
So here goes the first one for you....😉
1) In a row of boys A is 15th from the left and B is 4th from the right.there are three boys between A and B. C is the left of A.What is c's position from right?
NOTE: this appeared in the 2003 MBA paper.
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is it 9th ??
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2)A,B,C,D are 4 friends who do not mind exchanging items. A had 2 chessboards each costing Rs. 500 and a record player. C originally had a cycle and a walk man. each cricket bat costs Rs.700. Both D,C got a cricket bat from B. A gave his record player costing Rs.2000 to B.C got a camera costing Rs.1500 from D.The cycle costs Rs. 1000 and the Walkman costs Rs.700.B had 3 cricket bats initially.D had 2 cameras total cost of which is Rs.5000. A gave one of his chess boards to C and took C's cycle.C gave his walkman to D. (2006 MBA)
2.1)Who did not have a cricket bat at the end?
(a)A, (b)B, (c)C, (d)D
2.2)Total cost of materials C had in the begining?
(a)Rs.5000,(b)Rs.3000,(c)Rs.2100,(d)Rs.1700
2.3)who incurred the maximum loss in the transaction?
(a)D (b)A (c)C (d)B
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EnglishScared
is it 9th ??
Yeah you are right 😁
the answer for the 1st is 9th.
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2nd question continued....
2)A,B,C,D are 4 friends who do not mind exchanging items. A had 2 chessboards each costing Rs. 500 and a record player. C originally had a cycle and a walk man. each cricket bat costs Rs.700. Both D,C got a cricket bat from B. A gave his record player costing Rs.2000 to B.C got a camera costing Rs.1500 from D.The cycle costs Rs. 1000 and the Walkman costs Rs.700.B had 3 cricket bats initially.D had 2 cameras total cost of which is Rs.5000. A gave one of his chess boards to C and took C's cycle.C gave his walkman to D. (2006 MBA)
2.4)who made profit after the transactions..?
(a)A,B (b)A,D (c)B,C (d)C,D
2.5)After the transaction, who had items total cost of Rs. 1500?
(a)A (b)B (c)C (d)D
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3)In a certain coding system...
'816321' means 'the brown dog frightened the cat'
'64851' means 'the frightened cat ran away'
'7621'means 'the cat was brown'
'341' means 'the dog ran'
what is the code for 'the dog was frightened'?
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Answers:
1. A
2. 1700
3. A
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4. C
5. A
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Rohan_sK
Answers:
1. A
2. 1700
3. A
Guess these are correct !!!
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Rohan_sK
Answers:
1. A
2. 1700
3. A
EnglishScared
4. C
5. A
awesome going guys you got all the answers right.....😁
ANSWERS:
2.1)Who did not have a cricket bat at the end?
(a)A, (b)B, (c)C, (d)D
2.2)Total cost of materials C had in the begining?
(a)Rs.5000,(b)Rs.3000,(c)Rs.2100,
(d)Rs.1700
2.3)who incurred the maximum loss in the transaction?
(a)D
(b)A (c)C (d)B
2.4)who made profit after the transactions..?
(a)A,B (b)A,D
(c)B,C (d)C,D
2.5)After the transaction, who had items total cost of Rs. 1500?
(a)A (b)B (c)C (d)D
p.s: it would be better if you could also use the options when you give the answers.:smile:
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Hey guys the 3rd question remains unanswered....
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cooltwins
3)In a certain coding system...
'816321' means 'the brown dog frightened the cat'
'64851' means 'the frightened cat ran away'
'7621'means 'the cat was brown'
'341' means 'the dog ran'
what is the code for 'the dog was frightened'?
3241
is it right?.
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no yadav.
just try checking it again leisurely 😀
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Is the answer for the 3rd question: 1378
(i mean it can be in any order.)
is it right?
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yeah you are right princess...😀
the answer for the 3rd question is : 1378
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now to go on to the next set of questions.... 😛
4)if x men, working x hours per day, can do x units of work in x days then y men, working y hours per day would be able to complete how many units of work in y days?
(a) X^2/y^3 (b) x^3/y^2 (c) y^2/x^3 (d) y^3/x^2
^ to the power of.
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5)the front wheels of a wagon are 2(pi) feet in circumference and the rear wheels are 3(pi) feet in circumference. When the front wheels have made 10 more revolutions than the rear wheels how many feet has the wagon travelled?
(a)30(pi) (b)60(pi) (c)90(pi) (d)150(pi)
(pi)3.14
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cooltwins
5)the front wheels of a wagon are 2(pi) feet in circumference and the rear wheels are 3(pi) feet in circumference. When the front wheels have made 10 more revolutions than the rear wheels how many feet has the wagon travelled?
(a)30(pi) (b)60(pi) (c)90(pi) (d)150(pi)
(pi)3.14
Let x be the distance moved...
so the first wheel moves x/2(pi) revolutions.
2nd one moves x/3(pi) revolutions.
if the diff. in revolutions is 10
then 10=x/2(pi)x/3(pi) =x/6(pi) => x=60(pi).
so the answer is
(b) 60(pi)
hope it is correct😀
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yeah right princess....😀
what about the 4th one?
that is yet to be answered.😀
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hey guys what happened ....😔
no takers for the 4th question😕
it is an easy one try it......
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cooltwins
now to go on to the next set of questions.... 😛
4)if x men, working x hours per day, can do x units of work in x days then y men, working y hours per day would be able to complete how many units of work in y days?
(a) X^2/y^3 (b) x^3/y^2 (c) y^2/x^3 (d) y^3/x^2
^ to the power of.
work done by the xgroup =x*x*x(1)
work done by the ygroup =y*y*y(2)
(2)/(1)=>
y^3
x^3
but units of work done by xgroup is x
let units of work done by ygroup be a
=>
y^3=
a
x^3 x
=>a=y^3 / x^2
so is the solution
4)y^3 / x^2
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correct na....?
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nice set of questions.....
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you are right......😀
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now for the next set of questions.......
5)a car travelling 5/7th of its actual speed covers 42 km in 1hr 40 min 48 sec.find the actual speed of the car......:?:
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6) Pipe A can fill a tank in 20 minutes.Pipe A and B are opened and after 6 minutes Pipe A is closed.now the pipe B takes 15 more min. to fill the tank . in how many min. can the pipe B fill the tank....:?:
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ans for code breaking
i think it is :
1378
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cooltwins
2nd question continued....
2)A,B,C,D are 4 friends who do not mind exchanging items. A had 2 chessboards each costing Rs. 500 and a record player. C originally had a cycle and a walk man. each cricket bat costs Rs.700. Both D,C got a cricket bat from B. A gave his record player costing Rs.2000 to B.C got a camera costing Rs.1500 from D.The cycle costs Rs. 1000 and the Walkman costs Rs.700.B had 3 cricket bats initially.D had 2 cameras total cost of which is Rs.5000. A gave one of his chess boards to C and took C's cycle.C gave his walkman to D. (2006 MBA)
2.4)who made profit after the transactions..?
(a)A,B (b)A,D (c)B,C (d)C,D
2.5)After the transaction, who had items total cost of Rs. 1500?
(a)A (b)B (c)C (d)D
the answers are:
2.4c B,C
2.5a A
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shubhrajeet tiwa
ans for code breaking
i think it is :
1378
tech addict
the answers are:
2.4c B,C
2.5a A
your answers are all right.👍
now go ahead with the unsolved problems......😁
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cooltwins
6) Pipe A can fill a tank in 20 minutes.Pipe A and B are opened and after 6 minutes Pipe A is closed.now the pipe B takes 15 more min. to fill the tank . in how many min. can the pipe B fill the tank....:?:
Answer: 30 min
Is it correct?
