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  • Strings : Why is this program not printing the first element?

    Aadit Kapoor

    Aadit Kapoor

    @aadit-kapoor-EBxnXT
    Updated: Mar 18, 2014
    Views: 1.2K
    Why is this program not printing the first element?
    #include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(void)
{
    char names[][5] = {
        "aadit",
        "jobs",
        "mark",
    };



    printf("%s\n",names[0]);
    getch();
}

    when I printf(%s",names[0]) it shows aaditjobs.
    0
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Replies

  • [Prototype]

    Member • Mar 18, 2014

    The first name you specified actually requires 6 byte of space. So what's effectively happening is, at the run time, aadit took 5 byte with \0 not coming into picture because it's beyond the memory being held by the array. This made the program to think the string has not yet finished and making it jump to the next memory location pointing to jobs\0. This time, since jobs is only 4 bytes it finds the 5th byte as terminating char thus finishing the print.

    If you make jobs as jobss, it'll move forward to print mark as well.
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  • Aadit Kapoor

    Member • Mar 18, 2014

    Thank you!
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