Puzzle Busters Corner

Here comes one!

There is one word in english language that is always pronounced incorrectly.What is it?
😒

Re: Here comes one!

integratdbrainsThere is one word in english language that is always pronounced incorrectly.What is it?
😒

"Incorrectly" is often pronounced Incorrectly. :sleeping:

Correct? 😉

-The Big K-

The_Big_KLet's dedicate this place to Puzzle Busters! The CE Genius Team 8)

Note# Google / Yahoo / MSN is banned for the team here. Use only brainz , no internet! 😁

Here comes the first challenge -

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

-The Big K-

I had solve this puzzle when I was in college
people normally don't get answer for this puzzle because they tend to forget "( )" and "^" (power to) are part of the mathematical expressions 😀

Answer is (8 - 7 * 6) * (5 - 4 ^ 3) = 2006

Here is a new one for all CEians

Question: In the basement there are 3 light switches in the off position. Each switch controls 1 of 3 light bulbs on the floor above. You may move any of the switches, but you may only go up stairs one time. How can you determine which switch controls each light?

I guess it should be easy 😁

OK ! I know the answer to this from my engineering days ...
Many others may also know it. Anyway let me wait for people to try.

Clue : There is nothing extra ordinary in this puzzle. Just required some common sense.

😎

instruiteHere is a new one for all CEians

Question: In the basement there are 3 light switches in the off position. Each switch controls 1 of 3 light bulbs on the floor above. You may move any of the switches, but you may only go up stairs one time. How can you determine which switch controls each light?

I guess it should be easy 😁

I am posting the answer!

Turn on any switch and keep it 'ON' for some time. Switch it off. Now turn on another switch and rush to the floor above.

1. The bulb which is glowing corresponds to the switch which is presently 'ON'.
2. Touch the other two bulbs: The one which is warm(/hot) corresponds to the switch which was turned on initially.
3. The remaining bulb corresponds to the third (remaining) switch.

😁

Crook

crookI am posting the answer!

Turn on any switch and keep it 'ON' for some time. Switch it off. Now turn on another switch and rush to the floor above.

1. The bulb which is glowing corresponds to the switch which is presently 'ON'.
2. Touch the other two bulbs: The one which is warm(/hot) corresponds to the switch which was turned on initially.
3. The remaining bulb corresponds to the third (remaining) switch.

😁

Crook

that was a correct answer
any body posting a new puzzle?

The four people in this puzzle all competed in different classes of dog agility at a recent competition. The competitions all required the dogs to run over jumps, through tunnels and various other obstacles in as quicker time as possible. Each had a different result - one came first, one third, one fourth and one ninth. All four dogs were each of a different breed.

Can you work out who handled which dog, at what level each competed, the place each finished in and the breed of each dog?

1. If Tiff finished first then Terry finished fourth.
2. If Terry finished fourth then Jago is a collie otherwise Jago is not a collie.
3. If Jane competed in the Senior class then she finished third.
4. If Jane competed in Novice then she finished fourth.
5. The dog that finished ninth was an alsatian. This was either Jago, in which case Jago competed in the Elementary class, or this was Kelly, in which case Terry handled Kelly.
6. Mark won Starters.
7. If Mark's dog is called Patti then Patti is a labrador otherwise Patti is a collie.
8. Ruth's dog is called Jago.
9. If Jago finished fourth then she competed in the Novice class otherwise she competed in the Senior class.
10. If Patti finished first then Terry's dog is an alsatian otherwise Terry's dog is a collie.
11. If Jane's dog is a doberman then Jane finished fourth otherwise Jane finished third.
​Handler's Names: Jane, Mark, Ruth and Terry
Dog's Names: Tiff, Patti, Jago and Kelly
Breed: Alsatian, Collie, Labrador and Doberman
Level: Starters, Elementary, Novice or Senior

Imagine a prisoner in a prison. He is sentenced to death and has been told that he will be killed on one day of the following week. He has been assured that the day will be a surprise to him, so he will not be anticipating the hangman on a particular day, thus keeping his stress levels in check.

The prisoner starts to think to himself, if I am still alive on Thursday, then clearly I shall be hanged on Friday, this would mean that I then know the day of my death, therefore I cannot be hanged on Friday. Now then, if I am still alive on Wednesday, then clearly I shall be hanged on Thursday, since I have already ruled out Friday. The prisoner works back with this logic, finally concluding that he cannot after all be hanged, without already knowing which day it was.
Casually, resting on his laurels, sitting in his prison cell on Tuesday, the warden arrives to take him to be hanged, the prisoner was obviously surprised!

