Use four 0's & any mathematical operators to get 24

Replies

• 

  raj87verma88

  Rather difficult
  But let me give it a shot
  
  cos-1 (inverse) 0 = 90
  √90 = 9.5
  and 3√90 = 4.5
  √cos (inverse) 0 + √cos (inverse) 0 + √cos (inverse) 0 -3√cos (inverse) 0
  = √90 + √90 + √90 - 3√90
  = 9.48 +9.48 + 9.48 – 4.48
  = 28.44 – 4.48
  = 23.9
  
  after taking square root and cube root if we approximate
  
  that is
  
  9.5 + 9.5 + 9.5 – 4.5
  then answer is exactly 24
  
  How about it Biggie
• 

  raj87verma88

  Also instead of cube root of 90 we can do
  ln90 = 4.49
• 

  Kaustubh Katdare

  Hint -
  
  K.I.S.S 😁
  
  ...and since when did we start relying on 'approximate' values?
  
  On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?
  
  If yes, how? If not, why? 😉
• 

  devesh

  do we only have to use 0's?
  I mean nothing else(no other numerics),only operators and zeroes!!!
• 

  Kaustubh Katdare

  Yes, that's right. Only four zeros! (and of course, mathematical operators).
  
  Is it really 'that' difficult?
• 

  gohm

  Are we allowed to rotate the operators?
• 

  gohm

  Nope, it is never equal to 1. Only 1 is equal to 1. In most practical uses it is close enough mathematically to round the .99999 to 1 however it is never actually equal to 1.
  
  

  The_Big_K

  Hint -
  
  K.I.S.S 😁
  
  ...and since when did we start relying on 'approximate' values?
  
  On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?
  
  If yes, how? If not, why? 😉

• 

  Kaustubh Katdare

  1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!
  
  2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -
  
  x = 0.99999...(infinite times)
  10x = 9.9999.......
  
  => 9x = 9
  
  => x = 1
  
  😁
  
  What say? 😉
• 

  gohm

  Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?
  
  

  The_Big_K

  1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!
  
  2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -
  
  x = 0.99999...(infinite times)
  10x = 9.9999.......
  
  => 9x = 9
  
  => x = 1
  
  😁
  
  What say? 😉

• 

  Kaustubh Katdare

  gohm

  Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

  
  Umm, okay, here we go -
  
  x = 0.99999...(infinite times) - Equation (A)
  10x = 9.9999....... - Equation (B)
  
  Equation (B) minus (A)
  
  => 9x = 9
  
  => x = 1
  
  👍
• 

  mahul

  Four zeroes to score 24, that's easy-->>
  
  (0!+0!+0!+0!)!=24
  
  i hope that would do, unless _k has a problem with my repeated use of factorials 😀
• 

  Kaustubh Katdare

  mahul

  Four zeroes to score 24, that's easy-->>
  
  (0!+0!+0!+0!)!=24
  
  i hope that would do, unless _k has a problem with my repeated use of factorials 😀

  Hah, no problem with factorials! That's the right way to get 24. Pretty easy, eh? 😀