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sarveshgupta
Answer: 30 min
Is it correct?
yep your ans is correct 👍
try to give the explanation and do go ahead with the rest of the sums.😀
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2)Answers
1.(a)A
2.1700
3.A
4.B,C
5.A
what is the answer?
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anuraadha
2)Answers
1.(a)A
2.1700
3.A
4.B,C
5.A
what is the answer?
yes your answer is right. 👍
and the fifth question remains unanswered...
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cooltwins
now for the next set of questions.......
5)a car travelling 5/7th of its actual speed covers 42 km in 1hr 40 min 48 sec.find the actual speed of the car......:?:
Let x be the average speed.
its present velocity is v=5x/7.
the distance s=42km.
the time taken is,t=1hr40min48sec=1.68hr
speed is v=s/t
5x/7=42/1.68=25
=>x=7X25/5=35km/hr
so is the answer
35km/hr?
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yep the answer is correct...👍
sorry for the delay in the reply......😔
just caught up for a few days.... and got time only today......😀
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7)now find the next number in the series.....:
72,53,34,25,......
sorry for the delay in the questions😀
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8)here are two questions in the form of a string of letters try and find out the gaps...
1. A c f j o u?
2. B l d m f n h o ??
think...think...😀
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9) A goldsmith has 5 gold rings each having a different weight. Ring 1 weighing twice as much as ring 2. Ring 2 is weighing four and onehalf times as much as ring 3. Ring 3 is weighing half as much as ring 4. Ring 4 is weighing half as much as ring 5. Ring 5 is weighing less than ring 1 but more than ring 3. Then which of them have the lightest weight?
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7) 16
is it correct?
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Here's my answer to question 9) ring 3 is lightest... Just want someone to confirm whether it's correct. Anyone?
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yadavundertaker
7) 16
is it correct?
no yadav i don't think it is correct
anyway how did you arrive at that solution..?
because there is no steadfast approach a series question and who knows you may have got another formula...😀
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yadavundertaker
9) ring 3 is lightest..
yep you are right..👍
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the 8th question remains unanswered..?
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8th question remains unanswered...but i am giving the next two questions.
10)Three farmers paid rs.1000 for a small pasture. one farmer grazed his 9 mules, another his 12 cows for twice the time and last man put in some goats for 2.5 times as the second man’s cow and paid half the cost of the pasture.
Can you find out how many goats did the last man have,if 6 cows eat as much as 4 mules and 10 goats as much as 3 cows?and how much did the first and second man each pay?
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11)A five feet long staff casts a shadow 2 feet long.can you find the height of a steeple whose shadow at the same hour is 120 ft long?
three questions to be answered are 8,10,11.all the best!👍
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cooltwins
8)here are two questions in the form of a string of letters try and find out the gaps...
1. A c f j o u?
2. B l d m f n h o ??
think...think...😀
1. B or Z ( not very sure)
2. J P
Logic.. A to C the letters in between 1 so on going we get the difference as 2 ,3 ,4 ,5 so if we consider next is 6 we get as B if not lets go back to 4 then its Z.
For second one the sequence is +9 7 +8 6 +7 5 +6 4 and +5
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If we calculate tanx = 5/2
if we calculate it we get 300.
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EnglishScared
1. B or Z ( not very sure)
2. J P
Logic.. A to C the letters in between 1 so on going we get the difference as 2 ,3 ,4 ,5 so if we consider next is 6 we get as B if not lets go back to 4 then its Z.
For second one the sequence is +9 7 +8 6 +7 5 +6 4 and +5
Yes ES i too will like to go with your answers
Well what do you mean by the explanation of second i am unable to figure out what are you trying to say?
It was easy by way of looking at it carefully
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EnglishScared
1. B or Z ( not very sure)
2. J P
Logic.. A to C the letters in between 1 so on going we get the difference as 2 ,3 ,4 ,5 so if we consider next is 6 we get as B if not lets go back to 4 then its Z.
For second one the sequence is +9 7 +8 6 +7 5 +6 4 and +5
yes es you are right...👍
and the first one is B only......😀
and for the 2nd set make this series into two by grouping the alternate terms.
then it is really simple i believe.....😛
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EnglishScared
If we calculate tanx = 5/2
if we calculate it we get 300.
yep you are right😀
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cooltwins
no yadav i don't think it is correct
anyway how did you arrive at that solution..?
because there is no steadfast approach a series question and who knows you may have got another formula...😀
logic 1
7234=38
5325=28
34x=18
on solving we get x= 16
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yadavundertaker
logic 1
7234=38
5325=28
34x=18
on solving we get x= 16
yeah this does work out....but that is not the required logic....
ok,now i will give you the next term and now try and find the logic😀
old series is 72,53,34,25,......
the new series (after the inclusion of next term ) is
72,53,34,25,
29.
now does this sound better try it .........
looking forward to the logic.😀
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so 7th one's required logic is yet to be answered and 10th one remains untouched....
think.....think... ceans
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12)A person has Rs 100/ in his pocket, he can as 25 pencils or 15books.He kept 15% of the money for travelling expenses and purchased 5 pencils.So how many books he can purchase with the remaining money. a) 4 b) 3 c) 5 d)none:?😔from an IBM aptitude paper...)
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13)Find the next two numbers of the sequence given below
1,11,100,121,221, ___ , ___
this is a tough one....:evil:
but think....think......👍
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cooltwins
12)A person has Rs 100/ in his pocket, he can as 25 pencils or 15books.He kept 15% of the money for travelling expenses and purchased 5 pencils.So how many books he can purchase with the remaining money. a) 4 b) 3 c) 5 d)none:?😔from an IBM aptitude paper...)
@12
ans: d) none
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cooltwins
7)now find the next number in the series.....:
72,53,34,25,......
@7
answer 29
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ratikagoel
@12
ans: d) none
ratikagoel
@7
answer 29
hey ratika...
please do provide the solution along with the reasoning and method of solving😁
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ya sure y not
for 7th ques
72,53,34,25,......
7^2+2^2=53
5^2+3^2=34
3^2+4^2=25
so
2^2+5^2=29
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for 12th ques
25 pencils = 100 , so each pencil is Rs 4/
15 books = 100, so each book is 100/15
Now, he has kept aside 15%, that is 15 Rs
So, he is left with 85 rs
nd den he bought 5 pencils dat cost him 20rs
nw remaining money is 8520=65
1 book is of rs ~6.6
X = 65 * 15 / 100 = 39/4 ~ 9
with 65 rs he can buy 9 books
So, answer is none.
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ratikagoel
for 12th ques
25 pencils = 100 , so each pencil is Rs 4/
15 books = 100, so each book is 100/15
Now, he has kept aside 15%, that is 15 Rs
So, he is left with 85 rs
nd den he bought 5 pencils dat cost him 20rs
nw remaining money is 8520=65
1 book is of rs ~6.6
X = 65 * 15 / 100 = 39/4 ~ 9
with 65 rs he can buy 9 books
So, answer is none.
ratikagoel
ya sure y not
for 7th ques
72,53,34,25,......
