Puzzle Busters Corner

@thebigk • Mar 20, 2006

[FONT=Verdana, Arial, Helvetica]No Google For this one please 😀

->A famous problem: Prove that "if 4=5 then Russell is the Pope of Rome"

I'll wait for a few days before posting the answer. 😁

-The Big K-
[/FONT]

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Anil Jain

@CrazyBoy • Mar 20, 2006

The_Big_K
[FONT=Verdana, Arial, Helvetica]No Google For this one please 😀

->A famous problem: Prove that "if 4=5 then Russell is the Pope of Rome"

I'll wait for a few days before posting the answer. 😁

-The Big K-
[/FONT]

When will you reply the answer of last one....😔

0

@thebigk • Mar 20, 2006

Chill !

The first problem is a 'challenge' !

Let's see who cracks it 😉

For the time being, try the latest puzzle 😀

-The Big K-

0

@thebigk • Jun 27, 2006

The_Big_K
[FONT=Verdana, Arial, Helvetica]No Google For this one please 😀

->A famous problem: Prove that "if 4=5 then Russell is the Pope of Rome"

I'll wait for a few days before posting the answer. 😁

-The Big K-
[/FONT]

It seems this one has no takers. Well, it wasn't a puzzle 😉 . Here's the most logical answer 😁

We have "5 = 4".
Subtract 3 from both sides: 2 = 1.
Russell and the Pope are are two people.
Since "2 = 1", they are one.

0

@thebigk • Jun 27, 2006

Complete the Series

Here's a tough one - Try your luck.

Complete the following series & explain the logic: -

4, 6, 9, 12, 15, 18, 21, 26, 30, _ , _ , _ ....

-The Big K-

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Neha

@neha-3vibjn • Jun 27, 2006

😔 i give up...Lets c who solves it.

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rick

@rick-JybHX8 • Jun 27, 2006

The_Big_K
It seems this one has no takers. Well, it wasn't a puzzle 😉 . Here's the most logical answer 😁

We have "5 = 4".
Subtract 3 from both sides: 2 = 1.
Russell and the Pope are are two people.
Since "2 = 1", they are one.

😕 😕 😕

where do we report spam? 😁

4, 6, 9, 12, 15, 18, 21, 26, 30, _ , _ , _ ....
biggie wouldn't post it if it was easy. let me try this. Neha gave up so soon?

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Neha

@neha-3vibjn • Jun 27, 2006

I actually agree that biggie wud not have post it if it was that easy and i tried it but couldn't find a solution and on the other side waz not in a mood to solve coz i gave ma maths xam today only....so am on rest 😉

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@thebigk • Jun 27, 2006

hint

Its got something to do with the Prime Numbers 😁 .

No more clues. Try it out in your free time, fellaz.

All the best [IMG]

😀

-The Big K-

0

@thebigk • Jun 29, 2006

No takers?

It seems that prime numbers scare you 😎 !

No takers? 😉

0

@thebigk • Jul 7, 2006

huh

It seems that we have no takers for the sequence puzzle. Too tough ? uh? 😁

-The Big K-

p.s: I'll post the answer tomorrow.

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@thebigk • Jul 7, 2006

and the logic ...

The Logic is ..

Average of two consecutive odd primes ...

😁 easy, huh ?

-The Big K-

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Jerry

@jerry-5wPKU7 • Jul 8, 2006

It was not difficult. I did not really notice this question. I'll try to be frequent on forums 😉

Jerry

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Neha

@neha-3vibjn • Jul 12, 2006

Puzzle alwaz seems easy when u have the solution with u😉

Looking for some more!!!!

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@thebigk • Jul 12, 2006

Try this one now -

neha
Puzzle alwaz seems easy when u have the solution with u😉

Looking for some more!!!!

Oh really? 😉

Try this - ( should be easy )

-6 = -6
9-15 = 4-10

adding 25/4 to both sides:
9-15+(25/4) = 4-10+(25/4 )

Changing the order
9+(25/4)-15 = 4+(25/4)-10

(this is just like : a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

3 = 2 😒 😁

What's wrong with the above ?

-The Big K-

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@integratdbrains-8bmazm • Jul 12, 2006

Solved this...

The_Big_K
Let's dedicate this place to Puzzle Busters! The CE Genius Team 8)

Note# Google / Yahoo / MSN is banned for the team here. Use only brainz , no internet! 😁

Here comes the first challenge -

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

-The Big K-

I tried solving this but got 2007 as the answer biggie can i use 1 more number ! 😔 that is 1 ! 😀

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@thebigk • Jul 12, 2006

May us have a look at the rough work that lead to 2007 ? 😉

-The Big K-

0

@aashima-eO93l9 • Jul 12, 2006

oops!!!

gave it try... but 😉
wats the solution biggie???

0

@thebigk • Jul 12, 2006

i don't know

I don't know 😕

😁😁

-The Big K-

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@aashima-eO93l9 • Jul 12, 2006

haan??

The_Big_K
I don't know 😕

😁😁

-The Big K-

how is it possible... i tried but cud not do it... newaz will wait for the solution .....

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@thebigk • Jul 12, 2006

aashima
how is it possible... i tried but cud not do it... newaz will wait for the solution .....

Never Give Up -> Makes you a true !

Wait for Integratdbrains to post her answer. I'm sure she'll get it.

😁

-The Big K-

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@integratdbrains-8bmazm • Jul 12, 2006

biggie

How about if u asist me to get the right answer! 😉 Well I will surely try to get the right answer! 😀

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@thebigk • Jul 13, 2006

I will

But ... let us wait for the angel from Heaven who'd solve that puzzle for us .

Oh, is it really "that" difficult? 😒

-The Big K-

p.s: Do let us know how you arrived at 2007.

