Old is Gold : Numberology!!!

We will run two puzzle simultaneously,
1->>> Four fours problem : In this problem we have to make numbers starting from 1 by using only four 4, with any mathematical operation.
2->>> Four eights problem : This is same as above but instead of 4 we have to use 8.
We all have to follow some rules (including me cause I am with you in solving post):
1>> No thanks, no discussion, just post the answer.
2>> No double posting, let others solve the puzzle.
3>> We have to follow the sequence. That means that if I post the answer for 1, then the next one post the answer for 2 an the next 3, and so on.
4>> Post the answer for both 4 & 8. Single answer is not allowed.

Let us start and see how far we can go!!!!

Replies

  • RajdeepCE
    RajdeepCE
    Here is the first one & remember the format.

    1-> 4/4+4-4 = 1
    2-> 8/8+8-8 = 1

    now, go for 2...
  • shalini_goel14
    shalini_goel14
    Now for 2

    4/4 + 4/4 =2
    8/8 + 8/8 =2

    Go for 3..
  • smita89
    smita89
    (4+4+4)/4 =3
    (8+8+8)/8 =3

    Next is four!!
  • RajdeepCE
    RajdeepCE
    (4-4)/4+4 = 4
    8*8/(8+8) = 4
    Next is 5...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4!/4 -(4/4) =5
    8!!!!/8 + 8/8 =5

    8!!!! = 8*4 =32


    next 6
  • RajdeepCE
    RajdeepCE
    English-Scared
    8!!!! = 8*4 =32
    I dont know about it. Anyway I have alternate solution it:
    3√8+3√8+8/8=5.
    For 6:
    √4+4+4-4=6
    8-(8+8)/8=6
    next is 7...
  • shalini_goel14
    shalini_goel14
    4 + 4 - (4/4)= 7
    8 - 8 [sup](8-8)[/sup] = 7

    Doubt about 8 -Rajdeep . Please check if allowed or not

    Next 8...
  • silverscorpion
    silverscorpion
    4 + 4 + 4 - 4 = 8

    8 + (8 - 8) / 8 = 8

    Next is 9..
  • shalini_goel14
    shalini_goel14
    4 + 4 + (4/4)= 9
    8 + 8 [sup](8-8)[/sup] = 9

    Again Rajdeep . Please check for 8 if allowed or not 😁

    Next 10...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4+4+4 - sqrt 4 = 10

    8 + (8+8)/8 = 10

    next 11
  • RajdeepCE
    RajdeepCE
    @Shalini, I am not getting you cause you are using 8(8-8), its simply a 0. So I am sorry to say that your calculation for both 7 & 9 is wrong. Here is a correct calculation:
    8*Cos8-8/8=7
    8*Cos8+8/8=9
    here 8*Cos8=7.92β‰ˆ8.
    I am unable to found any other solution. If someone has more perfect solution than you are welcome!!!
    For 11,
    4+4+4-Cos4=11 (Cos4=0.997)
    8+3√8+8/8=11
    next is 12...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    Rajdeep Shalini is using 8 to the power of (8-8) that is zero so 8 power zero is 1 .

    so the answers are correct .
  • RajdeepCE
    RajdeepCE
    Either I am unable to view the sign '^' or she forgot to put the sign. Whatever it is. If 8^(8-8) is used than both answers is right. I apologize for the above post. And concerning about my alternate solution, I want to say that I went for longway and you went simple.
    @ES, thanks for pointing out my error. Anyway now go for 12...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! -(4+4+4) = 12

    8+8 -3√8-3√8 = 12


    now 13 πŸ˜€
  • RajdeepCE
    RajdeepCE
    4+4+4+Cos4=13
    8+8/√8+Cos8=13
    Here Cos4=0.997β‰ˆ1 & Cos8=0.99β‰ˆ1.
    Now go for 14...
  • shalini_goel14
    shalini_goel14
    @Rajdeep I need not to use '^' sign as CE provides a good facility of using a [sup ]b[/ sup] facility for displaying text in form a[sup]b[/sup]. πŸ˜€ You can refer this thread also #-Link-Snipped-#

    4+4+4 + sqrt(4) =14

    8+8 - sqrt(sqrt(8+8)) =14

    Go for 15...
  • RajdeepCE
    RajdeepCE
    May be this is due to my browser cause I am browsing CE from my mobile.
    For 15,
    4*4-4/4=15
    8+8-8/8=15
    Next is 16...
  • shalini_goel14
    shalini_goel14
    4 * 4 + (4-4) =16

    8 + 8 + (8-8)=16

    Go for 17...
  • pradeep_agrawal
    pradeep_agrawal
    4 * 4 + (4/4) = 17
    8 + 8 + (8/8) = 17

    Go for 18.