7^2+2^2=53
5^2+3^2=34
3^2+4^2=25
so
2^2+5^2=29
yes.....😀
good going ratika.........👍
and why don't you try the 10th and the 13th question......
ps: avoid usind SMS language in the forum. it is against the forum rules.....😀
good luck with the rest of the problems😀
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i m trying them too cooltwins
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in btw keep on posting ques yr
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ratikagoel
in btw keep on posting ques yr
sure will post more.....but don't use SMS language .....:smile:
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ok
i will keep it my mind while replying or posting
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answer for 13th ques.
253 and 364
is it correct?
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1,11,100,121,221,253,364
1001=99
12111=110
nd 11099=11
similarly
221100=121
121110=11
so let next term is x
ie x121=y
nd y121=11
so y=132
therefore
x=132+121=253
similarly for next term
x221=y
y132=11
y=143
x=221+143=364
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ratikagoel
answer for 13th ques.
253 and 364
is it correct?
awesome ratika........:clap:
you are indeed right......👍
and 10th question is still unanswered.........😀
why don't you try it......😛
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thanks cooltwins
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and here is a question for you people......
it was set as challenge and we are yet to discover the answers....
and i believe the brilliant minds here can surely solve this question.....👍
(because you are all the cooltwin's aptitude center students😉 😁.....just kidding)
14) ###
X###

##11
33##
##22

#3####
try and solve this i am trying them myself too😲
and don't forget 10th one remains too.....
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just solved the 14th one....:dance:
TIP:try using a template written in pen and try diff combos in pencil till you get it right...😉
that's how i did it.......took a whole hour to solve it.....
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cooltwins
and here is a question for you people......
it was set as challenge and we are yet to discover the answers....
and i believe the brilliant minds here can surely solve this question.....👍
(because you are all the cooltwin's aptitude center students😉 😁.....just kidding)
14) ###
X###

##11
33##
##22

#3####
try and solve this i am trying them myself too😲
and don't forget 10th one remains too.....
answer of 14th ques
837
X643

2511
3348X
5022XX

538191
😁
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Here is one question
15) A monkey starts climbing up a tree 20ft. tall. Each hour, it hops 3ft. and slips back 2ft. How much time would it take the monkey to reach the top?
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Is the answer for the 10th question 25 goats?
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sarveshgupta
Here is one question
15) A monkey starts climbing up a tree 20ft. tall. Each hour, it hops 3ft. and slips back 2ft. How much time would it take the monkey to reach the top?
So the relative movement per hour will be 1 ft.
in 17 hours it climbs 17 ft.
in the 18th hour it climbs 3 ft. and reaches 20 ft.
so the answer is
18 hours.
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ratikagoel
answer of 14th ques
837
X643

2511
3348X
5022XX

538191
😁
awesome ratika....:clap:
great going........👍
try solving the 10th one.......
Are you sure? This action cannot be undone.

sarveshgupta
Is the answer for the 10th question 25 goats?
hey sarvesh.....
you haven't answered the entire question.....😀
and yeah i do appreciate you posting questions in this thread....👍
so come up with the entire solution for the 10th one........
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CIVILPRINCESS
So the relative movement per hour will be 1 ft.
in 17 hours it climbs 17 ft.
in the 18th hour it climbs 3 ft. and reaches 20 ft.
so the answer is 18 hours.
You are absolutely right CP
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cooltwins
hey sarvesh.....
you haven't answered the entire question.....😀
and yeah i do appreciate you posting questions in this thread....👍
so come up with the entire solution for the 10th one........
Ok then the answer should be
The third man had
25 goats
the first farmer paid
Rs 180 while the second man paid
Rs 320
Am I right now? 😁
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sarveshgupta
Ok then the answer should be
The third man had 25 goats
the first farmer paid Rs 180 while the second man paid Rs 320
Am I right now? 😁
awesome sarvesh..:clap:
you are right...👍
atlast the 10th question is answered...
will upload more questions soon😀
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16)You walk upwards on an escalator, with a speed of 1 step per second.
After 50 steps you are at the end.
You turn around and run downwards with a speed of 5 steps per second.
After 125 steps you are back at the beginning of the escalator.
The escalator is moving upward with a speed of 1 step per second.
Question:
How many steps do you need if the escalator stands still?
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IS the answer 100 ?
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EnglishScared
IS the answer 100 ?
yeah your answer is correct ES....👍
do try and give the explanation..........😒
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17)Find the odd one out…:?:
19,28,39,52,67,84,102.
(a)52 (b)102 (c)84 (d)67
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18)Find the odd one out…:?:
888,440,216,104,48,22,6.
(a)440 (b)216 (c)104 (d)48 (e)22
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19)Find the odd one out…:?:
2807,1400,697,347,171,84,41,20
(a)697 (b)347 (c)171 (d)84 (e)12
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20)One morning I was on my way to the market…i met a man who had four wives each wife had four baskets containing four dogs.each dog had four puppies . taking this into consideration how many were going to the market…. :?:
so four questions for you to solve....😀
SO GET SOLVING..........👍
Are you sure? This action cannot be undone.

cooltwins
17)Find the odd one out…:?:
19,28,39,52,67,84,102.
(a)52 (b)102 (c)84 (d)67
Answer is b)
102
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cooltwins
18)Find the odd one out…:?:
888,440,216,104,48,22,6.
(a)440 (b)216 (c)104 (d)48 (e)22
Answer is e)
22
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cooltwins
20)One morning I was on my way to the market…i met a man who had four wives each wife had four baskets containing four dogs.each dog had four puppies . taking this into consideration how many were going to the market…. :?:
so four questions for you to solve....😀
SO GET SOLVING..........👍
Only two people you and the man you met
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cooltwins
20)One morning I was on my way to the market…i met a man who had four wives each wife had four baskets containing four dogs.each dog had four puppies . taking this into consideration how many were going to the market…. :?:
so four questions for you to solve....😀
SO GET SOLVING..........👍
answer:
only myself
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cooltwins
19)Find the odd one out…:?:
2807,1400,697,347,171,84,41,20
(a)697 (b)347 (c)171 (d)84 (e)12
answer
(b)347
41%20=1
84%41=2
171%84=3
so
347%171=5 which is wrong
😁
Are you sure? This action cannot be undone.

sarveshgupta
Answer is b) 102
sarveshgupta
Answer is e) 22
yeah right.....👍
what about the explanation sarvesh....:?:
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sarveshgupta
Only two people you and the man you met
no sarvesh you fell for the trick....😀
you are the only person who goes to the market....you only meet the other person on the way...😉
so the answer is only one...
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ratikagoel
answer:
only myself
yes you are right ratika👍
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ratikagoel
answer
(b)347
41%20=1
84%41=2
171%84=3
so
347%171=5 which is wrong
😁
yup your answer is right ratika😀
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sorry for the delay to post the next question guys.......
no broadband connection for 2 days due to some signal problem ........
anyway here goes the next question.....
21) probability of a bomb hitting a target is 1/5
2 bombs are required to blast off a bridge.
if 6 bombs are aimed at the bridge ........ find the probability that the bridge is destroyed........:?:
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and guys please do post your logic when you solve some question......
you can follow the format:
question no.) (option if provided) ans.
LOGIC:
         
it would be more clear this way......😀
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hey guys what happened to the 21st question.:?:
no takers?
anyway here goes the 22nd one:
22) what next...?
(1,2) (5,10) (15,30) (37,74) ...............
