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# C++ Programs by Yamrajbhalla

This Will Do the +,-,*and / of the complex numbers

/*Operator overloading for complex Numbers*/ #include#include class complex { float real; float img; public: complex() { real=img=0; } complex(float real,float img) { this->real=real; this->img=img; } void setcomplex(float r,float i) { real=r; img=i; } void print() { cout<

out put

(3+3i) + (5+5i) =(8+8i)

(3+3i) - (5+5i) =(-2+-2i)

(3+3i) * (5+5i) =(15+15i)

(3+3i) / (5+5i) =(0.6+0.6i)

The program looks good except the logic of for * (multiplication) and / (division). The code for that was mentioned as

(3+3i) * (5+5i) =(15+15i)

(3+3i) / (5+5i) =(0.6+0.6i)

The output should be

(3+3i) * (5+5i) = 3*5 + 3i*5 + 3*5i + 3i*5i = 15 + 15i + 15i -15 = (0+30i)

(3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)]

= (15 + 15i -15i + 15) / (25 + 25i -25i + 25) = 30/50 = 0.6 = (0.6+0i)

Coding for multiplication should be easy. Lets try coding for division.

-Pradeep

complex operator *(complex c) {complex t; t.real=real*c.real; t.img=img*c.img; return t; } complex operator /(complex c) {complex t; t.real=real/c.real; t.img=img/c.img; return t; }with output

(3+3i) * (5+5i) =(15+15i)

(3+3i) / (5+5i) =(0.6+0.6i)

The output should be

(3+3i) * (5+5i) = 3*5 + 3i*5 + 3*5i + 3i*5i = 15 + 15i + 15i -15 = (0+30i)

(3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)]

= (15 + 15i -15i + 15) / (25 + 25i -25i + 25) = 30/50 = 0.6 = (0.6+0i)

Coding for multiplication should be easy. Lets try coding for division.

-Pradeep

Hey pradeep, Don't you think for division it should be like following :pradeep_agrawal(3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5+5i)/(5+5i)]

= (15 + 15i -15i + 15) / (25 + 25i -25i + 25) = 30/50 = 0.6 = (0.6+0i)

Coding for multiplication should be easy. Lets try coding for division.

-Pradeep

(3+3i) / (5+5i) = [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)]

Please correct me if anything wrong. 😔

Thanks !

Yes that should be [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)].

I did all calculation using [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)] but mentioned [(3+3i)/(5+5i)] * [(5+5i)/(5+5i)] by mistake.

Thanks for correcting me. I am modifying the above statement to reflect this.

-Pradeep

I did all calculation using [(3+3i)/(5+5i)] * [(5-5i)/(5-5i)] but mentioned [(3+3i)/(5+5i)] * [(5+5i)/(5+5i)] by mistake.

Thanks for correcting me. I am modifying the above statement to reflect this.

-Pradeep

bro after posting this i have chnged the code for multiplication and divison bt i stuck with fever and i am nt able to update it

by the way thanks for view my post

by the way thanks for view my post