C++ Programs by Yamrajbhalla

Replies

• 

  pradeep_agrawal

  The program looks good except the logic of for * (multiplication) and / (division). The code for that was mentioned as
  
  

    complex operator *(complex c)
   {complex t;
     t.real=real*c.real;
     t.img=img*c.img;
     return t;
     }
    complex operator /(complex c)
    {complex t;
     t.real=real/c.real;
     t.img=img/c.img;
     return t;
    }
  

  with output
  (3+3i) * (5+5i) =(15+15i)
  (3+3i) / (5+5i) =(0.6+0.6i)
  
  The output should be
  (3+3i) * (5+5i) = 3*5 + 3i*5 + 3*5i + 3i*5i = 15 + 15i + 15i -15 = (0+30i)
  
  (3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)]
  = (15 + 15i -15i + 15) / (25 + 25i -25i + 25) = 30/50 = 0.6 = (0.6+0i)
  
  Coding for multiplication should be easy. Lets try coding for division.
  
  -Pradeep
• 

  shalini_goel14

  pradeep_agrawal

  (3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5+5i)/(5+5i)]
  = (15 + 15i -15i + 15) / (25 + 25i -25i + 25) = 30/50 = 0.6 = (0.6+0i)
  
  Coding for multiplication should be easy. Lets try coding for division.
  
  -Pradeep

  Hey pradeep, Don't you think for division it should be like following :
  (3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)]
  
  Please correct me if anything wrong. 😔
  
  Thanks !
• 

  pradeep_agrawal

  Yes that should be [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)].
  
  I did all calculation using [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)] but mentioned [(3+3i)/(5+5i)] * [(5+5i)/(5+5i)] by mistake.
  
  Thanks for correcting me. I am modifying the above statement to reflect this.
  
  -Pradeep
• 

  yamrajbhalla

  bro after posting this i have chnged the code for multiplication and divison bt i stuck with fever and i am nt able to update it
  by the way thanks for view my post