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@integratdbrains-8bmazm • Jul 13, 2006

The_Big_K
Oh really? 😉

Try this - ( should be easy )

-6 = -6
9-15 = 4-10

adding 25/4 to both sides:
9-15+(25/4) = 4-10+(25/4 )

Changing the order
9+(25/4)-15 = 4+(25/4)-10

(this is just like : a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

Taking mod on both sides. while subtracting the denominators of the numbers should be same! one cannot cancel the numbers!
/(3*2-5)/2/= /(2*2-5)/2/
/1/=/1/

The common CE sentence!"correct me if m wrong!"😒😁

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@thebigk • Jul 14, 2006

and here comes the tough one ( is it ? )

Okay !

Now this one will surely give you a good time 😀 !

How is this possible? -

(Edit: Removed the thumbnail and added the link -)

#-Link-Snipped-#

Thinks about it and post logical answer !

No kidding !

-The Big K-

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@integratdbrains-8bmazm • Jul 14, 2006

biggie

can't see the letters in green! plz can u manage to post an enlarged version!

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@thebigk • Jul 14, 2006

updated the link

The thumbnail has been removed and added a flickr link 😁

You have to explain if this is an optical illusion or just a math trick or is it something else?

Interesting, isn't it? 😉

-The Big K-

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@aashima-eO93l9 • Jul 16, 2006

its high time

even i am tired trying it so much... let the solution out biggie

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@thebigk • Jul 16, 2006

no free lunches

aashima
even i am tired trying it so much... let the solution out biggie

No Free Lunches to the CEans . Stretch the crazy brains to the limit !

The solution will follow, keep watching ! 😁

-The Big K-

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@aashima-eO93l9 • Jul 16, 2006

ann...

biggie are u sure the question has no faults??? coz it seems so... 😉

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@thebigk • Jul 17, 2006

you decide

aashima
biggie are u sure the question has no faults??? coz it seems so... 😉

You tell us that! Rearrangement of blocks produces the hole?

Or something's wrong in there 😁

Find out!

-The Big K-

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crook

@crook-0PFkJv • Jul 19, 2006

here is my explanation

This is a typical case of optical illusion. It is very simple. Take the 'tan' of the angle at the top using the upper block. I mean, in first figure - take the tan of top angle using the top green triangle & in the second, the top red triangle.

The value is different in each case. This explains that the second triangle is not a perfect triangle.

[IMG]

I think I got it right.

Crooook

0

@aashima-eO93l9 • Jul 19, 2006

The_Big_K
You tell us that! Rearrangement of blocks produces the hole?

Or something's wrong in there 😁

Find out!

-The Big K-

well this one was for the 345678 maths question.. i didnt check the blok game b4... will just try out.

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@aashima-eO93l9 • Jul 19, 2006

let me try explaining

crook
This is a typical case of optical illusion. It is very simple. Take the 'tan' of the angle at the top using the upper block. I mean, in first figure - take the tan of top angle using the top green triangle & in the second, the top red triangle.

The value is different in each case. This explains that the second triangle is not a perfect triangle.

I think I got it right.

Crooook

well a second possibility cud be as follows:
if we look at the picture... we shall notice the base of the triangle is longer w.r.t the perpendicular. this is because (in the first picture) the triangle in red has a long base to add up with the base of the initial triangle....
now if we re-arrange the blocks... we have placed this longer base red triangle on the top while a triangle with a smaller base (the green one) is placed at the bottom... now to maintain the same base as b4 the two " L" blocks have to be placed at a block's gap.... more over they bein initially designed to interlink to form a vertical block have now been used vertically... so they go out of order...

i hope i was fair enough to explain my point... do let me know in case of ne doubts...

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@thebigk • Aug 6, 2006

Have you all given up or what? Let the answers flood in 😉

-The Big K-

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@aashima-eO93l9 • Aug 6, 2006

well

so whats the answer biggie??

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@thebigk • Aug 14, 2006

Unusual paragraph

The figure is not correct and it can be proved in various ways.

Try this -

"I'm curious how quickly you can find out what is so unusual about it.
It Looks so plain you would think nothing was wrong with it. In fact,
Nothing Is wrong with it! It is unusual though. Study it, and think about it, but You still may not find anything odd. But if you work at it a bit, you might find out."
-The Big K-

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crook

@crook-0PFkJv • Aug 18, 2006

The_Big_K
The figure is not correct and it can be proved in various ways.

Try this -

"I'm curious how quickly you can find out what is so unusual about it.
It Looks so plain you would think nothing was wrong with it. In fact,
Nothing Is wrong with it! It is unusual though. Study it, and think about it, but You still may not find anything odd. But if you work at it a bit, you might find out."

-The Big K-

The paragraph does not contain letter 'e'.

Croook

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@thebigk • Aug 19, 2006

crook
The paragraph does not contain letter 'e'.

Croook

There you go buddy! The paragraph does not contain letter 'e' !

Way to go ! 😁

-The Big K-

0

@thebigk • Nov 29, 2006

Easy one for CEans -

 
Half circle full circle half circle A, half circle full circle 
right angle A

😁

-The Big K-

0

@integratdbrains-8bmazm • Nov 30, 2006

That's too simple to be asked on CE !

It is COCA COLA ! :smile:

CEans deserve tougher questions

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@integratdbrains-8bmazm • Nov 30, 2006

Here comes one!