    -Pradeep
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4 * 4 + (4/4) = 17

    8+8 + (8/8) = 17

    now 18 πŸ˜€
  • shalini_goel14
    shalini_goel14
    4 * 4 + sqrt(sqrt(4*4)) =18

    8 + 8 + sqrt(sqrt(8+8)))=18

    Go for 19..
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    shalini_goel14
    4 * 4 + sqrt(4) =18

    8 * 8 + sqrt(sqrt(8+8)))=18

    Go for 19..


    @Shalini : you have to use 4 ,4's
    4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18
  • shalini_goel14
    shalini_goel14
    English-Scared
    @Shalini : you have to use 4 ,4's
    4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18
    Thanks for pointing out, edited.
  • pradeep_agrawal
    pradeep_agrawal
    shalini_goel14
    8 * 8 + sqrt(sqrt(8+8)))=18
    I feel yyou mean to say

    8 + 8 + sqrt(sqrt(8+8)))=18

    -Pradeep
  • shalini_goel14
    shalini_goel14
    pradeep_agrawal
    I feel yyou mean to say

    8 + 8 + sqrt(sqrt(8+8)))=18

    -Pradeep
    Oops Sorry, what is happening to me. Editing

    Thanks for pointing out πŸ˜€
  • pradeep_agrawal
    pradeep_agrawal
    Do we allow operations like cube root and using sin, cos, etc. (for this we may need to take approximate values)?

    -Pradeep
  • pradeep_agrawal
    pradeep_agrawal
    4! - 4 - (4/4) = 19
    8 + 8 + cuberoot(8) + cos(8) = 19
    ((8 + cuberoot(8)) * cuberoot(8)) - cos(8) = 19

    4! - 4 + (4-4) = 20
    8 + 8 +√(8+8) = 20

    4! - 4 + (4/4) = 21
    ((8 + cuberoot(8)) * cuberoot(8)) + cos(8) = 21

    Go for 22.

    -Pradeep
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! - sqrt 4 + 4 - 4 = 22


    8+8+8 - Cuberoot (8) = 22

    now 23 .
  • RajdeepCE
    RajdeepCE
    @Pradeep. Yes we can. And one more thing that calculate only for one number only, cause we want to let others to solve. Anyway, for 23,
    4!-Cos4+(4-4)=23
    (8+8+8)-Cos8=23
    next is 24...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4 * 4 +4 + 4 = 24

    (8+8)*Cuberoot(8) -8 =24

    so next 25 πŸ˜€
  • RajdeepCE
    RajdeepCE
    4!+(4^(4-4))=25
    8+8+8+Cos8=25
    Next is 26...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! + sqrt(4) +4 -4 = 26

    8+8+8+ Cuberoot(8) = 26
    next 27
  • shalini_goel14
    shalini_goel14
    Hey Rajdeep, is use of numbers other than 4 and 8 allowed? I guess you have used '3' while giving answer for 11. I am still not clear what you want from us.

    Anyways if allowed here goes my solution for 27 😁

    4! + sqrt(4) + 4/4 =27

    8+8+8+ log[sub]2[/sub]8=27
    or
    8+8+8+(ln 8) =27 (assuming base root is 2)

    Go for 28..
  • RajdeepCE
    RajdeepCE
    @Shalini. I used qube root there.
    For 28,
    4!+4+4-4=28
    (8/quberoot(8))! + sqrt(8+8)=28
    Next is 29...
  • Anil Jain
    Anil Jain
    RajdeepCE
    (4-4)/4+4 = 4
    This is wrong...
    (4-4)/4+4 = 0

    -CB
  • Anil Jain
    Anil Jain
    4!+4+(4/4) = 24+4+1 = 29
    (log(base2)8)*(log(base2)8)*(log(base2)8)+cuberoot(8) = 3*3*3+2 = 29

    Next is 30...

    -CB
  • shalini_goel14
    shalini_goel14
    @CB I guess he meant

    ((4-4)/4 )+4=4

    Anyways for 29

    4! + 4 + (4/4) =29

    For 8
    Assuming base root is 2
    ( 8 * cube root of (8) ) + 8 - ln 8 = 29

    Go for 30..

    PS: Rajdeep for 8 , please tell any other option if you know. It couldn't strike to my mind.

    Thanks !
  • RajdeepCE
    RajdeepCE
    crazyboy
    This is wrong...
    (4-4)/4+4 = 0

    -CB
    lol, you just forgot the rule of priority, cause division & multiplication has higher priority than addition & subtraction. So the equation first becomes,
    0/4+4,
    and then it will bf,
    0+4=4.

