Solve this problem

Replies

• 

  Kaustubh Katdare

  Re: Mechanical engineering: Solve this problem
  
  @Geonana: Todd runs a funny video blog. I'm moving your question to appropriate section.
• 

  CIVILPRINCESS

  geonana

  Hi, Todd, hope this question qualifies, as I have no clue how to solve it
  
  I've provided you a drawing to the right to assist you in coming up with the answers. You need the following information to solve for the Northerly (R1) and Westerly (R2) ....
  
  Point Load (P) = 167.4571
  Length (L) between (R1) and (R2) is 1000
  Length (b) between (P) and (R2) is 319.442
  
  And that's all you should need to know to solve for (R1) and (R2).

  I think i have the solution to your problem...
  
  algebric sum of vertical forces=0
  i.e. R1+R2=167.4571----(1)
  
  The moment about any point in the beam is =0
  lets take the moment about the point where R2 acts
  R1x1000-167.4571x319.442=0
  =>R1=53.4928
  And substitute this in eq.(1)
  
  R1=53.4928
  R2=113.9643
  
• 

  geonana

  Ok, something is not quite right because the solution needs to be close to these coords: (within 3 km)N 53° 29.000 W 113° 58.000
• 

  heba66

  Hi geonana ,
  I think your problem is very big problem to you. Really this is a very big Mechanical Engineering problem. But don't be worried. You may find many experienced providers
  through
  
  Freelancer. com.
  
  So just visit here . There are thousands of providers are waiting for you to solve your difficult problems. Use this unique coupon word "NUTSANDBOLTS" to get some extra opportunity and first feedback.
  Have a nice time.
  Bye
• 

  CIVILPRINCESS

  geonana

  Ok, something is not quite right because the solution needs to be close to these coords: (within 3 km)N 53° 29.000 W 113° 58.000

  But why is the solution in degrees.😕
  if you apply degree to my solution you are getting the answer..
  i.e.When you convert to degree 53.4928=>53degree29minutes
  if you know the reason please let me know....:smile:
• 

  geonana

  THX, just needed to convert it...it's going to work! THX again 😀😁
• 

  Guttu

  CIVILPRINCESS

  But why is the solution in degrees.😕
  if you apply degree to my solution you are getting the answer..
  i.e.When you convert to degree 53.4928=>53degree29minutes
  if you know the reason please let me know....:smile:

  that person is geocaching puzzler. It's part of a puzzle.
• 

  mannucivil

  geonana

  Hi, Todd, hope this question qualifies, as I have no clue how to solve it
  
  I've provided you a drawing to the right to assist you in coming up with the answers. You need the following information to solve for the Northerly (R1) and Westerly (R2) ....
  
  Point Load (P) = 167.4571
  Length (L) between (R1) and (R2) is 1000
  Length (b) between (P) and (R2) is 319.442
  
  And that's all you should need to know to solve for (R1) and (R2).

  this is determinate beam ,solv it by using equilibrium condition
• 

  shubhrajeet tiwa

  let us apply newton equilibrium eq we have
  1)net force in y dir=0
  therefore
  r1+r2=p---(1)
  net moment about r1 =0
  i.e
  r2*1000=p*(1000-319.442)---(2)
  solve simultaneously get ans
  how ever to find difflection
  generate an poerator =0;{f(x)=0 or (-)eve}
  then bending moment eq is: r1*-p*----(3)
  now since
  d^sy/dx^2=eq(3)/(e*i);were e is young modulus and i is moment of inertia
  integrate twise will give you defliction having to constat of integration
  to find there value
  put y=0 at point r1 and r2
  were y is difliction