There is one word in english language that is always pronounced incorrectly.What is it?
😒

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@thebigk • Nov 30, 2006

Re: Here comes one!

integratdbrains
There is one word in english language that is always pronounced incorrectly.What is it?
😒

"Incorrectly" is often pronounced Incorrectly. :sleeping:

Correct? 😉

-The Big K-

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instruite

@instruite-3JCI35 • Dec 18, 2006

The_Big_K
Let's dedicate this place to Puzzle Busters! The CE Genius Team 8)

Note# Google / Yahoo / MSN is banned for the team here. Use only brainz , no internet! 😁

Here comes the first challenge -

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

-The Big K-

I had solve this puzzle when I was in college
people normally don't get answer for this puzzle because they tend to forget "( )" and "^" (power to) are part of the mathematical expressions 😀

Answer is (8 - 7 * 6) * (5 - 4 ^ 3) = 2006

0

instruite

@instruite-3JCI35 • Dec 18, 2006

Here is a new one for all CEians

Question: In the basement there are 3 light switches in the off position. Each switch controls 1 of 3 light bulbs on the floor above. You may move any of the switches, but you may only go up stairs one time. How can you determine which switch controls each light?

I guess it should be easy 😁

0

reachrkata

@reachrkata-FOcqhH • Dec 19, 2006

OK ! I know the answer to this from my engineering days ...
Many others may also know it. Anyway let me wait for people to try.

Clue : There is nothing extra ordinary in this puzzle. Just required some common sense.

😎

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crook

@crook-0PFkJv • Dec 20, 2006

instruite
Here is a new one for all CEians

Question: In the basement there are 3 light switches in the off position. Each switch controls 1 of 3 light bulbs on the floor above. You may move any of the switches, but you may only go up stairs one time. How can you determine which switch controls each light?

I guess it should be easy 😁

I am posting the answer!

Turn on any switch and keep it 'ON' for some time. Switch it off. Now turn on another switch and rush to the floor above.

1. The bulb which is glowing corresponds to the switch which is presently 'ON'.
2. Touch the other two bulbs: The one which is warm(/hot) corresponds to the switch which was turned on initially.
3. The remaining bulb corresponds to the third (remaining) switch.

😁

Crook

0

instruite

@instruite-3JCI35 • Jan 28, 2007

crook
I am posting the answer!

Turn on any switch and keep it 'ON' for some time. Switch it off. Now turn on another switch and rush to the floor above.

1. The bulb which is glowing corresponds to the switch which is presently 'ON'.
2. Touch the other two bulbs: The one which is warm(/hot) corresponds to the switch which was turned on initially.
3. The remaining bulb corresponds to the third (remaining) switch.

😁

Crook

that was a correct answer
any body posting a new puzzle?

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raj87verma88

@raj87verma88-ZpL2Wn • Apr 18, 2008

The four people in this puzzle all competed in different classes of dog agility at a recent competition. The competitions all required the dogs to run over jumps, through tunnels and various other obstacles in as quicker time as possible. Each had a different result - one came first, one third, one fourth and one ninth. All four dogs were each of a different breed.

Can you work out who handled which dog, at what level each competed, the place each finished in and the breed of each dog?

1. If Tiff finished first then Terry finished fourth.
2. If Terry finished fourth then Jago is a collie otherwise Jago is not a collie.
3. If Jane competed in the Senior class then she finished third.
4. If Jane competed in Novice then she finished fourth.
5. The dog that finished ninth was an alsatian. This was either Jago, in which case Jago competed in the Elementary class, or this was Kelly, in which case Terry handled Kelly.
6. Mark won Starters.
7. If Mark's dog is called Patti then Patti is a labrador otherwise Patti is a collie.
8. Ruth's dog is called Jago.
9. If Jago finished fourth then she competed in the Novice class otherwise she competed in the Senior class.
10. If Patti finished first then Terry's dog is an alsatian otherwise Terry's dog is a collie.
11. If Jane's dog is a doberman then Jane finished fourth otherwise Jane finished third.

Handler's Names: Jane, Mark, Ruth and Terry
Dog's Names: Tiff, Patti, Jago and Kelly
Breed: Alsatian, Collie, Labrador and Doberman
Level: Starters, Elementary, Novice or Senior

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raj87verma88

@raj87verma88-ZpL2Wn • Apr 18, 2008

Imagine a prisoner in a prison. He is sentenced to death and has been told that he will be killed on one day of the following week. He has been assured that the day will be a surprise to him, so he will not be anticipating the hangman on a particular day, thus keeping his stress levels in check.

The prisoner starts to think to himself, if I am still alive on Thursday, then clearly I shall be hanged on Friday, this would mean that I then know the day of my death, therefore I cannot be hanged on Friday. Now then, if I am still alive on Wednesday, then clearly I shall be hanged on Thursday, since I have already ruled out Friday. The prisoner works back with this logic, finally concluding that he cannot after all be hanged, without already knowing which day it was.
Casually, resting on his laurels, sitting in his prison cell on Tuesday, the warden arrives to take him to be hanged, the prisoner was obviously surprised!

Ponder this?

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mayachallenge

@mayachallenge-vy1wHC • May 23, 2008

8+(7+(6*5))(sqrt(4)(cube of 3)
i.e 54*37+8=1998+8=2006
here* imean multiply

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Manish_Tiwari

@manish-tiwari-XQWPh1 • Jul 27, 2008

495, isnt this the anwer people
simple mathematics

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banu

@banu-d7GxOI • Aug 11, 2008

8,7,6,5,4,3
solution is
8*7 +3=56+3=59
6*5+4=30+4=34
now 59*34=2006
that's it
banu

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icefreak

@icefreak-caznXT • Feb 28, 2009

Man just let me no the answer

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arsh86

@arsh86-pwVJG2 • Mar 21, 2009

this is nice.
add more puzzles.......

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rishna

@rishna-9pM65A • Apr 1, 2009

Use +, -, *, / to make the following equation. There are at least 6 solutions.

9,9,9,9,9,9 = 100

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veerapps

@veerapps-Qie2ZF • May 6, 2009

Hi
(8+7+6-5+4) ( 3+2+1)
=(20) (06)
=2006 😁

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ms_cs

@ms-cs-Ab8svl • May 6, 2009

the y-not
use +, -, *, / to make the following equation. There are at least 6 solutions.

