# Quantitative Aptitude 13

Question asked by Tejashree Katdare in #Coffee Room on Sep 17, 2010

Tejashree Katdare · Sep 17, 2010

Rank C2 - EXPERT

A person is standing on a staircase . He walks down 4 steps, up 3 steps, down 6 steps, up 2 steps, up 9 steps, and down 2 steps. Where is he standing in relation to the step on which he started?

A) 2 steps above

B) 1 steps above

C) the same place

D) 1 steps below

E) 4 steps above Posted in: #Coffee Room

A) 2 steps above

B) 1 steps above

C) the same place

D) 1 steps below

E) 4 steps above Posted in: #Coffee Room

Saandeep Sreerambatla · Sep 17, 2010

Rank A2 - PRO

Its 2 Steps above.

@Mona: Good going to keep this initiative active. Could you increase the difficulty level .

@Mona: Good going to keep this initiative active. Could you increase the difficulty level .

rishi0922 · Sep 17, 2010

Rank C1 - EXPERT

its soooo easy mona, so increase the toughness ......./

Chitti · Mar 21, 2011

Rank C1 - EXPERT

Increased difficulty level....

A and B are participating i a 1500 m race. A gives B a lead of 50 m and beats him by 10 m in a 500 m race. If B completes the 1500 m race in 44 minutes, then A finishes the race.....minutes before B.

1) 2 minutes

2) 12 minutes

3) 14 minutes

4) 20 minutes

A and B are participating i a 1500 m race. A gives B a lead of 50 m and beats him by 10 m in a 500 m race. If B completes the 1500 m race in 44 minutes, then A finishes the race.....minutes before B.

1) 2 minutes

2) 12 minutes

3) 14 minutes

4) 20 minutes

mathbyvemuri · May 4, 2012

Rank D2 - MASTER

"A gives B a lead of 50 m and beats him by 10 m in a 500 m race"

=> this means, in the same amount of time the distances travelled by A and B are as follows:

distance travelled by A = 500m

distance travelled by B = 450-10 = 440m

=> (Speed of A)/(Speed of B) = 500/440 = 50/44

As the speed and time are inversly proportional for the same amount od distance,

=> (Time taken by A)/(Time taken by B) = 44/50

=> (Time taken by A) = (44/50)(Time taken by B)

This relation holds good for any race, if the speeds of A and B are assuned constant.

"B completes the 1500 m race in 44 minutes"

=> A completes this in = (44/50)*44 = this comes approximately to be 39 minutes

A completes the race 44-39 =

=> this means, in the same amount of time the distances travelled by A and B are as follows:

distance travelled by A = 500m

distance travelled by B = 450-10 = 440m

=> (Speed of A)/(Speed of B) = 500/440 = 50/44

As the speed and time are inversly proportional for the same amount od distance,

=> (Time taken by A)/(Time taken by B) = 44/50

=> (Time taken by A) = (44/50)(Time taken by B)

This relation holds good for any race, if the speeds of A and B are assuned constant.

"B completes the 1500 m race in 44 minutes"

=> A completes this in = (44/50)*44 = this comes approximately to be 39 minutes

A completes the race 44-39 =

**5 minutes**before B**Answer is not available in the options**, pl check