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# Use four 0's & any mathematical operators to get 24

For those who don't have to do anything better -

Use four 0's (zeros) and any mathematical operators to get 24.

Those who are smart, don't spoil the fun soon. Others, give it a try.

Use four 0's (zeros) and any mathematical operators to get 24.

Those who are smart, don't spoil the fun soon. Others, give it a try.

Rather difficult

But let me give it a shot

cos-1 (inverse) 0 = 90

√90 = 9.5

and 3√90 = 4.5

√cos (inverse) 0 + √cos (inverse) 0 + √cos (inverse) 0 -3√cos (inverse) 0

= √90 + √90 + √90 - 3√90

= 9.48 +9.48 + 9.48 – 4.48

= 28.44 – 4.48

= 23.9

after taking square root and cube root if we approximate

that is

9.5 + 9.5 + 9.5 – 4.5

then answer is exactly 24

How about it Biggie

But let me give it a shot

cos-1 (inverse) 0 = 90

√90 = 9.5

and 3√90 = 4.5

√cos (inverse) 0 + √cos (inverse) 0 + √cos (inverse) 0 -3√cos (inverse) 0

= √90 + √90 + √90 - 3√90

= 9.48 +9.48 + 9.48 – 4.48

= 28.44 – 4.48

= 23.9

after taking square root and cube root if we approximate

that is

9.5 + 9.5 + 9.5 – 4.5

then answer is exactly 24

How about it Biggie

Also instead of cube root of 90 we can do

ln90 = 4.49

ln90 = 4.49

Hint -

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉

do we only have to use 0's?

I mean nothing else(no other numerics),only operators and zeroes!!!

I mean nothing else(no other numerics),only operators and zeroes!!!

Yes, that's right. Only four zeros! (and of course, mathematical operators).

Is it really 'that' difficult?

Is it really 'that' difficult?

Are we allowed to rotate the operators?

Nope, it is never equal to 1. Only 1 is equal to 1. In most practical uses it is close enough mathematically to round the .99999 to 1 however it is never actually equal to 1.

The_Big_KHint -

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉

1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)

10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)

10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉

Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

The_Big_K1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)

10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉

gohmHere is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

Umm, okay, here we go -

x = 0.99999...(infinite times) - Equation (A)

10x = 9.9999....... - Equation (B)

Equation (B) minus (A)

=> 9x = 9

=> x = 1

👍

Four zeroes to score 24, that's easy-->>

(0!+0!+0!+0!)!=24

i hope that would do, unless _k has a problem with my repeated use of factorials 😀

(0!+0!+0!+0!)!=24

i hope that would do, unless _k has a problem with my repeated use of factorials 😀

Hah, no problem with factorials! That's the right way to get 24. Pretty easy, eh? 😀mahulFour zeroes to score 24, that's easy-->>

(0!+0!+0!+0!)!=24

i hope that would do, unless _k has a problem with my repeated use of factorials 😀