP on May 16, 2011
Praveen Kumar Purushothaman · May 16, 2011
Member of CrazyEngineers
Hey guys... As discussed at https://www.crazyengineers.com/forum/computer-science-engineering/22952-flames-code.html the code for Flames using PHP is ready! 😀
PHP Version of the same is ready... 😀
Posted in:
#PHP
PHP Version of the same is ready... 😀
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "https://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="https://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Flames by Praveen</title>
<style type="text/css">
body, input {font-family: candara, tahoma; font-size: 12px; width: 150px;}
form div {margin: 5px;}
</style>
</head>
<body>
<?php
$flames = array(
"F" => "Friends",
"L" => "Lovers",
"A" => "Affectionate",
"M" => "Married",
"E" => "Enemies",
"S" => "Siblings"
);
if(isset($_GET["names"]))
if(count($_GET["names"])==2)
{
$n1 = strtoupper(str_replace(" ", "", $_GET["names"][0]));
$n2 = strtoupper(str_replace(" ", "", $_GET["names"][1]));
if($n1 == $n2)
echo "<div>Both the names are same!</div>";
else
{
for($i = 0; $i < strlen($n1); $i++)
{
if(isset($n1[$i]))
for($j = 0; $j < strlen($n1); $j++)
if(isset($n2[$j]))
if($n1[$i] == $n2[$j])
{
$n1[$i] = $n2[$j] = "/";
break;
}
}
$n1 = str_replace("/", "", $n1);
$n2 = str_replace("/", "", $n2);
$count = strlen($n1) + strlen($n2);
$flame = "FLAMES";
echo "<div>";
while(strlen($flame)!=1)
{
$flame[$count%strlen($flame)] = "/";
$flame = str_replace("/", "", $flame);
}
echo "You both are [b]" . $flames[$flame] . "[/b]</div>";
}
}
else ;
else
{?>
<form method="get" action="">
<div>Enter the Names</div>
<div><input type="text" name="names[]" /></div>
<div><input type="text" name="names[]" /></div>
<div><input type="submit" value="Get Relation" /></div>
</form>
<?php } ?>
</body>
</html>
eternalthinker · Aug 4, 2011
Member of CrazyEngineers
I was trying to implement FLAMES in python seeing this thread, but then I met with a doubt.
While counting, we strike the FLAMES letter where the count stopped and start again from the next letter right?
The above code will start counting from the first letter every time I suppose.
While counting, we strike the FLAMES letter where the count stopped and start again from the next letter right?
The above code will start counting from the first letter every time I suppose.
Praveen Kumar Purushothaman · Aug 4, 2011
Member of CrazyEngineers
Ah crap!!! 😔 Yeah man... How to make it right??? 😲
eternalthinker · Aug 4, 2011
Member of CrazyEngineers
In a straightforward way, we'll have to simulate the actual counting using a count variable.
But I'm sure if we process enough mathematics in our brains, some efficient equation will pop up 😀
But I'm sure if we process enough mathematics in our brains, some efficient equation will pop up 😀
Praveen Kumar Purushothaman · Aug 4, 2011
Member of CrazyEngineers
Yup... am working on it... But are you sure this one is wrong? 😐 Tried so hard.. 😔
eternalthinker · Aug 4, 2011
Member of CrazyEngineers
The whole code is nicely written 😀
But when we do count%strlen, the counting is always starting from the beginning right.
Or suppose if we stop counting in the middle in a case; that information is not tracked anywhere in the code.
Just small changes in the counting alone 😀
But when we do count%strlen, the counting is always starting from the beginning right.
Or suppose if we stop counting in the middle in a case; that information is not tracked anywhere in the code.
Just small changes in the counting alone 😀
Praveen Kumar Purushothaman · Aug 4, 2011
Member of CrazyEngineers
Thanks ,,, Will add this part and release.. 😁
eternalthinker · Aug 4, 2011
Member of CrazyEngineers
Praveen Kumar Purushothaman · Aug 5, 2011
Member of CrazyEngineers
Yes, but I am still in the situation of where to initialize the counter and its value! 😲eternalthinkerI just made the python code. It's posted in here
The counting logic is slightly changed 😀
eternalthinker · Aug 6, 2011
Member of CrazyEngineers
In the python code, I kept track of the position where we stop counting in each iteration.praveenscienceYes, but I am still in the situation of where to initialize the counter and its value! 😲
If we stop at $pos last time, then the next stopping position will be $pos = ($count + $pos) % strlen($flame)
Praveen Kumar Purushothaman · Aug 6, 2011
Member of CrazyEngineers
Dude... Good one... Will try ... Behold... 😁
