• Kaustubh

MemberMay 1, 2008

## Use four 0's & any mathematical operators to get 24

For those who don't have to do anything better -

Use four 0's (zeros) and any mathematical operators to get 24.

Those who are smart, don't spoil the fun soon. Others, give it a try.

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Replies
• MemberMay 2, 2008

Rather difficult
But let me give it a shot

cos-1 (inverse) 0 = 90
√90 = 9.5
and 3√90 = 4.5
√cos (inverse) 0 + √cos (inverse) 0 + √cos (inverse) 0 -3√cos (inverse) 0
= √90 + √90 + √90 - 3√90
= 9.48 +9.48 + 9.48 – 4.48
= 28.44 – 4.48
= 23.9

after taking square root and cube root if we approximate

that is

9.5 + 9.5 + 9.5 – 4.5

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• MemberMay 2, 2008

Also instead of cube root of 90 we can do
ln90 = 4.49
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Hint -

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉
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• MemberMay 4, 2008

do we only have to use 0's?
I mean nothing else(no other numerics),only operators and zeroes!!!
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Yes, that's right. Only four zeros! (and of course, mathematical operators).

Is it really 'that' difficult?
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• MemberMay 4, 2008

Are we allowed to rotate the operators?
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• MemberMay 4, 2008

Nope, it is never equal to 1. Only 1 is equal to 1. In most practical uses it is close enough mathematically to round the .99999 to 1 however it is never actually equal to 1.

The_Big_K
Hint -

K.I.S.S 😁

...and since when did we start relying on 'approximate' values?

On the same lines, I've another question -> is 0.999999...(infinite times) equal to 1 ?

If yes, how? If not, why? 😉
Are you sure? This action cannot be undone.

1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)
10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉
Are you sure? This action cannot be undone.
• MemberMay 4, 2008

Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

The_Big_K
1. No, you cannot 'rotate' operators. Come on, its just basic mathematics!

2. If 0.99999...(infinite) is not equal to one, what's wrong with the following? -

x = 0.99999...(infinite times)
10x = 9.9999.......

=> 9x = 9

=> x = 1

😁

What say? 😉
Are you sure? This action cannot be undone.

gohm
Here is your problem, the tricky business between the 10x=9.999999... and then 9x=9. Did you change the value of x?

Umm, okay, here we go -

x = 0.99999...(infinite times) - Equation (A)
10x = 9.9999....... - Equation (B)

Equation (B) minus (A)

=> 9x = 9

=> x = 1

👍
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• MemberMay 4, 2008

Four zeroes to score 24, that's easy-->>

(0!+0!+0!+0!)!=24

i hope that would do, unless _k has a problem with my repeated use of factorials 😀
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