    For 30,
    4! + 4 + (4/sqrt(4)) = 30
    (8/cuberoot(8))! + 8 - cuberoot(8)=30
    next is 31...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! + sqrt(4)+sqrt(4)+sqrt(4) = 30


    (8* (Cuberoot(8)+Cuberoot(8)))-Cuberoot(8) =30


    next 31.
  • RajdeepCE
    RajdeepCE
    @Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
    (8 / cuberoot(8))! + 8 - ln 8 = 29,
    assuming base 2, ln 8=3.
    For 31,
    4! + 4 + 4 - Cos 4 = 31,
    (8 / cuberoot(8))! + 8 - Cos 8 = 31
    next is 32...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    its easy πŸ˜€

    (4*4)+ (4*4) = 32

    8+8+8+8 =32


    now 33 πŸ˜€
  • RajdeepCE
    RajdeepCE
    Here is 33,
    (4*4)*sqrt(4)+Cos 4=33
    (8+8)*quberoot(8)+Cos 8 = 33
    next is 34...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4*4*Sqrt(4) + sqrt(4) = 34

    8*Cuberoot(8)*cuberoot(8) +cuberoot(8) = 34

    next 35 πŸ˜€
  • RajdeepCE
    RajdeepCE
    For 35,
    4! + Cot 4 - sqrt(4) - Cos 4 = 35,
    (8/quberoot(8))! + 8 + log 8 = 35,
    assuming base 2 for log 8.
    Cot 4 = 14.1
    next is 36,..
  • shalini_goel14
    shalini_goel14
    RajdeepCE
    @Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
    (8 / cuberoot(8))! + 8 - ln 8 = 29,
    Oh yes, you are 100% right. I messed up in hurry. Sorry

    Anyways for 36

    4! + 4 + 4 + 4 =36

    [( 8 * 8 ) + 8 ]/ (cube root of 8) =36

    Go for 37.. πŸ˜€

    PS: I guess use of trignometry and logs should not be allowed, it gives approximate results ?
  • Yamini L
    Yamini L
    For 37,

    ((4+4)*4)+4+(4/4))

    ((8/cube root(8))! + 8 + ((8/cube root(8)) +(8/8)

    next 38..
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    @Miniy: You havent read the rules.
    You are supposed to use exactly 4 4's and 4 8's no more and no less are allowed.
  • Yamini L
    Yamini L
    Completely missed itπŸ˜”.Thanks for alerting me ES.I will edit that post.
  • RajdeepCE
    RajdeepCE
    shalini_goel14
    PS: I guess use of trignometry and logs should not be allowed, it gives approximate results.
    You are absolutely right, but sometime it is impossible to find a number without using trignometric or logrethmic functions. Consider for 37, I messed myself about half an hour but I was unable to find the answer with simple arithmetic functions, than I tried with trignometric functions and answer comes within 10 minutes. If anyone have better solution than feel free to repost. So here is my answer for 37,
    Cot 4 + 4! - (4/4) = 37,
    Cot (Cos 8) - (8/cuberoot(8))! + log[sub]2[/sub]8 = 37,
    here,
    Cot 4 β‰ˆ 14, & Cot (Cos 8) β‰ˆ 58.
    Next is 38.
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! +(4*4) -sqrt(4) =38

    x = log8 to the base2 =3
    so 8*(x+cuberoot(8))-cuberoot(8) = 8*(2+3) -2 =38

    anyways next numebr is 39 πŸ˜€
  • RajdeepCE
    RajdeepCE
    4! + (4*4) - Cos 4 = 39,
    ((8*8)/cuberoot(8)) + Cot 8 = 39,
    Cot 8 β‰ˆ 7.
    Next is 40.
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4* (4+4+sqrt(4)) =40

    (8/cuberoot(8))!+8+8 =40

    Next 41

    A small suggestion guys , if Cot 4 = 14.12 you can use a function called Int cot 4 which gives 14.
    for values below 1 there is no excuse we need to go with the approximation as of now.
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! +(4*4) +cos(4) =41

    x = log8 to the base2 =3
    so 8*(x+cuberoot(8))+cos8 =41

    Cos4 and Cos8 are approximately 1


    So next 42
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! +(4*4) +sqrt(4) =42

    x = log8 to the base2 =3
    so 8*(x+cuberoot(8))+cuberoot8 =42

    next 43 ??
  • RajdeepCE
    RajdeepCE
    @ES, I think you haven't read the rule. No double posting allowed cause we want others to take part here. So be patient next time.
    For 43,
    4! + 4! - 4 - Cos 4 = 43,
    (8 - cuberoot(8)) * Cot 8 + Tan 8 = 43,
    here, the total value is around 42.9, so by rounding up we get 43.
    Next is 44...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! + (4*4) + 4 = 44

