find the % increase in population after 2 years ?

Sir / madam,
My question is

The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ?

Advance Thanks,
R.Rengaraj
{3i Infotech-QNo:62}

Replies

  • AshNZ
    AshNZ
    let population now be 100

    after one year, population is 108 (4% + 4%)

    after 2 years, population is (.08*108)+108 = 117 (0 d.p.)

    increase in population = 117 - 100 = 17

    % increase = (17/100) * 100 = 17%

    this is my guess. hope someone can check it.
  • sherya mathur
    sherya mathur
    The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ?

    let population now be 100
    as given population increased 4% p.a.
    therefore population will be 104 after one year
    and also given additional increment in population due to job seekers is 4%
    therefore population will be =104+104X0.04
    =104+4.16
    =108.16
    after one year, population is 108 (4% + 4%)

    after 2 years, population is (.04*108.16)+108.16 = 112.4864
    due to job seekers population will be after two years=116.986256
    increase in population = 116.986256 - 100 = 16.986256

    % increase = (16.986256/100) * 100 = 116.986256%

You are reading an archived discussion.

Related Posts

plz suggest me some latest seminar topics for a technical seminar at college.
Sir / madam, My question is 4a3+984=13b7.13b7 is divisible by 11. Find a+b. Advance Thanks, R.Rengaraj
some useful html tips Many times I have seen sometimes in some websites there are links created on image itself today i learn it...so I would like to share it...
I have passed my MCA in 2006 and also have almost 2 years of work experience; now I want to go for higher studies but I am confused whether I...
I looked up your article on Hydrogen Inversion Temperature & non-Joule Thomson cooling in Wikipedia. Its unfortunate that a know-it-all made you resign. I understand the concept from the formula...