Ponder this?

8+(7+(6*5))(sqrt(4)(cube of 3)
i.e 54*37+8=1998+8=2006
here* imean multiply

495, isnt this the anwer people
simple mathematics

8,7,6,5,4,3
solution is
8*7 +3=56+3=59
6*5+4=30+4=34
now 59*34=2006
that's it
banu

Man just let me no the answer

this is nice.
add more puzzles.......

Use +, -, *, / to make the following equation. There are at least 6 solutions.

9,9,9,9,9,9 = 100

Hi
(8+7+6-5+4) ( 3+2+1)
=(20) (06)
=2006 😁

the y-notuse +, -, *, / to make the following equation. There are at least 6 solutions.

9,9,9,9,9,9 = 100

99/99+99=100

heyy what about that prisoner's question

raj87verma88The prisoner starts to think to himself, if I am still alive on Thursday, then clearly I shall be hanged on Friday, this would mean that I then know the day of my death, therefore I cannot be hanged on Friday. Now then, if I am still alive on Wednesday, then clearly I shall be hanged on Thursday, since I have already ruled out Friday. The prisoner works back with this logic, finally concluding that he cannot after all be hanged, without already knowing which day it was.
Casually, resting on his laurels, sitting in his prison cell on Tuesday, the warden arrives to take him to be hanged, the prisoner was obviously surprised!

Ponder this?

If we come back thinking this we think that this is true but its not true.
this is a paradox.
on sunday he have a chance to die in next 6 days , on monday next 5 days and tuesday next 4 days so there is a possibility to hang him..
i guess this might be the answer ,
Raj need to explain it 😀

English-ScaredIf we come back thinking this we think that this is true but its not true.
this is a paradox.
on sunday he have a chance to die in next 6 days , on monday next 5 days and tuesday next 4 days so there is a possibility to hang him..
i guess this might be the answer ,
Raj need to explain it 😀

raj...plz explain the reason behind this..

Hi,

(9*9)+9+(9/9)+9 = 100

Hope this will be one among the answers.

The Y-NotUse +, -, *, / to make the following equation. There are at least 6 solutions.

9,9,9,9,9,9 = 100

Thanks.

9/9 + 9 + 9*9 + 9=100

i would like to add one more problem here.

a person has eight identical looking balls,but one of them is heavier than others, he has a two -arm balancing machine and he can weigh only twice,

how can he determine the heavier one ?

yaar give me at least two chaNCES
so that i can solve it😁

yes, you got two chances to measure

Insert standard math symbols in the below numbers to get an expression equalling 2006.

8 7 6 5 4 3

The answer for this puzzle is

8*7+6^5/4+3!=2006

ankur vermaa person has eight identical looking balls,but one of them is heavier than others, he has a two -arm balancing machine and he can weigh only twice,

how can he determine the heavier one ?

Split the balls into two groups of three and one group of two.

Compare the two groups of three.

If one side is heavier, then take two balls from that group and compare them--if neither is heavier, then it's the third ball.

If the groups of three in the first weighing came up equal, then you know that the heavier ball is in the group of two, so you compare the weights of those two.

woot.

yup its good pizzle..............😁😁

The result can be generalized for any number of items to be weighed.....for and number that is between any fixed powers of 3!!!!

Here is a more interesting ques.....

there are 10 identical machines manufacturing medicines,one of them is defective and produces a tablet that is different in weight(not lighter necessary)....using a digital weight once,how will u tell the defective machine from the others?????😕

is this thread is active ? guys post some puzzles..infoyss puzzles

karan_shah89The result can be generalized for any number of items to be weighed.....for and number that is between any fixed powers of 3!!!!

Here is a more interesting ques.....

there are 10 identical machines manufacturing medicines,one of them is defective and produces a tablet that is different in weight(not lighter necessary)....using a digital weight once,how will u tell the defective machine from the others?????😕

you can have standard weight of tablet suppose say 10gm....now take one tablet from 1st machine..two tablet form 2nd machine ...3 tablet from 3rd machine and so on..so u must have 55 tablet and u must have total weight equal to 55*(standard weight of tablet)=550..... but actually u dont have because one machine is defective...so measure the weight of 55 tablet together...u can easily find out the defective machine from the difference |actual weight-550|......

correct me if i m wrong.....

