Simple math question, solve this.
A + B → A – B,
A – B → A × B,
A × B → A ÷ B and
A÷B → A+B
Find the value of (a ÷ b – c + d × e)?
1. a + bc - d/e
2. a - b/c + de
3. a + b/c + de
4. a - b/c - de
A – B → A × B,
A × B → A ÷ B and
A÷B → A+B
Find the value of (a ÷ b – c + d × e)?
1. a + bc - d/e
2. a - b/c + de
3. a + b/c + de
4. a - b/c - de
Replies
-
Mangesh6688The answer should be
1. a + bc - d/e
Am i right? -
Saandeep SreerambatlaMangesh6688The answer should be
1. a + bc - d/e
Am i right?
Yes I will also go with the same answer!!! -
Kaustubh KatdareExplanation, please 😀
-
Mangesh6688
The given equation is (a ÷ b – c + d × e)The_Big_KExplanation, please 😀
As per the given condition that A÷B → A+B, if we are dividing A and B then it will be replaced with addition of A and B.
(Here,A÷B tends to A+B but A+B do not tends to A÷B)
So, a÷b will be replaced with a+b,
b-c will be replaced with b×c
and so on.
Therefore, Option 1.a + bc - d/e should be correct.
Correct me if i am wrong.😕 -
CIVILPRINCESSi think the solution mangesh6688 gave is correct.
You are reading an archived discussion.
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