(a) (80,160) (b) (82,164) (c) (83,166) (d) (84,168)
put your thinking caps on.....
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and here is the 23rd one....
23) in a chess tournament each player plays with every other player exactly once and a total of 190 games were played.so how many players participated in the tournament?
(a)21 (b)20 (c)19 (d)18
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Answer of Qstn 22> it is c) 83,166
solution : 51=4
155=10
3715=22
4*2+2=10
10*2+2=22
22*2+2=46
46+37=83
rite?"?
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19 players have played games
hence answer is c)19
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dazzling
Answer of Qstn 22> it is c) 83,166
solution : 51=4
155=10
3715=22
4*2+2=10
10*2+2=22
22*2+2=46
46+37=83
rite?"?
YEP YOU ARE RIGHT DAZZLING....👍
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dazzling
19 players have played games
hence answer is c)19
hey dazzling.....
just try checking the 23rd question once more....😉
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its question 23 :by using permutation ,combination
the equation is (n C 2) means n!/((n2)!*2!)=190
so its a quardatic ,and answer is 20.
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cooldudeiet
its question 23 :by using permutation ,combination
the equation is (n C 2) means n!/((n2)!*2!)=190
so its a quardatic ,and answer is 20.
Yeah right cooldudeiet👍
way to go......
go on to the next questions....
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21: (6 C 2) (1/5)pow2*(11/5)pow4 its a binomial distribution
so after solving 768/3125
am i right?
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cooldudeiet
21: (6 C 2) (1/5)pow2*(11/5)pow4 its a binomial distribution
so after solving 768/3125
am i right?
yup you are absolutely right...great going👍
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24) The needle of a compass is turned in such a manner that the pointer which was pointing 45 degrees clockwise from south is now showing north. a person went towards the geographical east as per the above compass. in what direction did he want to go?
(a) south west (b)north west (c)north east (d)south east
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Here is the grand 25th question of cooltwins aptitude centre:clap: :dance: :clap:
25) A,B,C,D,E are five cars and P,Q,R are 3 motorcycles.
A is the fastest of the cars.and R is the slowest of the motorcycles.
C is costlier than D and Q but cheaper than B.
Among the cars A is not the costliest.
D is cheaper than E and there is no car whose cost lies between these two.
E is faster than 3 of the cars and all of the motor cycles.
Q is costlier than R but cheaper than P.
P is faster than Q.
25.1)which of the following cars can not stand exactly in the center position as far as the cost is concerned?
(a)A (b)C (c)E (d)D
25.2) which of the following is true?
(a)P is the costliest as well as fastest.
(b)fastest motorcycle is not the costliest
(c) slowest motorcycle is the cheapest one.
(d) both (a) and (c)
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continuation of 25th question.:
25) A,B,C,D,E are five cars and P,Q,R are 3 motorcycles.
A is the fastest of the cars.and R is the slowest of the motorcycles.
C is costlier than D and Q but cheaper than B.
Among the cars A is not the costliest.
D is cheaper than E and there is no car whose cost lies between these two.
E is faster than 3 of the cars and all of the motor cycles.
Q is costlier than R but cheaper than P.
P is faster than Q.
25.3) if P is the costliest than E how many cars are cheaper than P?
(a) 1 (b)2 (c)3 (d)cannot be determined.
25.4)if P is cheaper than A which is not costlier than E , which of these is the cheapest of all cars and motorcycles put together?
(a)R (b)Q (c)E (d)cannot be determined.
25.5) which of these is the slowest of the cars, if B and C are faster than D?
(a) B (b) D (c) E (d) A
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hey i guess its c)north east...
its because initially he was at southwest...and north of southwest is north east...
M i right...???
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Qst 25.1 : ans : d) D
25.2 ; ans : b) fastest motorcycle is not the costliest
25.3 : ans : a) 1
25.4 : ans : a) R
25.5 : ans : b) D
rite?
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Guttu
Member •
Dec 16, 2009
25.1 D
25.2 both a and c
25.3 2
25.4 cannot be determined
25.5 D
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dazzling
Qst 25.1 : ans : d) D
25.2 ; ans : b) fastest motorcycle is not the costliest
25.3 : ans : a) 1
25.4 : ans : a) R
25.5 : ans : b) D
rite?
Guttu
25.1 D
25.2 both a and c
25.3 2
25.4 cannot be determined
25.5 D
hey dazzling and guttu,
both got answers partially right...😀
but any way good going from both of you👍
here are the correct answers:
25.1) (d) D
25.2) (d) both A and C
25.3) (b) 2
25.4) (a)R
25.5) (b) D
will post more questions soon😉
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Guttu
Member •
Dec 17, 2009
OOps... just one wrong.
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doesn't matter guttu😀
wait for more competitive questions👍
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my first question and 26th question of this thread...
Q.26) A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally?
a) 100
b) 110
c) 97
d) 11
please give answer with solution.
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dazzling
my first question and 26th question of this thread...
Q.26) A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally?
a) 100
b) 110
c) 97
d) 11
please give answer with solution.
hey dazzling,
are you sure that the question and the options is correct....:?:
because for a work the product of the no. of workmen and the days that they take is constant...😕
so will be getting,
(x10)*20=x*10
20x200=10x
10x=200
X=20
but this is not one of the options....😔
let me know if my approach is wrong.
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Guttu
Member •
Dec 18, 2009
^^^
I agree with that logic but not sure if it's true. 😲
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I've seen this question in one of the online aptitude tests.i was unable to get solution of this question.thats y i asked for solution. i also dont knw how to solve it. but i knw the ans. ans is 110 workers. dont knw how.
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hey dazzling,
in order to get 110 workers as answer, the initial no. of days must be 100.
see and try it out with the initial time as 100 days the solution is 110.so the problem is the question i think....
check it out 😀
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yes you are correct.i think the initial days should be 100. good job twin.
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dazzling
yes you are correct.i think the initial days should be 100. good job twin.
yeah the question should be 100.😀
and what is up with the "twin" you mentioned...did you mean CEan cooltwins :?:
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ooops. i did a mistake here also.sorry for that.princess.that time i was in a hurry. thats y i wrote cooltwins. anyway now its your turn to post a question. i think so. its looking like something is missing in this thread without question.hope to have question soon..
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hey dazzling 😀
sorry for the delay in posting the next question
heregoes the next one:
27) what is the angle between the hour hand and the minute hand when the time is 3:25?
think think......
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cooltwins
hey guys what happened to the 21st question.:?:
no takers?
anyway here goes the 22nd one:
22) what next...?
(1,2) (5,10) (15,30) (37,74) ...............
(a) (80,160) (b) (82,164) (c) (83,166) (d) (84,168)
put your thinking caps on.....
and by the way this question has been unattended to.....😒
guys try solving this too.
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anyway here goes the next one:
28)at what time between 8 and 9 will the hands of a clock be in a straight line and not be together?
so there are three questions(22,27,28) in front of you to solve
and as usual get solving....👍
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I think I've given the answer of 22nd question. and you said that was rite.
According to me the answer of 27th question shud be 51 degree 36 minute.
is it right?
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I am not sure but i think answer will be
b) for 21 question
am I right?
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yeah the 22nd qeustion has been answered.
and the anwer for 27th one i think is 47.5 degrees....