9,9,9,9,9,9 = 100

99/99+99=100

0

sanandsanu

@sanandsanu-lhT9JZ • May 20, 2009

heyy what about that prisoner's question

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 20, 2009

raj87verma88
The prisoner starts to think to himself, if I am still alive on Thursday, then clearly I shall be hanged on Friday, this would mean that I then know the day of my death, therefore I cannot be hanged on Friday. Now then, if I am still alive on Wednesday, then clearly I shall be hanged on Thursday, since I have already ruled out Friday. The prisoner works back with this logic, finally concluding that he cannot after all be hanged, without already knowing which day it was.
Casually, resting on his laurels, sitting in his prison cell on Tuesday, the warden arrives to take him to be hanged, the prisoner was obviously surprised!

Ponder this?

If we come back thinking this we think that this is true but its not true.
this is a paradox.
on sunday he have a chance to die in next 6 days , on monday next 5 days and tuesday next 4 days so there is a possibility to hang him..
i guess this might be the answer ,
Raj need to explain it 😀

0

tech_vaibhav_ee

@tech-vaibhav-ee-65Xzvs • Jul 13, 2009

English-Scared
If we come back thinking this we think that this is true but its not true.
this is a paradox.
on sunday he have a chance to die in next 6 days , on monday next 5 days and tuesday next 4 days so there is a possibility to hang him..
i guess this might be the answer ,
Raj need to explain it 😀

raj...plz explain the reason behind this..

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justaglance

@justaglance-3T6eU6 • Aug 14, 2009

Hi,

(9*9)+9+(9/9)+9 = 100

Hope this will be one among the answers.

The Y-Not
Use +, -, *, / to make the following equation. There are at least 6 solutions.

9,9,9,9,9,9 = 100

Thanks.

0

Aashish Joshi

@aashish-VrevFC • Sep 15, 2009

9/9 + 9 + 9*9 + 9=100

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ankur verma

@ankur-verma-7tarI4 • Sep 25, 2009

i would like to add one more problem here.

a person has eight identical looking balls,but one of them is heavier than others, he has a two -arm balancing machine and he can weigh only twice,

how can he determine the heavier one ?

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Manish Goyal

@manish-r2Hoep • Sep 26, 2009

yaar give me at least two chaNCES
so that i can solve it😁

0

ankur verma

@ankur-verma-7tarI4 • Sep 26, 2009

yes, you got two chances to measure

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odivya

@odivya-s3uO6s • Sep 30, 2009

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

The answer for this puzzle is

8*7+6^5/4+3!=2006

0

yocko

@yocko-KcNfal • Oct 4, 2009

ankur verma
a person has eight identical looking balls,but one of them is heavier than others, he has a two -arm balancing machine and he can weigh only twice,

how can he determine the heavier one ?

Split the balls into two groups of three and one group of two.

Compare the two groups of three.

If one side is heavier, then take two balls from that group and compare them--if neither is heavier, then it's the third ball.

If the groups of three in the first weighing came up equal, then you know that the heavier ball is in the group of two, so you compare the weights of those two.

woot.

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aaryan

@aaryan-zwuCzt • Jan 28, 2010

yup its good pizzle..............😁😁

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karan_shah89

@karan-shah89-RrTbMc • Feb 9, 2010

The result can be generalized for any number of items to be weighed.....for and number that is between any fixed powers of 3!!!!

Here is a more interesting ques.....

there are 10 identical machines manufacturing medicines,one of them is defective and produces a tablet that is different in weight(not lighter necessary)....using a digital weight once,how will u tell the defective machine from the others?????😕

0

csiscool

@csiscool-qA5mGA • Feb 18, 2010

is this thread is active ? guys post some puzzles..infoyss puzzles

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rushi4444

@rushi4444-Ksd0D5 • Apr 28, 2010

karan_shah89
The result can be generalized for any number of items to be weighed.....for and number that is between any fixed powers of 3!!!!

Here is a more interesting ques.....

there are 10 identical machines manufacturing medicines,one of them is defective and produces a tablet that is different in weight(not lighter necessary)....using a digital weight once,how will u tell the defective machine from the others?????😕

you can have standard weight of tablet suppose say 10gm....now take one tablet from 1st machine..two tablet form 2nd machine ...3 tablet from 3rd machine and so on..so u must have 55 tablet and u must have total weight equal to 55*(standard weight of tablet)=550..... but actually u dont have because one machine is defective...so measure the weight of 55 tablet together...u can easily find out the defective machine from the difference |actual weight-550|......

correct me if i m wrong.....

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vineetdiit

@vineetdiit-BmzMSG • Aug 17, 2010

Re: and here comes the tough one ( is it ? )

the answer is in the figure only....
they both have the same area.....look at the hypotnuse...both the hypotnuse are different......which is hard to visualize....and there is no extra space....

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vineetdiit

@vineetdiit-BmzMSG • Aug 17, 2010

u r right...

0

rushi4444

@rushi4444-Ksd0D5 • Aug 23, 2010

Re: and here comes the tough one ( is it ? )

The_Big_K
Okay !

Now this one will surely give you a good time 😀 !

How is this possible? -

(Edit: Removed the thumbnail and added the link -)

#-Link-Snipped-#

Thinks about it and post logical answer !

No kidding !

-The Big K-

actually the figure is wrong because...imagine this figure in a geometrical plane.......bottom left corner (0,0)...and top right corner (13,5)...then line joining these points does not pass through any of the points with both integer coordinates...where as in figure it is shown that....line passes through (8,3) and (5,2)....which is totaly wrong.....

