05 May 2008

# Use four 0's & any mathematical operators to get 24

For those who don't have to do anything better -

Use four 0's (zeros) and any mathematical operators to get 24.

Those who are smart, don't spoil the fun soon. Others, give it a try.

raj87verma88

Branch Unspecified
10 years ago
Rather difficult
But let me give it a shot

cos-1 (inverse) 0 = 90
√90 = 9.5
and 3√90 = 4.5
√cos (inverse) 0 + √cos (inverse) 0 + √cos (inverse) 0 -3√cos (inverse) 0
= √90 + √90 + √90 - 3√90
= 9.48 +9.48 + 9.48 – 4.48
= 28.44 – 4.48
= 23.9

after taking square root and cube root if we approximate

that is

9.5 + 9.5 + 9.5 – 4.5

raj87verma88

Branch Unspecified
10 years ago
Also instead of cube root of 90 we can do
ln90 = 4.49
10 years ago
Hint -

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉

devesh

Branch Unspecified
10 years ago
do we only have to use 0's?
I mean nothing else(no other numerics),only operators and zeroes!!!
10 years ago
Yes, that's right. Only four zeros! (and of course, mathematical operators).

Is it really 'that' difficult?

gohm

Branch Unspecified
10 years ago
Are we allowed to rotate the operators?

gohm

Branch Unspecified
10 years ago
Nope, it is never equal to 1. Only 1 is equal to 1. In most practical uses it is close enough mathematically to round the .99999 to 1 however it is never actually equal to 1.

The_Big_K
Hint -

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉
10 years ago
1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)
10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉

gohm

Branch Unspecified
10 years ago
Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

The_Big_K
1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)
10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉
10 years ago
gohm
Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

Umm, okay, here we go -

x = 0.99999...(infinite times) - Equation (A)
10x = 9.9999....... - Equation (B)

Equation (B) minus (A)

=> 9x = 9

=> x = 1

👍

mahul

Branch Unspecified
10 years ago
Four zeroes to score 24, that's easy-->>

(0!+0!+0!+0!)!=24

i hope that would do, unless _k has a problem with my repeated use of factorials 😀
10 years ago
mahul
Four zeroes to score 24, that's easy-->>

(0!+0!+0!+0!)!=24

i hope that would do, unless _k has a problem with my repeated use of factorials 😀
Hah, no problem with factorials! That's the right way to get 24. Pretty easy, eh? 😀