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@pratap singh, upendra • 08 Oct, 2013
hi,
When we compute the pinch off voltage for an n channel JFET, we always do it by keeping Vgs = 0 and then the value of Vds for which the channel conductivity ceases is noted. Now when we try to find out the cut-off voltage Vgs(off) it is the gate source voltage for which the channel ceases its conduction. My question is do we keep Vds = 0 during the calculation of cut-off voltage.
When we compute the pinch off voltage for an n channel JFET, we always do it by keeping Vgs = 0 and then the value of Vds for which the channel conductivity ceases is noted. Now when we try to find out the cut-off voltage Vgs(off) it is the gate source voltage for which the channel ceases its conduction. My question is do we keep Vds = 0 during the calculation of cut-off voltage.
@Jeffrey Arulraj • 10 Oct, 2013
Your first statement is not correct
It may not be zero at any time.
This will make the next part easier for
You just need to keep a constant Vds through out the test to calculate the Vgs at which you have the needed solution
Here we keep a constant Vgs through out the testing process without changing itproffyWhen we compute the pinch off voltage for an n channel JFET, we always do it by keeping Vgs = 0 and then the value of Vds for which the channel conductivity ceases is noted.
It may not be zero at any time.
This will make the next part easier for
You just need to keep a constant Vds through out the test to calculate the Vgs at which you have the needed solution
1.8k views
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