Re: and here comes the tough one ( is it ? )

the answer is in the figure only....
they both have the same area.....look at the hypotnuse...both the hypotnuse are different......which is hard to visualize....and there is no extra space....

u r right...

Re: and here comes the tough one ( is it ? )

The_Big_KOkay !

Now this one will surely give you a good time 😀 !

How is this possible? -

(Edit: Removed the thumbnail and added the link -)

#-Link-Snipped-#

Thinks about it and post logical answer !

No kidding !

-The Big K-

actually the figure is wrong because...imagine this figure in a geometrical plane.......bottom left corner (0,0)...and top right corner (13,5)...then line joining these points does not pass through any of the points with both integer coordinates...where as in figure it is shown that....line passes through (8,3) and (5,2)....which is totaly wrong.....

We all knew that the absolute value would be the same. But I'm not sure how that solve's the biggie's ques

integratdbrains

The_Big_KOh really? 😉

Try this - ( should be easy )

-6 = -6
9-15 = 4-10

adding 25/4 to both sides:
9-15+(25/4) = 4-10+(25/4 )

Changing the order
9+(25/4)-15 = 4+(25/4)-10

(this is just like : a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

Taking mod on both sides. while subtracting the denominators of the numbers should be same! one cannot cancel the numbers!
/(3*2-5)/2/= /(2*2-5)/2/
/1/=/1/

The common CE sentence!"correct me if m wrong!"😒😁

What's the answer?

karan_shah89The result can be generalized for any number of items to be weighed.....for and number that is between any fixed powers of 3!!!!

Here is a more interesting ques.....

there are 10 identical machines manufacturing medicines,one of them is defective and produces a tablet that is different in weight(not lighter necessary)....using a digital weight once,how will u tell the defective machine from the others?????😕

shreyasm89What's the answer?

well, this is easy.

You take 1 tablet from machine 1, 2 from machine 2 and so on and 10 from machine 10.
Weigh the total tablets in the digital weight.
The total weight should ideally be a multiple of 55. (55 times the weight of one tablet)
See how much is the difference between the total weight and the nearest multiple of 55.

That is the defective machine, and if the total weight is greater than the multiple of 55, then the defective machine produces heavier tablets, and vice versa. 😀

Let's say machine 5 is defective and it produces lighter tablets. Then, the total weight will be 5 less than 55 times the weight of 1 tablet. 😀😀

Answer these...
1. There are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.
2. A train ran at a certain speed for one hour and then due to a technical problem, it ran at 3/5th of its original speed and reached the destination 2 hrs late. The driver said, had the problem occurred 50 miles later, we would have gained 40 minutes. What is the distance between the two cities that the train traveled?

There are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.

Ans: 1

harshajdThere are 6561 balls out of them 1 is heavy. Find the min. no. of times the balls have to be weighed for finding out the heavy ball.

Ans: 1

What??? How??? Explain... 😲

praveenscienceWhat??? How??? Explain... 😲

make two groups of 3820 balls.. if both are equal in weight then the left(6561th) ball is the one with higher weight...


*this is the possible minimum....

What if they are not equal... I am asking the minimum, where you get to know the heaviest ball...

then it's 7

harshajdthen it's 7

You came close... Say how you got... 😀

praveenscienceYou came close... Say how you got... 😀

break in to 3 groups.. and weigh two, if both are equal then third group is the one with heavier ball and if not equal, then choose the heavier one

6561/3=2187

2187/3= 729

729/3=243

243/3=81

81/3=27

27/3=9

9/3=3

3/3=1

had missed the bolder one while counting ...

ans is 8

harshajdbreak in to 3 groups.. and weigh two, if both are equal then third group is the one with heavier ball and if not equal, then choose the heavier one

6561/3=2187

2187/3= 729

729/3=243

243/3=81

81/3=27

27/3=9

9/3=3

3/3=1

had missed the bolder one while counting ...

ans is 8

Perfect!!! Now answer the second question... 😀

i am not good with trains and water slides

harshajdi am not good with trains and water slides

Thats not a good answer... But you were great with solving this one... 😀

total distance = 225 miles

here is the answer:
[8 - (7*6)] * [5 - (4^3)] =2006
step1: 7*6 = 42
step2: 8-42=-34
step3: 4^3 = 4*4*4= 64
step4: 5-64=-59
step5: -34 * -59
step6: 2006