@rengaraj • 20 Dec, 2009
My question is

The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ?

R.Rengaraj
{3i Infotech-QNo:62}
@AshNZ • 07 Jan, 2010 let population now be 100

after one year, population is 108 (4% + 4%)

after 2 years, population is (.08*108)+108 = 117 (0 d.p.)

increase in population = 117 - 100 = 17

% increase = (17/100) * 100 = 17%

this is my guess. hope someone can check it.
@sherya mathur • 16 Mar, 2010 The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ?

let population now be 100
as given population increased 4% p.a.
therefore population will be 104 after one year
and also given additional increment in population due to job seekers is 4%
therefore population will be =104+104X0.04
=104+4.16
=108.16
after one year, population is 108 (4% + 4%)

after 2 years, population is (.04*108.16)+108.16 = 112.4864
due to job seekers population will be after two years=116.986256
increase in population = 116.986256 - 100 = 16.986256

% increase = (16.986256/100) * 100 = 116.986256%

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