    (8 - cuberoot(8)) * Cot 8 +Cuberoot (8) = 44

    next 45 ..
  • RajdeepCE
    RajdeepCE
    For 45,
    4! + 4! - 4 + Cos 4 = 45,
    ( 8 + 8 ) * Log[sub]2[/sub]8 - Log[sub]2[/sub]8 = 45,
    here, Log[sub]2[/sub]8=3
    next is 46.
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    @Rajdeep edit your last post it is 8+8 not 8 * 8 thanks

    for 46..

    4!+4!+Sqrt(4)-4 = 46

    (8+8)*Log8to the base2 - Cuberoot(8) =46

    Next 47..
  • RajdeepCE
    RajdeepCE
    Thanks ES!!
    For 47,
    4! + 4! - ( 4 / 4 ) = 47,
    ( 8 / cuberoot(8) )! * cuberoot(8) - Cos 8 = 47.
    Next is 48.
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! + 4! +4 -4 = 48

    8 * (cuberoot(8)+cuberoot(8)+cuberoot(8)) =48

    Next 49

    @Rajdeep : πŸ˜€
  • RajdeepCE
    RajdeepCE
    4! + 4! + ( 4 / 4 ) = 49,
    ( 8 / cuberoot(8) )! * cuberoot(8) + Cos 8 = 49.
    Waiting for half century!!!!
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4!+4!+4-Sqrt(4) =50

    (8+8) *Log8tothebase2 + Cuberoot(8) =50

    haha Half century sandy πŸ˜€

    Next 51 πŸ˜€
  • RajdeepCE
    RajdeepCE
    4! + 4! + sqrt(4) + Cos 4 = 51,
    (8 / cuberoot(8) )! * cuberoot(8) + Log[sub]2[/sub]8 = 51,
    Greas ES!!!
    Next is 52,
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4!+4!+Sqrt(4)+Sqrt(4) =52

    8*cot8 -(8/Cuberoot(8))= 52

    next 53
  • RajdeepCE
    RajdeepCE
    4! + 4! + 4 + Cos4 = 53
    8 * 8 - 8 - Log[sub]2[/sub]8 = 53
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4!+4!+4+Sqrt(4) = 54

    8*8 -8-Cuberoot(8) =54

    next 55
  • RajdeepCE
    RajdeepCE
    4! + 4! + ( Cot 4 / sqrt(4) ) = 55,
    ( 8 * 8 ) - 8 - Cos 8 = 55,
    next is 56,
  • shalini_goel14
    shalini_goel14
    4! + 4! + 4 + 4 =56

    (8 * 8 ) + sqrt(8*8) =56

    Go for 57..
  • RajdeepCE
    RajdeepCE
    Cot ( Cos 4 ) + 4 * ( 4 - 4 ) = 57,
    ( 8 * 8 ) - 8 + Cos 8 = 57,
    here Cot ( Cos 4 ) = 57.4, so by rounding of we get the answer.
  • Harshad Italiya
    Harshad Italiya
    4! + 4! + Cot4-4 = 58
    8*8-8+cuberoot(8)=58
    Next one 59...
  • RajdeepCE
    RajdeepCE
    Cot ( Cos 4 ) + ( 4 + 4 ) / 4 = 59,
    8 * 8 + Cot 8 - quberoot(8) = 59,
    here, Cot(Cos 4) = 57 approx. and Cot 8 = 7 appox.
    Next is 60...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4!+4! + Int(cot4) -cos4 =61

    8*8 -(Cos8+Cuberoot(8))= 61

    Next 62
  • Harshad Italiya
    Harshad Italiya
    4*4*4-sqrt(4)=62,
    8*8-cuberoot(8)-Sin(Sin8)=62,
    Sin(Sin8)=0.
    Go for 63...
  • RajdeepCE
    RajdeepCE
    4 * 4 * 4 - Cos 4 = 63,
    8 * 8 - ( 8 / 8 ) = 63,
    next is 64, easy one...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! +4! +(4*4) = 64

    8*8 +log(8/8) =64

    next 65
  • RajdeepCE
    RajdeepCE
    4 * 4 * 4 + Cos 4 = 65,
    8 * 8 + ( 8 / 8 ) = 65,
    next is 66.
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4 * 4 * 4 + Sqrt(4) =66

    8 * 8 +cos8+cos8 =66

    next 67
  • RajdeepCE
    RajdeepCE
    Cot ( Cos 4 ) + 4 + 4 + sqrt(4) = 67,
    8 * 8 + cuberoot(8) + Cos 8 = 67,
    next is 68...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4*4*4 +4 =68

    8*8+Cuberoot(8)+Cuberoot(8) =68

    next 69?
  • RajdeepCE
    RajdeepCE
    Cot ( Cos 4 ) + 4 + 4 + 4 = 69,
    8 * 8 + 8 - Log[sub]2[/sub]8 = 69,
    next is 70.,
  • shalini_goel14
    shalini_goel14
    Guys where is 60 gone? πŸ˜•
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    It was my error to ignore 60 and go for 61 Sorry guys.