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shreyasm89

@shreyasm89-jGobVm • Jan 20, 2011

We all knew that the absolute value would be the same. But I'm not sure how that solve's the biggie's ques

integratdbrains
The_Big_K
Oh really? 😉

Try this - ( should be easy )

-6 = -6
9-15 = 4-10

adding 25/4 to both sides:
9-15+(25/4) = 4-10+(25/4 )

Changing the order
9+(25/4)-15 = 4+(25/4)-10

(this is just like : a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

Taking mod on both sides. while subtracting the denominators of the numbers should be same! one cannot cancel the numbers!
/(3*2-5)/2/= /(2*2-5)/2/
/1/=/1/

The common CE sentence!"correct me if m wrong!"😒😁

0

shreyasm89

@shreyasm89-jGobVm • Jan 20, 2011

What's the answer?

karan_shah89
The result can be generalized for any number of items to be weighed.....for and number that is between any fixed powers of 3!!!!

Here is a more interesting ques.....

there are 10 identical machines manufacturing medicines,one of them is defective and produces a tablet that is different in weight(not lighter necessary)....using a digital weight once,how will u tell the defective machine from the others?????😕

0

silverscorpion

@silverscorpion-iJKtdQ • Jan 20, 2011

shreyasm89
What's the answer?

well, this is easy.

You take 1 tablet from machine 1, 2 from machine 2 and so on and 10 from machine 10.
Weigh the total tablets in the digital weight.
The total weight should ideally be a multiple of 55. (55 times the weight of one tablet)
See how much is the difference between the total weight and the nearest multiple of 55.

That is the defective machine, and if the total weight is greater than the multiple of 55, then the defective machine produces heavier tablets, and vice versa. 😀

Let's say machine 5 is defective and it produces lighter tablets. Then, the total weight will be 5 less than 55 times the weight of 1 tablet. 😀😀

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@praveenkumar-66Ze92 • Mar 2, 2011

Answer these...
1. There are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.
2. A train ran at a certain speed for one hour and then due to a technical problem, it ran at 3/5th of its original speed and reached the destination 2 hrs late. The driver said, had the problem occurred 50 miles later, we would have gained 40 minutes. What is the distance between the two cities that the train traveled?

0

@harshajd-F0ZGFM • Mar 10, 2011

There are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.

Ans: 1

0

@praveenkumar-66Ze92 • Mar 10, 2011

harshajd
There are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.

Ans: 1

What??? How??? Explain... 😲

0

@harshajd-F0ZGFM • Mar 10, 2011

praveenscience
What??? How??? Explain... 😲

make two groups of 3820 balls.. if both are equal in weight then the left(6561th) ball is the one with higher weight...

*this is the possible minimum....

0

@praveenkumar-66Ze92 • Mar 10, 2011

What if they are not equal... I am asking the minimum, where you get to know the heaviest ball...

0

@harshajd-F0ZGFM • Mar 10, 2011

then it's 7

0

@praveenkumar-66Ze92 • Mar 10, 2011

harshajd
then it's 7

You came close... Say how you got... 😀

0

@harshajd-F0ZGFM • Mar 10, 2011

praveenscience
You came close... Say how you got... 😀

break in to 3 groups.. and weigh two, if both are equal then third group is the one with heavier ball and if not equal, then choose the heavier one

6561/3=2187

2187/3= 729

729/3=243

243/3=81

81/3=27

27/3=9

9/3=3

3/3=1

had missed the bolder one while counting ...

ans is 8

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@praveenkumar-66Ze92 • Mar 10, 2011

harshajd
break in to 3 groups.. and weigh two, if both are equal then third group is the one with heavier ball and if not equal, then choose the heavier one

6561/3=2187

2187/3= 729

729/3=243

243/3=81

81/3=27

27/3=9

9/3=3

3/3=1

had missed the bolder one while counting ...

ans is 8

Perfect!!! Now answer the second question... 😀

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@harshajd-F0ZGFM • Mar 10, 2011

i am not good with trains and water slides

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@praveenkumar-66Ze92 • Mar 10, 2011

harshajd
i am not good with trains and water slides

Thats not a good answer... But you were great with solving this one... 😀

0

@harshajd-F0ZGFM • Mar 10, 2011

total distance = 225 miles

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deepac

@deepac-P1tinP • Mar 14, 2011

here is the answer:
[8 - (7*6)] * [5 - (4^3)] =2006
step1: 7*6 = 42
step2: 8-42=-34
step3: 4^3 = 4*4*4= 64
step4: 5-64=-59
step5: -34 * -59
step6: 2006

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deepac

@deepac-P1tinP • Mar 14, 2011

here is the answer:
[8 - (7*6)] * [5 - (4^3)] =2006
step1: 7*6 = 42
step2: 8-42=-34
step3: 4^3 = 4*4*4= 64
step4: 5-64=-59
step5: -34 * -59
step6: 2006 😀

0

Kate_w

@kate-w-7LjGWt • Jul 4, 2011

Well I am posting first time on this forum , must say it's a great place to share stuffs. Well Big K all are asking literally begging you to tell the answer to the question puzzle you've posed on us, so speak out dude!!!! I'm also eager to know the answer. I thought the correct numerical to be 1 and 2 as all other numbers are going in declining order but cannot relate them with 2006 expression!! Please explain.
Anyway here's a brainteaser link which has got some of the great mind teasers -
<a href="https://www.iqtestexperts.com/brainteasers/" target="_blank" rel="nofollow noopener noreferrer">Brain Teasers | IQ Test Experts |</a>

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@praveenkumar-66Ze92 • Jul 21, 2011

No Deepac... The answer is here:

Here the constant is the distance.
Let consider the time is 'T', velocity is 'V' and distance is 'D' for normal journey.
Equating distances in each case.
Let time in minutes, length in miles initially.