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oops looks like it was my turn to make a mistake 😳
any way you still have 2 questions
and as for the 27th question it is a toipc i myself am not too sure about the solution
the answer of CP is actually right but both of you do try and provide the logical solution.😀
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goyal420
I am not sure but i think answer will be
b) for 21 question
am I right?
goyal,
i think you have made a mistake with the question no. because 21 has no option 😀
let me know of the correct question😀
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22) what next...?
(1,2) (5,10) (15,30) (37,74) ...............
(a) (80,160) (b) (82,164) (c) (83,166) (d) (84,168)
sorry
is the answer c) for this
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hey goyal check out the 21st question...it has no options...so what options are you saying...please check the question number again😛
cooltwins
21) probability of a bomb hitting a target is 1/5
2 bombs are required to blast off a bridge.
if 6 bombs are aimed at the bridge ........ find the probability that the bridge is destroyed........:?:
Are you sure? This action cannot be undone.

goyal420
22) what next...?
(1,2) (5,10) (15,30) (37,74) ...............
(a) (80,160) (b) (82,164) (c) (83,166) (d) (84,168)
sorry
is the answer c) for this
yup,you are right goyal...👍
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the angle covered in every minute is 6 (since 360/60)
so when the time is 3:25,
the angle made by minutes hand with respect to the 12th hour is 5x5x6=150.
then the angle made by the hour hand :
for every 1 hr the angle made is 30.
so for 3 hour 90
and for 25 mins past the hour hand makes an angle of 12.5
(every hour has 5 division so 30/5=6
so for every 12 mins it moves through one division
so for 25 mins it travels a little more the 2 division
so lets take the answer as 12.5)
therefore total angle made by hour hand is 102.5
angle between the two hands is 150102.5=47.5
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i got the ans for 28th question .
ans is 8hrs 10.9090 mins.
am i right??
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yeah right CP.
and lets move on to more questions.
28) A train running at 54 kmph takes 20 seconds to pass a platform . it takes 12 secs to pass a man walking at 6kmph in same direction in which train is going.Find the length of the train and the length of the platform?
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dazzling
i got the ans for 28th question .
ans is 8hrs 10.9090 mins.
am i right??
yeah you are right dazzling...👍
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ans of 29th question:
length of train is 280 m.
length of platform is 20 m.???
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30)shobana's maths test had 75 problems i.e.,10 arithmetic,30 algebra,35 geometry problems.although she answered 70% of the arithmetic,40%algebra and 60% geometry problems correctly she did not pass the test because she got less than 60% of the problems right.how many more questions would she have to answer correctly to earn a 60% passing grade.?
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dazzling
ans of 29th question:
length of train is 280 m.
length of platform is 20 m.???
no dazzling the answer is not correct....
do try again with it.:smile:
...and provide the solution always along with the answer...😀
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31)a cone,a hemisphere, a cylinder stand on equal bases and have same height. find the ratio of their volumes.
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32)two pipes can fill a cistern in 14 hours and 16 hours respectivly.the pipes are opened simultaneously and due to leakage it took 32 mins. more to fill the cistern.when the cistern is full in what time will the leak empty it :?:
so four questions to be answered are :29,30,31,32.
so..think...think...😁
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Q.29) distance traveled by train in 20 secs =20*( 54*1000/3600 ) = 300 m
distance traveled by train in 12 secs = 12*( 54*1000/3600 ) =180 m
distance traveled by man in 12 secs = 12*( 6*1000/3600 ) =20 m
length of train = 18020= 160m
length of platform = 300  length of train
= 300  160
= 140 m
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Q.29) shobana has to solve more 5 questions correctly to get 60% marks.
solution : 70% of 10 qst = 7
40% of 30 qst = 12
60% of 35 qst = 21
total = 40
40/75*100=53.66 %
60 % of 75 = 45
hence more questns to be solved = 4540 = 5
Q.30) volume of cone : volume of hemisphere : volume of cylinder
height of each solid = d/2...as height of hemisphere is d/2
taking ration of each volume, we get
1 : 2 : 3
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Everybody is looking inactive related to aptitude.
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hey dazzling the last question still remains unanswered you could have tried that..... 😀
anyway as for the answers:
dazzling
Q.29) distance traveled by train in 20 secs =20*( 54*1000/3600 ) = 300 m
distance traveled by train in 12 secs = 12*( 54*1000/3600 ) =180 m
distance traveled by man in 12 secs = 12*( 6*1000/3600 ) =20 m
length of train = 18020= 160m
length of platform = 300  length of train
= 300  160
= 140 m
yup dazzling your answer is right....👍
in qn. no. 29
the lenght of train is 160m
the length of platform is 140m
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dazzling
Q.29) shobana has to solve more 5 questions correctly to get 60% marks.
solution : 70% of 10 qst = 7
40% of 30 qst = 12
60% of 35 qst = 21
total = 40
40/75*100=53.66 %
60 % of 75 = 45
hence more questns to be solved = 4540 = 5
Q.30) volume of cone : volume of hemisphere : volume of cylinder
height of each solid = d/2...as height of hemisphere is d/2
taking ration of each volume, we get
1 : 2 : 3
cool dazzling both your answers are right...👍
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sorry for the delay....
here is something i came across:
33)Can you fiind the tenth number in this series?
3, 3, 5, 4, 4, 3, 5, 5, 4, ?
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one more series question:
34)find d next number of the series...
2,10,42,130,?
and don't forget the 32nd question lies untouched...
come on attempt it😀
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cooltwins
one more series question:
34)find d next number of the series...
2,10,42,130,?
and don't forget the 32nd question lies untouched...
come on attempt it😀
answer is 266
2*5=10
10*4=40+2=42
42*3=126+4=130
130*2=260+6=266
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cooltwins
sorry for the delay....
here is something i came across:
33)Can you fiind the tenth number in this series?
3, 3, 5, 4, 4, 3, 5, 5, 4, ?
answer is 3
two 3
one 5
two 4
one 3
two 5
one 4
two 3
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cooltwins
sorry for the delay....
here is something i came across:
33)Can you fiind the tenth number in this series?
3, 3, 5, 4, 4, 3, 5, 5, 4, ?
I think answer is 4
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ratikagoel
answer is 3
two 3
one 5
two 4
one 3
two 5
one 4
two 3
though your answer is right..... but the logic used is wrong...
try it again 😀
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ratikagoel
answer is 266
2*5=10
10*4=40+2=42
42*3=126+4=130
130*2=260+6=266
yeah right......👍
carry on...
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cooltwins
32)two pipes can fill a cistern in 14 hours and 16 hours respectivly.the pipes are opened simultaneously and due to leakage it took 32 mins. more to fill the cistern.when the cistern is full in what time will the leak empty it :?:
what about this question guys...
it is not exactly a tough one...
give it a try.....
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35) A software engineer has the capability of thinking 100 lines of code in five minutes and can type 100 lines of code in 10 minutes.He takes a break for fiveminutes after every ten minutes. How many lines of codes will he complete typing after an hour:?:
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cooltwins
32)two pipes can fill a cistern in 14 hours and 16 hours respectivly.the pipes are opened simultaneously and due to leakage it took 32 mins. more to fill the cistern.when the cistern is full in what time will the leak empty it :?:
volume of cistern = V
volume through one pipe in 32 hrs = 32V/14
volume through another pipe in 32 hrs = 32V/16
Total volume through both pipes in 32 hrs = 32V/14+32V/16
total volume leaked = (32V/14+32V/16)V
time required to leak above volume = 32hrs
time required to leak volume V = ?
time required = 32V/[(32V/14+32V/16)V]
= V/[V/14+V/16V/32]
= 1/[1/14+1/161/32]
= 1/[0.71428+0.06250.03125]
= 1.34
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cooltwins
35) A software engineer has the capability of thinking 100 lines of code in five minutes and can type 100 lines of code in 10 minutes.He takes a break for fiveminutes after every ten minutes. How many lines of codes will he complete typing after an hour:?:
i think the answer for this question is he types
250 lines
am i right...:?:
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36)There is a pole in a lake.Onehalf of the pole is in the ground, another onethird of it is covered by water, & 8 ft is out of the water.
