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# Google Valentine Day Easter Egg: Algebraic Equation!

If you want to impress your friends with your Google search abilities; enter the following search query in Google search bar and hit enter.

sqrt(cos(x))*cos(300x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(6-x^2), -sqrt(6-x^2) from -4.5 to 4.5☕ What gives?

Valentine Day does not exist for year 2012!

Want proof?

Here:

Want proof?

Here:

**14-02-12 = 0****😁**
This one looks better:

Copy n paste in google

Copy n paste in google

sqrt(cos(x))*cos(180x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(6-x^2), -sqrt(6-x^2) from -4 to 4hit enter

There is warning in your code:The_Big_KIf you want to impress your friends with your Google search abilities; enter the following search query in Google search bar and hit enter.

sqrt(cos(x))*cos(300x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(6-x^2), -sqrt(6-x^2) from -4.5 to 4.5☕ What gives?

**The function might not be plotted correctly.**😛😁

Looks like you didn't copy the complete code (there's a horizontal scrollbar). Or maybe Google doesn't heart you? 😒ianoopThere is warning in your code:The function might not be plotted correctly.😛😁

Kidding!

This is kinda corrugated! Biggie's one was the BEST! 😛ianoopThis one looks better:

Copy n paste in google

sqrt(cos(x))*cos(180x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(6-x^2), -sqrt(6-x^2) from -4 to 4hit enter

When I saw it at first I wracked my brains over how the plot is 'shaded'. Because by definition a function is such that for a particular value of x , there is only one value of y.

But I noticed that the image is a very zoomed out version of the plot. If you zoom in it has got closely spaced sine-like curve. The zoomed-out version of the plot & the closely-spaced zero crossings give an impression of 'shaded' region. So it is indeed a function with each value of x having at most one value of y.

Nice job.

But I noticed that the image is a very zoomed out version of the plot. If you zoom in it has got closely spaced sine-like curve. The zoomed-out version of the plot & the closely-spaced zero crossings give an impression of 'shaded' region. So it is indeed a function with each value of x having at most one value of y.

Nice job.