just solve it!!!
Puzzle 1:
Who stole the clock?![[IMG]](proxy.php?image=http%3A%2F%2Ffreepuzzles.com%2Fimages%2Fpuzzles%2FLogic%2FLogic017s.jpg&hash=379d5d303dd318e89200733117212797)
![[IMG]](proxy.php?image=http%3A%2F%2Ffreepuzzles.com%2Fimages%2Fbackground%2Ftrans.gif&hash=e2c3c609da8255089971513ae032970d)
If Robort was the thief, he was telling the truth, Tommy did not steal but was telling a lie: Scott is innnocent. It meant Scott was the thief which was not true becasue we assumed Robert was the thief.
If Scott was the thief, then both Robert and Tommy told a lie. It meant Tommy and Scott both were thief which was not true.
Tommy was the thief, what he said was true: Scott was innocent. Robert told a lie, which meant Tommy was the thief.
puzzle 2:
![[IMG]](proxy.php?image=http%3A%2F%2Ffreepuzzles.com%2Fimages%2Fpuzzles%2FWeight%2FWeight005.jpg&hash=6fbeba8d599d7bc26368726b16981d22)
Among 6 coins one is heavier than all the others. You can weigh only 2 times to find out which one is heavier.
Who stole the clock?
If Robort was the thief, he was telling the truth, Tommy did not steal but was telling a lie: Scott is innnocent. It meant Scott was the thief which was not true becasue we assumed Robert was the thief.If Scott was the thief, then both Robert and Tommy told a lie. It meant Tommy and Scott both were thief which was not true.
Tommy was the thief, what he said was true: Scott was innocent. Robert told a lie, which meant Tommy was the thief.
puzzle 2:
Among 6 coins one is heavier than all the others. You can weigh only 2 times to find out which one is heavier.
Replies
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reachrkataPuzzle 2 solution :
Take 4 coins randomly and put two on either side of the balance
Case 1: Both sides are equal.
then the heavy coin is in the remaining 2 coins not chosen. The exact one can be found by one more weighing.
Case 2: One of the sides is heavier.
The heavier one is on that particular side. The exact one can be found by one more weighing.
😁
Yahoo !!! -
ish_nalinireachrkataPuzzle 2 solution :
Take 4 coins randomly and put two on either side of the balance
Case 1: Both sides are equal.
then the heavy coin is in the remaining 2 coins not chosen. The exact one can be found by one more weighing.
Case 2: One of the sides is heavier.
The heavier one is on that particular side. The exact one can be found by one more weighing.
😁
Great your right!!!!!!!!!!!!!!!!!! -
pradeep_agrawalAnother approach that helps in optimizing other similar cases:
Step 1: Take 3-3 coins randomly and put on either side of the balance. This will give you a set of 3 coin which contain heavier coin.
Step 2: From the above obtained 3 coin set, take 1-1 coin randomly and put on either side of the balance and keep 1 coin separate.
Step 3: If the balance is unbalanced, the heavier coin is on the heavier side of balance, otherwise the third coin is the heavier coin.
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