Then,What is the total length of the pole in ft?
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dazzling
cooltwins
32)two pipes can fill a cistern in 14 hours and 16 hours respectivly.the pipes are opened simultaneously and due to leakage it took 32 mins. more to fill the cistern.when the cistern is full in what time will the leak empty it :?:
volume of cistern = V
volume through one pipe in 32 hrs = 32V/14
volume through another pipe in 32 hrs = 32V/16
Total volume through both pipes in 32 hrs = 32V/14+32V/16
total volume leaked = (32V/14+32V/16)V
time required to leak above volume = 32hrs
time required to leak volume V = ?
time required = 32V/[(32V/14+32V/16)V]
= V/[V/14+V/16V/32]
= 1/[1/14+1/161/32]
= 1/[0.71428+0.06250.03125]
= 1.34
no dazzling
check it again
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CIVILPRINCESS
i think the answer for this question is he types 250 lines
am i right...:?:
yup CP you are right.😀
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Guttu
Member •
Jan 4, 2010
cooltwins
36)There is a pole in a lake.Onehalf of the pole is in the ground, another onethird of it is covered by water, & 8 ft is out of the water.
Then,What is the total length of the pole in ft?
48ft :idea:
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yeah right guttu.....👍
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hello guys, 😀
here are the next set of questions.....
37) how do get 20 by using four 4s.
rules:
the operators that can be used are the basic mathematics operators which are +,,*,/.
 there must be an operator between two 4s...i.e.you cannot use 44 or 444,etc.
 and no splitting of the number...like 2 and 2...
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38) now how do you get 1000 from eight 8s...:?:
note :the same rules above apply here also....😀
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32)two pipes can fill a cistern in 14 hours and 16 hours respectivly.the pipes are opened simultaneously and due to leakage it took 32 mins. more to fill the cistern.when the cistern is full in what time will the leak empty it
guys this question still remains unanswered.....😒
its not that tough so try it...;)
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cooltwins
37) how do get 20 by using four 4s.
is answer
(4+(4/4))*4
because that becomes (4+1)*4=20
am i right...:?:
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cooltwins
38) now how do you get 1000 from eight 8s...:?:
note :the same rules above apply here also....😀
((((8*8)+(8*8))*8)888)
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yeah you are right ratika...
and sorry for the delay in the next question.....
here it goes.....
39) Suppose you are captain of the ship "sail away". Ship is going from India to Australia. In between Indian Ocean, after traveling for 10 hours, storm came. The only way to be safe from storm was to go back to India or go to Malaysia. But captain told that we will go straight and fortunately storm also became less aggressive. They crossed the danger and continued journey well. Can you guess the age of captain who took a strong and dangerous decision but at last won
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40)The 4 people are lined up on some steps They are all facing in the same direction. A wall seperates the fourth man from the other three.
So to summarise :
Man 1 can see men 2 and 3.
Man 2 can see man 3.
Man 3 can see none of the others.
Man 4 can see none of the others.
They are wearing hats. They are told that there are two white hats and two black hats. The men initially don't know what colour hat they are wearing. They are told to shout out the colour of the hat that they are wearing as soon as they know for certain what colour it is.
RULES:
They are not allowed to turn round or move.
They are not allowed to talk to each other.
They are not allowed to take their hats off.
Who is the first person to shout out and why?
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Is the question complete?
I think you should also give the colour of hats they are wearing in the question.
Man1  White , Man2  Black , Man3  White  Man4  Black.
Man 2 will shout and he is rite 😀
Because , Man 3 and Man 4 cannot see anyone so they cannot answer.
Now if Man 1 can see other two but he cannot shout because he is uncertain.
Man2 can see only man3 thus Man2 will shout he is wearing black hat because if he is wearing white one Man1 would be certain of his hat.
Did you get me?
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cooltwins
yeah you are right ratika...
and sorry for the delay in the next question.....
here it goes.....
39) Suppose you are captain of the ship "sail away". Ship is going from India to Australia. In between Indian Ocean, after traveling for 10 hours, storm came. The only way to be safe from storm was to go back to India or go to Malaysia. But captain told that we will go straight and fortunately storm also became less aggressive. They crossed the danger and continued journey well. Can you guess the age of captain who took a strong and dangerous decision but at last won
Yes I need not guess the age, if suppose I am the captain then its my age 😀
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EnglishScared
Yes I need not guess the age, if suppose I am the captain then its my age 😀
yes you are right captain..😀
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EnglishScared
Is the question complete?
I think you should also give the colour of hats they are wearing in the question.
Man1  White , Man2  Black , Man3  White  Man4  Black.
Man 2 will shout and he is rite 😀
Because , Man 3 and Man 4 cannot see anyone so they cannot answer.
Now if Man 1 can see other two but he cannot shout because he is uncertain.
Man2 can see only man3 thus Man2 will shout he is wearing black hat because if he is wearing white one Man1 would be certain of his hat.
Did you get me?
hey ES,
the question is complete....😀
there will be only two possibilities:
I) both 2nd and 3rd are wearing the same colour......
then 1st guy will shout the answer.
II) 2nd and 3rd wear the opposite colours.....
then what you said happens... i.e., 2nd guy shouts out his colour.
this was the expected answer...
and you did get it right.
then why do you want the colours also mentioned 😛
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41)A standard sized cigarette can be rolled out of 6 standard sized cigarette butts. How many cigarettes can be made and smoked from 36 butts :?:
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42)A box contains 12 marbles of three different colours green, yellow and blue 4 each.
If you were to take the marbles at random with your eyes closed, how many marbles must you take out to be sure that there are at least two of one colour among the marbles are picked.
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I think 4 marbles
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yep you are right...😉
and what about the 41st question?
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43)There are two persons each having same amount of
sweets in the beginning and 1st person gains 20 more
From the second person and he eventually lose two
Thirds of it during a bet and now the second person has four times sweets of what first person is having now.find how much sweets did each have in the
beginning ?
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44)here is a question that is a bit tough but just try it or i will give the answer:
How many squares are there on a chessboard? How many rectangles?
so 41,43,44 remain to be answered.👍
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cooltwins
41)A standard sized cigarette can be rolled out of 6 standard sized cigarette butts. How many cigarettes can be made and smoked from 36 butts :?:
Is the answer
6.
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gaurav.bhorkar
Is the answer 6.
no check it out again gaurav 😀
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cooltwins
44)here is a question that is a bit tough but just try it or i will give the answer:
How many squares are there on a chessboard? How many rectangles?
the answer for the last question is:
Number of squares in a chessboard:
1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2 + 7^2 + 8^2 = 204.
Formula N = (n(n+1)(2n+1))/6
Number of rectangles in a chessboard:
There are 9 vertical lines and 9 horizontal lines. To form a rectangle
you must choose 2 of the 9 vertical lines, and 2 of the 9 horizontal
lines. Each of these can be done in 9C2 ways = 36 ways. So the number
of rectangles is given by 36^2 = 1296.
