A simple C problem.....

Pensu · 2011-08-09T05:52:02+00:00

Hey ppl, I have a problem related to a C program. #include<stdio.h> #include<conio.h> int sum(int a,int b) { int c=a+b; } int main() { int a=5,b=2; printf("%d",sum(a,b)); getch(); return 0; } Now, surprisingly the output is 7. I am not returning anything from the function. It should return garbage value. But how am i getting the correct output????

A simple C problem.....

Pensu

Member

Updated: Oct 25, 2024

Views: 1.3K
Hey ppl,

I have a problem related to a C program.
```
#include<stdio.h>
#include<conio.h>


 int sum(int a,int b)
 {
    int c=a+b;
 }




 int main()
  {
    int a=5,b=2;
    printf("%d",sum(a,b));
    getch();
    return 0;
  }
```
Now, surprisingly the output is 7. I am not returning anything from the function. It should return garbage value. But how am i getting the correct output????
0

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Reya

Member • Aug 9, 2011

If i run the program using online compiler it returns the output as 0.Whereas in devcpp it returns 7.

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Pensu

Member • Aug 9, 2011

@praveena: exactly my point....how it can print 7 while i am not returning anything.

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Bharath51

Member • Aug 13, 2011

i think....it defaultly return last operation performed by the compiler......
i tried this....
as
a+b;
a-b;
a*b;
a/b;

the last statement "a/b" returned to the function......so the c compiler default return some thing......that is last operation performed.....

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gaurav.bhorkar

Member • Aug 15, 2011

This may also be because of compiler optimization. Did you get a warning?

PS: I didn't compile your code

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ayusha patnaik

Member • Aug 15, 2011

i think its by default since u r using it for a single tym...if u use multiple operations thn the correct output would be avilable fr a single operation...means it is set as a default .

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