puzzle..
Next door to me live four brothers of different heights. Their average height is 74 inches, and the differencein height amongst the first three men is two inches. The difference between the third and fourth is six inches. Can you tell how tall is each brother?
PS: Post detailed solution
PS: Post detailed solution
Replies

sookieGiven :
C1(Condition 1): differencein height amongst the first three men is two inches
C2(Condition 2): difference between the third and fourth is six inches
Average height= 74
Solution:
Let first man's height= x
Second man's height= x+2 (as per C1)
Third man's height= (x+2)+2= x+4 (as per C1)
Fourth man's height= (x+4)+ 6 = x+10(as per C2)
Average = (First man's height+ Second man's height+ Third man's height+ Fourth man's height)/Total no of men
Average = (x+(x+2)+(x+4)+(x+10))/4 = 74
Solving it we get x=70
so now
First man's height= 70
Second man's height= x+2 = 70+2=72
Third man's height= x+4 = 70+4= 74
Fourth man's height= x+10 = 70+10=80
Was this so simple or still any other thing for puzzling us is there ðŸ˜” ..Please tell 
sherya mathurlets the height of third person is=x
therefore the height of the forth person will be=x6
from the first condition
the second person will be=x+2
the first person will be=x+4
given average height=74
hence total height will be =74 x4=296
which will be equal to
(x+4)+(x+2)+(x)+(x6)=296
4x=296
x=74
therefore answers are
first=78
second=76
third=74
fourth=68
You are reading an archived discussion.
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