Formula N = (n(n+1)/2)^2
do try the 41st and 43rd questions....they are easy😀
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cooltwins
41)A standard sized cigarette can be rolled out of 6 standard sized cigarette butts. How many cigarettes can be made and smoked from 36 butts :?:
the answer would be 7 .
out of the 36 cigars we get 36 cigarette butts.
with 36 cigarette butts we can make
6 cigars.
and on smoking these 6 cigarettes we get 6 cigarette butts.
and we can make
1 cigar of these 6 cigarette butts.
so totally
7 cigarettes.
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yep you are right princess.😀
and 43rd remains unanswered...
come on it is not that tough.
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ok
43Q
x =180
let x be equal amounts of fruits with perosn A , B
the final equation is
4(x+20)/3 = 5(x20)/3
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no durga you have made a small error in your final equation check it out 😀
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the ans is x=100
let x be equal no: of sweets for A and B
A gains 20 from B so: A: x+20 and B: x20
A loses 2/3 of his sweets that means B gains 2/3 sweets of A's:
hence A=(x+20)2/3(x+20) and B=(x20)+2/3(x+20)
finally B has 4times of A's sweets
so (x20)+2/3(x+20)=4[(x20)2/3(x+20)]
solving it we get x=100
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yeah right shamala 👍
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thanq sir😀
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i am not a sir 😀
you just call me cooltwins 😛
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ok cooltwins😀
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1) In a row of boys A is 15th from the left and B is 4th from the right.there are three boys between A and B. C is the left of A.What is c's position from right
solution is:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
C A X Y Z B
hence it is clear from the above there are total 22 boys and 22'nd boy is right most so we find from there c is at the 9'th position from the right
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2)A,B,C,D are 4 friends who do not mind exchanging items. A had 2 chessboards each costing Rs. 500 and a record player. C originally had a cycle and a walk man. each cricket bat costs Rs.700. Both D,C got a cricket bat from B. A gave his record player costing Rs.2000 to B.C got a camera costing Rs.1500 from D.The cycle costs Rs. 1000 and the Walkman costs Rs.700.B had 3 cricket bats initially.D had 2 cameras total cost of which is Rs.5000. A gave one of his chess boards to C and took C's cycle.C gave his walkman to D. (2006 MBA)
2.1)Who did not have a cricket bat at the end?
(a)A, (b)B, (c)C, (d)D
2.2)Total cost of materials C had in the beginning?
(a)Rs.5000,(b)Rs.3000,(c)Rs.2100,(d)Rs.1700
2.3)who incurred the maximum loss in the transaction?
(a)D (b)A (c)C (d)B
2.4)who made profit after the transactions..?
(a)A,B (b)A,D (c)B,C (d)C,D
2.5)After the transaction, who had items total cost of Rs. 1500?
(a)A (b)B (c)C (d)D
solution:
solution will be:First i would like to give the explanation of solution
A had items:2 chessboard cost of each is Rs.500 & 1 record player of cost Rs. 2000
so A had in beginning items of total cost of Rs.=3000
after transaction he had only only 1 cycle of cost Rs.=1000 & 1 chessboard of his own
loss in transaction =1500
B had items:3 cricket bat each of rs.700
so B had in beginning items of total cost of rs.=2100
after transaction he had only 1 record player of cost Rs.=2000 & 1 bat of his own
profit in transaction =600
C had items:1 cycle cost of rs.1000 & 1walkman of cost rs.700
so C had in beginning items of total cost of rs.=1700
after transaction he had only 1 bat of cost Rs.=700 & 1 chessboard of cost=500 and 1 camera=1500
profit in transaction =2700
D had items:2 camera cost of one is Rs 1500 & other one of cost Rs. 3500
so A had in beginning items of total cost of Rs.=5000
after transaction he had only only 1batof cost Rs.=700 & 1 camera of his own of cast Rs.=3500 & a walkman of Rs. 700
loss in transaction =100
1. A[ A did not have the bat at the end]
2. 1700 [coat of materials c had in the beginning]
3. A [A had the maximum loss of Rs. 1500 after the transaction]
4. B & C made the profit after transaction
5. A [A had a chessboard and a cycle]
I hope this will be the right way of explanation
if not then suggest me what else should be and should not be there....
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22) what next...?
(1,2) (5,10) (15,30) (37,74) ...............
(a) (80,160) (b) (82,164) (c) (83,166) (d) (84,168)
solution to this:
51=>4x2+2=10
155=>10x2+10=30
3715=>22x2+30=74
8337=>46x2+74=166
therefore the answer will be
c)(83,166)
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33)Can you fiind the tenth number in this series?
3, 3, 5, 4, 4, 3, 5, 5, 4, ?
solution is : the series is like that
first come two 3
then one 5
then two 4
one 3
two 5
one 4
so next will two 3
so the next digit will be 3 in the series
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2)A,B,C,D are 4 friends who do not mind exchanging items. A had 2 chessboards each costing Rs. 500 and a record player. C originally had a cycle and a walk man. each cricket bat costs Rs.700. Both D,C got a cricket bat from B. A gave his record player costing Rs.2000 to B.C got a camera costing Rs.1500 from D.The cycle costs Rs. 1000 and the Walkman costs Rs.700.B had 3 cricket bats initially.D had 2 cameras total cost of which is Rs.5000. A gave one of his chess boards to C and took C's cycle.C gave his walkman to D. (2006 MBA)
2.1)Who did not have a cricket bat at the end?
(a)A, (b)B, (c)C, (d)D
2.2)Total cost of materials C had in the beginning?
(a)Rs.5000,(b)Rs.3000,(c)Rs.2100,(d)Rs.1700
2.3)who incurred the maximum loss in the transaction?
(a)D (b)A (c)C (d)B
2.4)who made profit after the transactions..?
(a)A,B (b)A,D (c)B,C (d)C,D
2.5)After the transaction, who had items total cost of Rs. 1500?
(a)A (b)B (c)C (d)D
solution:
solution will be:First i would like to give the explanation of solution
A had items:2 chessboard cost of each is Rs.500 & 1 record player of cost Rs. 2000
so A had in beginning items of total cost of Rs.=3000
after transaction he had only only 1 cycle of cost Rs.=1000 & 1 chessboard of his own
loss in transaction =1500
B had items:3 cricket bat each of rs.700
so B had in beginning items of total cost of rs.=2100
after transaction he had only 1 record player of cost Rs.=2000 & 1 bat of his own
profit in transaction =600
C had items:1 cycle cost of rs.1000 & 1walkman of cost rs.700
so C had in beginning items of total cost of rs.=1700
after transaction he had only 1 bat of cost Rs.=700 & 1 chessboard of cost=500 and 1 camera=1500
profit in transaction =2700
D had items:2 camera cost of one is Rs 1500 & other one of cost Rs. 3500
so A had in beginning items of total cost of Rs.=5000
after transaction he had only only 1batof cost Rs.=700 & 1 camera of his own of cast Rs.=3500 & a walkman of Rs. 700
loss in transaction =100
1. A[ A did not have the bat at the end]
2. 1700 [coat of materials c had in the beginning]
3. A [A had the maximum loss of Rs. 1500 after the transaction]
4. B & C made the profit after transaction
5. A [A had a chessboard and a cycle]
I hope this will be the right way of explanation
if not then suggest me what else should be and should not be there....
