Try The 'C' Code !

Replies

• 

  sristi

  1)
  int i, n = 20;
  for (i = 0; i < n; i++)
  {
  printf("X");
  }
  
  
  2)int i,n=20;
  for(i=0;i++ {
  print("X");
  }
  
  
  3)
  int i, n = 20;
  for (i = 0; ++i < =n; )
  {
  printf("X");
  }
• 

  Kaustubh Katdare

  That was a nice attempt
  
  But you missed this -
  
  

  By only changing or adding ONLY ONE character to the above code:

  😉
  
  -The Big K-
• 

  Jerry

  working on it
  
  

  sristi

  1)
  int i, n = 20;
  for (i = 0; i < n; i++)
  {
  printf("X");
  }

  yeh, you changed -- to ++ , that is you changed two characters. However you are allowed to change only one chracter from the code. Really interesting, I'm working on it !😉
• 

  crook

  I'm not a C programmer but this is more of a logic problem. Should not take more time. Let me see what can I do about it.
  
  crook
• 

  Kaustubh Katdare

  probably I should start giving out hints!
  
  Cummont fellaz, do you really need them?
  
  -The Big K-
• 

  crook

  got it
  
  i think i got it.
  
  in the original code, make the following change
  
  for (i = 0; i < n; n--)
  
  it should work! now trying the remaining two methods 😁
• 

  crook

  here comes the second way - 😁
  
  

  int i, n = 20;
  for (i = 0; -i < n; i--)
  {
  printf("X");
  }

  and the third 😁
  
  

  int i, n = 20;
  for (i = 0; i + n; i--)
  {
  printf("X");
  }

• 

  crook

  New Challenge !
  
  This is a simple C puzzle for you -
  
  "Write a "Hello World" program in 'C' without using a semicolon."
  
  Try it, its very simple.
  
  CrooK
  
• 

  Jerry

  int i, n = 20;
  for (i = 0; -i < n; i--)
  {
  printf("X");
  }
  
  will this work? 😒
  
  I don't have a compiler to try this out. I have started working on crook's problem. Its been quite sometime since I letf coding 😔
• 

  pradypop

  main(){if(printf("Hello world")){}}
  
  This might print hello world. No semi-colons used.
• 

  crook

  yes, thats a correct solution! 😀
• 

  rajeshkumar.km

  my guesss
  
  😉
  int i, n = -20;
  for (i = 0; i < n; i--)
  {
  printf("X");
  }
  
  i think the above change ( minus sign before 20 in the line 'int i,n=20')will respond to your view correctly
• 

  crook

  rajeshkumar.km

  😉
  int i, n = -20;
  for (i = 0; i < n; i--)
  {
  printf("X");
  }
  
  i think the above change ( minus sign before 20 in the line 'int i,n=20')will respond to your view correctly

  😕 I'm afraid the logic won't work.
  
  Croook
• 

  devi prasad

  ans:
  
  first method:
  
  int i, n = -20;
  for (i = 0; i < n; i--)
  {
  printf("X");
  }
  
  
  second method :
  
  
  int i, n = 20;
  for (i = 0; i < -n; i--)
  {
  printf("X");
  }
  
  
  third method:
  
  
  int i, n = 20;
  for (i = 20; i < n; i--)
  {
  printf("X");
  }
  
  
  😁
• 

  Mahesh

  third method:
  
  
  int i, n = 20;
  for (i = 20; i < n; i--)
  {
  printf("X");
  }
  
  
  
  How can this work? This is an infinite loop.
• 

  Kaustubh Katdare

  Mahesh

  third method:
  
  
  int i, n = 20;
  for (i = 20; i < n; i--)
  {
  printf("X");
  }
  
  
  
  How can this work? This is an infinite loop.

   for (i = 20; i < n; i--)

  Good Catch, Mahesh 😀 . Devi Prasad might want to fix it.
  
  -The Big K-
• 

  bantini

  how about (i=0;i
• 

  pradypop

  Mahesh

  third method:
  
  
  int i, n = 20;
  for (i = 20; i < n; i--)
  {
  printf("X");
  }
  
  
  
  How can this work? This is an infinite loop.

  I don't think there's an infinite loop in the code. Infact, statements inside loop are not executed even once.
  
  n=20, i=20 at initilization and condition is i
• 

  Mahesh

  Still the program is wrong.Can you give correct solution?
• 

  pradeep_agrawal

  /* 1st Way: Change i in i-- by n*/
  int i, n = 20;
  for (i = 0; i < n; n--)
  {
  printf("X");
  }
  
  
  /* 2nd Way: Add - before i in i < n */
  int i, n = 20;
  for (i = 0; -i < n; i--)
  {
  printf("X");
  }
  
  
  /* 3rd Way: Change < in i < n by + */
  int i, n = 20;
  for (i = 0; i + n; i--)
  {
  printf("X");
  }
• 

  Prasad Ajinkya

  This is decent enough, hope the 3 ways are as follows -
  
  int i, n = 20;
  for (i = 0; i < -n; i--)
  {
  printf("X");
  }
  
  
  int i, n = 20;
  for (i = 40; i < n; i--)
  {
  printf("X");
  }
  
  int i, n = 20;
  for (i = 0; i > n; i--)
  {
  printf("X");
  }
  
  I have indicated in red the change in character that I have made.
• 

  ksrbhanu

  Hi friends,
  
  I have one method, i will try other two. mean while review this method
  
  int i, n = 20;
  for (i = 0; i < n; n--)
  {
  printf("X");
  }
  
  replacing the i in the decrement statement with n it works , this is one character change 😎
• 

  ksrbhanu

  sory guys, i have n't checked the whole chain , pradeep has already posted this metho 😔
• 

  spirit

  hello.....i m giving your answer n u have to tell thats right or not.....😎
  this is your code........
  int i, n = 20;
  for (i = 0; i < n; i--)
  {
  printf("X");
  }
  1. instead of i-- in the loop,change it as n--.
  2.in initialisation,n=20,change it as:n=-20.
  3.instead of i--,use:i++.
  
  😁
• 

  rahul dev choud

  hey its really interesting don't tell da ans...
  
  working on it ....
  
  w'll back soon......