    4! + 4! +Int(cot4) -sqrt(4) =60

    8*8 -Cuberoot(8)-Cuberoot(8) =60


    Thanks shalini for pointing it out.

    Guys 61 to 69 are done..
    So next go for 70.
  • RajdeepCE
    RajdeepCE
    For 70,
    4! + 4! + 4! - sqrt(4) = 70
    8 * 8 + 8 - quberoot(8) = 70,
    next is 71.
  • shalini_goel14
    shalini_goel14
    4! + 4! + 4! -( log[sub]4[/sub]4 ) = 71

    8 * 8 + 8 -( log[sub]8[/sub]8 ) = 71

    log[sub]n[/sub]n=1

    Go for 72..
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! * (4-(4/4)) =72

    8 * (8+(8/8)) = 72

    next 73
  • RajdeepCE
    RajdeepCE
    4! + 4! + 4! + Cos 4 = 73,
    ( 8 * 8 ) + 8 + Cos 8 = 73,
    next is 74...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! + 4! + 4! + Sqrt(4) =74


    8*8 +8 +Cuberoot(8) =74

    next 75
  • RajdeepCE
    RajdeepCE
    Cot ( Cos 4 ) + 4! - 4 - sqrt(4) = 75,
    ( 8 * 8 ) + 8 + Log[sub]2[/sub]8 =75,
    next is 76...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    4! +4! +4! + 4 = 76

    Int(Cot(cos8)) =57+log8tothe base2 + (8+8) = 76

    next 77

    PS.Thanks Rajdeep for correcting me
  • RajdeepCE
    RajdeepCE
    ES, you need to correct second one. Instead of (8*8) use (8+8).
    For 77,
    Cot(Cos 4) + ( 4 * 4 ) + 4 = 77,
    8 ( 8 + cuberoot(8) - Log[sub]2[/sub]8 = 77,
    next is 78...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    Int(Cot(cos(4!))-Log(4)) +4*4 =Int(62.71-0.6020)+16 =62+16 = 78

    (8* (8+cuberoot(8)))-Cuberoot(8) =78

    This took lot of time for me.

    next 79 πŸ˜€
  • RajdeepCE
    RajdeepCE
    ES, it was not so hard.
    ( 4 * 4! ) - Cot 4 - 4 = 78.
    For 79,
    Cot(Cos 4) + 4! - 4 + sqrt(4) = 79,
    ( 8 * 8 ) + 8 + Cot 8 = 79,
    next is 80...
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    Oh! rajdeep ok.. thanks πŸ˜€

    4! *4 - (4*4) =80

    (8*8)+8+8 =80

    next 81
  • RajdeepCE
    RajdeepCE
    ( 4! * 4 ) - Cot 4 - Cos 4 = 81,
    8 * ( 8 + cuberoot(8) ) + Cos 8 = 81,
    next is 82...
  • sheeko
    sheeko
    sorry i posted a wrong answer then delete it
  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    Int(Cot(cos(4!)))+4*4+4 =Int(62.71)+16+4 =62+16+4 = 82


    8*(8+cuberoot(8))+Cuberoot(8) = 82

    Next 83 πŸ˜€
  • RajdeepCE
    RajdeepCE
    ( 4! * 4 ) - Cot 4 + Cos 4 = 83,
    ( 8 * ( 8 + cuberoot(8) ) + Log[sub]2[/sub]8 = 83,
    next is 84,
  • RajdeepCE
    RajdeepCE
    * bump *
    4! * 4 + sqrt(4) - Cot 4 = 84,
    8 * ( 8 + sqrt(Cot 8) ) - Cos 8 = 84,
    next is 85...

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I need the help of persons who have knowledge in Graphic Designing. I need a good logo and since I am no good at Graphics, thought I'll ask for help...
hi guys , We have many people on CE more than 41K. So i wanted to ask a question , are you people stressed of working/reading etc etc . If...
We're less than a week away from the launch of the supposed next "iPhone killer," the Palm Pre. The iPhone has miraculously survived a few of these attempts on its...