Case1: 120 minutes late
VT = V * 60min + (3/5)*V* ( T + 120min - 60min)
=> VT = 60V + (3/5)VT + (3/5)60V
=> T = 240min = 4hours. Therefore normal journey is 4Hrs.----(1)

Case2: 40 minutes gained from 120 min late.
VT = 50miles + (3/5)*V*(T + 120min - 40min - (50mile/V))
=>using eq.1

=>240V = 50 + (3/5)320V - (3/5)*50
=>V = (5/12)miles/minute. Convert this to miles/hour.
=>v = (5/12)*60 = 25 Miles/Hour.

=>Required Distance is D= VT = 25*4= 100Miles.

0

shivamvaishy

@shivamvaishy-O7To8H • Aug 12, 2011

Hey The Big K may i get the question of this answer...please??
Here the constant is the distance.
Let consider the time is 'T', velocity is 'V' and distance is 'D' for normal journey.
Equating distances in each case.
Let time in minutes, length in miles initially.

Case1: 120 minutes late
VT = V * 60min + (3/5)*V* ( T + 120min - 60min)
=> VT = 60V + (3/5)VT + (3/5)60V
=> T = 240min = 4hours. Therefore normal journey is 4Hrs.----(1)

Case2: 40 minutes gained from 120 min late.
VT = 50miles + (3/5)*V*(T + 120min - 40min - (50mile/V))
=>using eq.1

=>240V = 50 + (3/5)320V - (3/5)*50
=>V = (5/12)miles/minute. Convert this to miles/hour.
=>v = (5/12)*60 = 25 Miles/Hour.

=>Required Distance is D= VT = 25*4= 100Miles.

0

nick916

@nick916-tWfrXE • Sep 13, 2011

i have 2 puzzles:

1) how many cars r thr in US/INDIA?
2) y r manholes alws round?

these 2 r askd often give a logical answer.....plz
thks

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@ce-designer-BWq0yl • Dec 30, 2011

Here's one:
What's something you never want to get, but if you do get it you never want to lose it?

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@praveenkumar-66Ze92 • Dec 30, 2011

nick916
2) y r manholes alws round?

Round covers won't fall in at any case, where as square covers can fall in when placed diagonally! 😀

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Reya

@reya-SMihdC • Dec 30, 2011

@Ce Designer: Lawsuit?

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@ce-designer-BWq0yl • Dec 31, 2011

Hehe, you got it Reya 👍
Here is another:
A horse is galloping at high speed on a road. Along the same road comes a bull galloping in the opposite direction.
They both crash into each other.
Who is to blame? The horse, or the bull?
P.S. the answer is a funny one.

0

Ankita Katdare

@abrakadabra • Jan 1, 2012

CE Designer
Hehe, you got it Reya 👍
Here is another:
A horse is galloping at high speed on a road. Along the same road comes a bull galloping in the opposite direction.
They both crash into each other.
Who is to blame? The horse, or the bull?
P.S. the answer is a funny one.

No takers here? 😯

0

ISHAN TOPRE

@ishan-nohePN • Jan 1, 2012

The bull is to blame.
Because he has no brakes while the horse has brakes (bit).

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@praveenkumar-66Ze92 • Jan 1, 2012

Issue
The bull is to blame.
Because he has no brakes while the horse has brakes (bit).

Woah... Nice one... I thought that but, didn't strike!!! 😛

Now solve this one... Very easy one... A classic one too! 😀

You are in a candle lit room with a single wooden door, no windows and three light switches labeled A, B and C. You cannot by any means see anything outside the room. The three switches are connected to three lights in another room. They are all currently in the off position. You are given ten minutes in the room with the switches then you will be taken to the room with the lights. At that time you need to label each light with the letter of the corresponding switch. How do you do it?

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@kr-at-nsngu-XqzcfU • Jan 1, 2012

Bro .... I know this... but, I am giving chance to others.....
Let them try .... I will answer if no one knows.

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ISHAN TOPRE

@ishan-nohePN • Jan 1, 2012

Praveen-Kumar
You are in a candle lit room with a single wooden door, no windows and three light switches labeled A, B and C. You cannot by any means see anything outside the room. The three switches are connected to three lights in another room. They are all currently in the off position. You are given ten minutes in the room with the switches then you will be taken to the room with the lights. At that time you need to label each light with the letter of the corresponding switch. How do you do it?

When you are in the room, turn ON any of the switch. Leave it as it is for next 10 minutes. At the end of 10 minutes turn ON any of the switches. Now go to the next room.

There are 2 glowing bulbs. One is hot-this is the first one that you switched on. Label it as A. The other colder glowing bulb can be named as B. The remaining bulb that is not glowing is labeled as C. 😀

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@praveenkumar-66Ze92 • Jan 1, 2012

Issue
When you are in the room, turn ON any of the switch. Leave it as it is for next 10 minutes. At the end of 10 minutes turn ON any of the switches. Now go to the next room.

There are 2 glowing bulbs. One is hot-this is the first one that you switched on. Label it as A. The other colder glowing bulb can be named as B. The remaining bulb that is not glowing is labeled as C. 😀

Perfect, but you forgot to turn the first switchoff!!! 😛

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@ce-designer-BWq0yl • Jan 3, 2012

Issue
The bull is to blame.
Because he has no brakes while the horse has brakes (bit).

Haha, you are right the bull is to blame but the answer i was looking for was:
The bull is to blame because he has horns, he should have blown his horns 😁😉

0

@dancer-engineer-EJ8rGI • Jan 6, 2012

The following equation is wrong:

101 - 102 = 1

Move one numeral to make it correct

(Caution: Trick) 😁

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@praveenkumar-66Ze92 • Jan 6, 2012

Dancer_Engineer
The following equation is wrong:

101 - 102 = 1

Move one numeral to make it correct

(Caution: Trick) 😁

101 - 10[sup]2[/sup] = 1
Right aa?