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36)There is a pole in a lake.Onehalf of the pole is in the ground, another onethird of it is covered by water, & 8 ft is out of the water.
Then,What is the total length of the pole in ft?
solution : let the total length of the pole is x feet
x[x/2+x/6]=8
6x4x=48
x=24 feet
therefore total length of the pole will be 24 feet
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yeah right shreya
sorry for the delayed reply
i was so busy with my college stuff + some extra curricular stuff too.
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45 )A long wire, 16 meters in length, hangs between two poles that are both 15 meters high.The ends of the wire are attached to the tops of the poles.At its lowest point, the wire hangs 7 meters above the ground.Then how far the two poles apart ?
TIP: Do not get too technical just think logically 👍
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46)There are 3 people A,B,C.A lent cars to B and C as many as they had already.After some time B gave as many cars to A & C as many as they have.
After sometime C did the same thing.At the end of this transaction each one of them had 24.Then,find the cars each originally had ?
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cooltwins
46)There are 3 people A,B,C.A lent cars to B and C as many as they had already.After some time B gave as many cars to A & C as many as they have.
After sometime C did the same thing.At the end of this transaction each one of them had 24.Then,find the cars each originally had ?
A = 39 cars
B = 21 cars
C =12 cars
....hope this is right?😒
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whiz.kid.aniket
A = 39 cars
B = 21 cars
C =12 cars
....hope this is right?😒
yeah right whiz kid 👍
what about the 45th question ?
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cooltwins
45 )A long wire, 16 meters in length, hangs between two poles that are both 15 meters high.The ends of the wire are attached to the tops of the poles.At its lowest point, the wire hangs 7 meters above the ground.Then how far the two poles apart ?
TIP: Do not get too technical just think logically 👍
the poles stand next to each other. it means that the cable goes 8 meters straight down and 8 meters straight up.
the ans should be zero metres!!
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whiz.kid.aniket
the poles stand next to each other. it means that the cable goes 8 meters straight down and 8 meters straight up.
the ans should be zero metres!!
yes you are right whiz.kid.aniket 👍
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47)Using the mathematical symbols (,+,,*,/,) can you make following equation become true.
9 8 7 6 5 4 3 2 1 = 2021
Note: Don't combine the numbers. For example 987+65....
you should use all the numbers and the symbols.
the numbers can used only once in the same order and the symbols can be used any number of times
so start thinking 😁
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s1512
Member •
Apr 9, 2010
is it 9 am i rgt
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s1512
is it 9 am i rgt
sorry but which question's answer is this.😀
please specify the question number to answer.😁
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sherya mathur
36)There is a pole in a lake.Onehalf of the pole is in the ground, another onethird of it is covered by water, & 8 ft is out of the water.
Then,What is the total length of the pole in ft?
solution : let the total length of the pole is x feet
x[x/2+x/6]=8
6x4x=48
x=24 feet
therefore total length of the pole will be 24 feet
the correct answer is 48 I think..
x/2 + x/3 + 8 = x
5x+48 = 6x
x = 48
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it will be at 9th
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cooltwins
47)Using the mathematical symbols (,+,,*,/,) can you make following equation become true.
9 8 7 6 5 4 3 2 1 = 2021
Note: Don't combine the numbers. For example 987+65....
you should use all the numbers and the symbols.
the numbers can used only once in the same order and the symbols can be used any number of times
so start thinking 😁
what's up people...:?:
no answer for this question 😔
ok. i'm giving some clues. form the equation using
* 4 times,
+ 3 times,
/ 1 time,
( 1 time,
) 1 time,
 0 time.
now any one ready to answer :hehehe:
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hello CEans,
after a long gap, the cooltwins aptitude centre is back in action. 😁
sorry for the long gap... i'm back with a fresh set of questions 😁
48) if i bought a book having 1156 pages, and tear of 4 pages in random and add up their page numbers, what is the probability that the sum of the page numbers from the torn pages will be 87:?:
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49) vikram was attending a maths class. his teacher asked him to take a seven digit number and add all the seven digits. then he asks them to subtract the sum of digits from the seven digit number. he asks them to write the answer down in the paper. vikram was not attentive and he missed one of the digits. he gave the rest six digits : 3,4,0,1,4,9 (the digits are also not in order 😉)
is possible for you to find the missing digit:?:
it's not too complicated. just work on the basic subtraction 😀
think think 😀
P.S.: the 47th question still remains unanswered😀
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In Q48 the pages torn are consecutive?
In q49 is it nine/seven digit no.?
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vik001ind
In Q48 the pages torn are consecutive?
In q49 is it nine/seven digit no.?
the pages are torn at random. no order. but it may be consecutive also 😉
sorry for the confusion in q49... it is a seven digit number
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Q48
let the page no. be
x,x+1
y,y+1
z,z+1
t,t+1
(hint: removing a page removes its backside too)
adding all
2(x+y+z+t) +4 = 87
2(x+y+z+t) = 83 > a contradiction
therefore answer is zero probability.
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yes vik 001 you are absolutely right..... 👍
what about the other question? any luck........?
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I can't find any way to proceed in last question, 47th sounds too length!
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48) if i bought a book having 1156 pages, and tear of 4 pages in random and add up their page numbers, what is the probability that the sum of the page numbers from the torn pages will be 87:?:
the answer is zero.
because adding 4 odds and 4 evens (page nos. of the 4 pages) will give even... so no chance of it being 87(odd)..
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hey guys whats up?
no takers for the last question?
its easy ......
anyway here goes the next question....
50) What is the last digit of S, if S = 1^101 + 2^101 + 3^101 + … + 101^101?
OPTIONS
1)1 2)3 3)5 4)7 5)9
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I think its 1!
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you are right vik 001...... 👍
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cooltwins
49) vikram was attending a maths class. his teacher asked him to take a seven digit number and add all the seven digits. then he asks them to subtract the sum of digits from the seven digit number. he asks them to write the answer down in the paper. vikram was not attentive and he missed one of the digits. he gave the rest six digits : 3,4,0,1,4,9 (the digits are also not in order 😉)
is possible for you to find the missing digit:?:
i found the answer 😁
the answer is
6
reason:
let us consider a number abc.
it can be written as 100a+10b+c.
the sum of it's digits is a+b+c.
when we subtract the sum from the number we get : (100a+10b+c)(a+b+c) => 99a+9b ..... i.e. a multiple of 9.
this can be applied to any number of digits...
so the sum of digits obtained after subtracting the sum from number should be a multiple of 9.
therefore 3+4+0+1+4+9+x should be a multiple of nine.......=> x=6
am i right:?:
i did one sum in similar lines some time back 😀
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1378 for question 3? Am i correct?
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yeah you are right 👍
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hey guys i know there has been no activity in this thread of late.
its just that i do not find time. but here goes the next question:
51) i have three numbers in arithmetic progression. when i multiply them i get a prime number. can you find out the numbers?
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cooltwins
51) i have three numbers in arithmetic progression. when i multiply them i get a prime number. can you find out the numbers?
is it 0,1,2 ??
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no ,when you multiply them you get zero and zero is not considered as a prime 😀
prime numbers start only from 2
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oops *bangs head on keyboard for being so stupid*
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no you were not that stupid 😉 😁
even my sis did the same mistake. do try. its easy. 😀
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 3 , 1 and 1
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absolutely right ES 😀
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moar! 😁 😁
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