Use four 0's & any mathematical operators to get 24
For those who don't have to do anything better 
Use four 0's (zeros) and any mathematical operators to get 24.
Those who are smart, don't spoil the fun soon. Others, give it a try.
Use four 0's (zeros) and any mathematical operators to get 24.
Those who are smart, don't spoil the fun soon. Others, give it a try.
Replies

raj87verma88Rather difficult
But let me give it a shot
cos1 (inverse) 0 = 90
√90 = 9.5
and 3√90 = 4.5
√cos (inverse) 0 + √cos (inverse) 0 + √cos (inverse) 0 3√cos (inverse) 0
= √90 + √90 + √90  3√90
= 9.48 +9.48 + 9.48 – 4.48
= 28.44 – 4.48
= 23.9
after taking square root and cube root if we approximate
that is
9.5 + 9.5 + 9.5 – 4.5
then answer is exactly 24
How about it Biggie 
raj87verma88Also instead of cube root of 90 we can do
ln90 = 4.49 
Kaustubh KatdareHint 
K.I.S.S 😁
...and since when did we start relying on 'approximate' values?
On the same lines, I've another question > is 0.999999...(infinite times) equal to 1 ?
If yes, how? If not, why? 😉 
deveshdo we only have to use 0's?
I mean nothing else(no other numerics),only operators and zeroes!!! 
Kaustubh KatdareYes, that's right. Only four zeros! (and of course, mathematical operators).
Is it really 'that' difficult? 
gohmAre we allowed to rotate the operators?

gohmNope, it is never equal to 1. Only 1 is equal to 1. In most practical uses it is close enough mathematically to round the .99999 to 1 however it is never actually equal to 1.
The_Big_KHint 
K.I.S.S 😁
...and since when did we start relying on 'approximate' values?
On the same lines, I've another question > is 0.999999...(infinite times) equal to 1 ?
If yes, how? If not, why? 😉 
Kaustubh Katdare1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!
2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? 
x = 0.99999...(infinite times)
10x = 9.9999.......
=> 9x = 9
=> x = 1
😁
What say? 😉 
gohmHere is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?
The_Big_K1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!
2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? 
x = 0.99999...(infinite times)
10x = 9.9999.......
=> 9x = 9
=> x = 1
😁
What say? 😉 
Kaustubh KatdaregohmHere is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?
Umm, okay, here we go 
x = 0.99999...(infinite times)  Equation (A)
10x = 9.9999.......  Equation (B)
Equation (B) minus (A)
=> 9x = 9
=> x = 1
👍 
mahulFour zeroes to score 24, that's easy>>
(0!+0!+0!+0!)!=24
i hope that would do, unless _k has a problem with my repeated use of factorials 😀 
Kaustubh Katdare
Hah, no problem with factorials! That's the right way to get 24. Pretty easy, eh? 😀mahulFour zeroes to score 24, that's easy>>
(0!+0!+0!+0!)!=24
i hope that would do, unless _k has a problem with my repeated use of factorials 😀
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