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@dancer-engineer-EJ8rGI • Jan 6, 2012

Praveen-Kumar
101 - 10[sup]2[/sup] = 1
Right aa?

Oh Yesh...Right! 😁

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@kr-at-nsngu-XqzcfU • Jan 7, 2012

Using five zero's(0's) with any mathematical equation/operation can anyone bring 120 as an answer ???

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

K!r@nS!ngu
Using five zero's(0's) with any mathematical equation/operation can anyone bring 120 as an answer ???

You mean:

Any Mathematical operation (0 0 0 0 0) = 120 ?

0

@kr-at-nsngu-XqzcfU • Jan 7, 2012

Dancer_Engineer
You mean:

Any Mathematical operation (0 0 0 0 0) = 120 ?

Yes....

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@dancer-engineer-EJ8rGI • Jan 7, 2012

K!r@nS!ngu
Yes....

I got answer as 2.

(0^0) + (0^0) + 0 = 1+1+0 = 2

How did you get 120? 😕

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@kr-at-nsngu-XqzcfU • Jan 7, 2012

Let others give a trail....

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Reya

@reya-SMihdC • Jan 7, 2012

(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=120.

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@kr-at-nsngu-XqzcfU • Jan 7, 2012

Reya
(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=120.

you are damn right !!! keep going reya...

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@dancer-engineer-EJ8rGI • Jan 7, 2012

Ohh Damn! 😔

Reya
(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=120.

Cool! 😎

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ISHAN TOPRE

@ishan-nohePN • Jan 7, 2012

Reya
(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=120.

(She is Reya after all) FACTORIAL 😁

0

@praveenkumar-66Ze92 • Jan 7, 2012

Ah!!! Where is the next question now... 😛

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

Praveen-Kumar
Ah!!! Where is the next question now... 😛

Here you go:

Two friends have a nice meal together, and the bill is $25

The friends pay $15 each, which the Waiter gives to the Cashier

The Cashier hands back $5 to the Waiter

The Waiter keeps $3 as a tip and hands back $1 each

So, the friends paid $14 each for the meal, for a total of $28. The Waiter has $3, and that makes $31. Where did the other dollar come from?

0

@praveenkumar-66Ze92 • Jan 7, 2012

Dancer_Engineer
Here you go:

Two friends have a nice meal together, and the bill is $25

The friends pay $15 each, which the Waiter gives to the Cashier

The Cashier hands back $5 to the Waiter

The Waiter keeps $3 as a tip and hands back $1 each

So, the friends paid $14 each for the meal, for a total of $28. The Waiter has $3, and that makes $31. Where did the other dollar come from?

Oyee! Actually, the question with the answer is tricky!!!
Let the friends be A, and B.
Cashier be C.
Waiter be W.
A+B (15+15) » C
C (5) » W
W (1+1) » A+B
Total Pay: 14 (A) + 14 (B) - 3 (W) = 25 (C)
Is the answer right???

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

Praveen-Kumar
Oyee! Actually, the question with the answer is tricky!!!
Let the friends be A, and B.
Cashier be C.
Waiter be W.
A+B (15+15) » C
C (5) » W
W (1+1) » A+B
Total Pay: 14 (A) + 14 (B) - 3 (W) = 25 (C)
Is the answer right???

I didn't understand your solution dude 😕

C (5) >> W ?

0

@praveenkumar-66Ze92 • Jan 7, 2012

Cashier gives five to waiter...

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

Praveen-Kumar
Oyee! Actually, the question with the answer is tricky!!!
Let the friends be A, and B.
Cashier be C.
Waiter be W.
A+B (15+15) » C
C (5) » W
W (1+1) » A+B
Total Pay: 14 (A) + 14 (B) - 3 (W) = 25 (C)
Is the answer right???

You say,
Total Pay: 14 (A) + 14 (B) - 3 (W) = 25 (C)

But both A and B pay 15 each.

0

@praveenkumar-66Ze92 • Jan 7, 2012

Dancer_Engineer
You say,
Total Pay: 14 (A) + 14 (B) - 3 (W) = 25 (C)

But both A and B pay 15 each.

They get back 1 rupee each from the Waiter na? So, mathematically, check! 😀

0

@praveenkumar-66Ze92 • Jan 7, 2012

They pay 15 each... And in turn, cashier gives back 5, out of which 3 is taken by the waiter. So, the waiter pays back 1 each... This way, they effectively pay 14 each! 😀

0

@praveenkumar-66Ze92 • Jan 7, 2012

A = 15
B = 15
C = -5
W =  3
------
T = 28
W = -3
------
F = 25
------

Where, A & B are friends, C is the Cashier, W is the Waiter and F is the Food! 😀

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

Praveen-Kumar
They pay 15 each... And in turn, cashier gives back 5, out of which 3 is taken by the waiter. So, the waiter pays back 1 each... This way, they effectively pay 14 each! 😀

Ok.

So Both A and B pay $14 and the waiter keeps $3,
that makes: $14 + $14 + $3 = $31.

But initially there was just $30,
$15 each from A and B.

Where did this 1 Dollar come from?

0

@praveenkumar-66Ze92 • Jan 7, 2012

Dancer_Engineer
Ok.

So Both A and B pay $14 and the waiter keeps $3,
that makes: $14 + $14 + $3 = $31.

But initially there was just $30,
$15 each from A and B.

Where did this 1 Dollar come from?

Eiii!!! I said, Waiter's bill is to be negated!!! You didn't add the $5 which you got from the Cashier!!!
Okay, then coming to your way itself...
First these two pay 15$ each...
Cashier returns back 5$, which you didn't mention...
So, technically, it is not 14 + 14 + 3, but it is 14 + 14 - 5 + 3!!!

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

Praveen-Kumar
Eiii!!! I said, Waiter's bill is to be negated!!! You didn't add the $5 which you got from the Cashier!!!
Okay, then coming to your way itself...
First these two pay 15$ each...
Cashier returns back 5$, which you didn't mention...
So, technically, it is not 14 + 14 + 3, but it is 14 + 14 - 5 + 3!!!

Dude, 14 + 14 - 5 + 3 = 26.
But the bill is $25. 😛

I think you are pretty close to the solution. 😁

0

Reya

@reya-SMihdC • Jan 7, 2012

The bill is $25. If i divide that,each should contribute $12.5

The waitor returned $2 back($1 for each)

The tips of the waitor is $3.

Each gave $15 to the waitor.So the total amount is $30.

$25+$3+$2=30.

"So, the friends paid $14 each for the meal, for a total of $28" is the misleading statement.

0

@praveenkumar-66Ze92 • Jan 7, 2012

Reya
The bill is $25. If i divide that,each should contribute $12.5

The waitor returned $2 back($1 for each)

The tips of the waitor is $3.

Each gave $15 to the waitor.So the total amount is $30.

$25+$3+$2=30.

"So, the friends paid $14 each for the meal, for a total of $28" is the misleading statement.

This is what even I said!!! 😲

0

@dancer-engineer-EJ8rGI • Jan 7, 2012

Reya
"So, the friends paid $14 each for the meal, for a total of $28" is the misleading statement.

Nope, I think the statement meant total of 14 and 14 is 28.
I'm getting confused 😕

I'll post the solution here

The Solution . . .

$25 is sitting with the Cashier, $2 with the friends, and $3 with the Waiter. That adds to the required $30.

The mistake is expecting that what the men paid and what the Waiter kept to add up to what the men initially gave. In fact, it is the amount that the meal effectively cost them, plus the amount they received back, that should add to $30.

Both of you are right.
Praveen, I didn't have the solution with me earlier. 😀

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@praveenkumar-66Ze92 • Jan 8, 2012

Dancer_Engineer
Both of you are right.
Praveen, I didn't have the solution with me earlier. 😀

Yay!!! 😀 Mine is right!!! 😁

0

@dancer-engineer-EJ8rGI • Jan 8, 2012

Praveen-Kumar
Yay!!! 😀 Mine is right!!! 😁

Yes you are. 😛 😁

0

Sughosh Deshmukh

@sughosh-deshmukh-PzB3WX • Feb 2, 2012

The_Big_K
Try this one now -

Oh really? 😉

Try this - ( should be easy )

-6 = -6
9-15 = 4-10

adding 25/4 to both sides:
9-15+(25/4) = 4-10+(25/4 )

Changing the order
9+(25/4)-15 = 4+(25/4)-10

(this is just like : a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

3 = 2 😒 😁

What's wrong with the above ?

-The Big K-

the positive square root is the culprit
we have to consider
(3-5/2)(3-5/2)=-(2-5/2)(2-5/2)

0

sowjanya allam

@sowjanya-allam-QGXV8W • Feb 10, 2012

The_Big_K
Let's dedicate this place to Puzzle Busters! The CE Genius Team 8)

Note# Google / Yahoo / MSN is banned for the team here. Use only brainz , no internet! 😁

Here comes the first challenge -

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

-The Big K-

what is the ans

0

sowjanya allam

@sowjanya-allam-QGXV8W • Feb 10, 2012

what is the ans

0

shreeharsha

@shreeharsha-xzQWqw • Feb 28, 2012

The_Big_K
Let's dedicate this place to Puzzle Busters! The CE Genius Team 8)

Note# Google / Yahoo / MSN is banned for the team here. Use only brainz , no internet! 😁

Here comes the first challenge -

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

-The Big K-

The_Big_K
Let's dedicate this place to Puzzle Busters! The CE Genius Team 8)

Note# Google / Yahoo / MSN is banned for the team here. Use only brainz , no internet! 😁

Here comes the first challenge -

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

yeah yeah yeah big k i got da answer...hehe.... (8*7-(6c5))*4)3! ==((56-6)*4)6==(50*4)6==2006

-The Big K-

0

shreeharsha

@shreeharsha-xzQWqw • Feb 28, 2012

what i have done is ri8 na???

0

sahilmohindroo

@sahilmohindroo-frErzt • Jun 4, 2012

and here comes the tough one ( is it ? )

Okay !

Now this one will surely give you a good time 😀 !

How is this possible? -

(Edit: Removed the thumbnail and added the link -)

#-Link-Snipped-#

Thinks about it and post logical answer !

No kidding !

-The Big K-

#-Link-Snipped-#, #-Link-Snipped-#

There is a small difference b/w the slopes of hypotenuse of the red(3/8) and green(2/5) triangle, so that the hypotenuse (of the bigger traingle(which is actually a quadrilateral)) is concave in first figure and convex in second resulting for the difference.

0

@ce-designer-BWq0yl • Jun 5, 2012

#-Link-Snipped-# whats the answer to this. This is messing with my mind 😕

0

Lalit77

@lalit77-ITuWjY • Jul 4, 2012

rick
New Puzzle!

err! wait ! 😁

I did try Google, Yahoo, MSN & my brain 😁

I'm posting a new question. The one who solves this first gets ...

a smile from me 😁

here we go -

A number of children are standing in a circle. They are evenly spaced and the 5th child is directly opposite the 17th child. How many children are there altogether?

RICK

yup its 24...

0

Lalit77

@lalit77-ITuWjY • Jul 4, 2012

😁

0

@vinod1993-r3yTlk • Jul 24, 2012

pls wait....dnt post the answer.....

0

@vinod1993-r3yTlk • Jul 24, 2012

i was able to get upto 2012...!! 😛 but not 2006..! 😛 trying and trying..!

0

@vinod1993-r3yTlk • Jul 24, 2012

got 2007 too but not 2006...! 😛 "K"..!

0