Old is Gold : Numberology!!!

RajdeepCE
@rajdeepce-7UdrG8 โ€ข Oct 25, 2024

We will run two puzzle simultaneously,
1->>> Four fours problem : In this problem we have to make numbers starting from 1 by using only four 4, with any mathematical operation.
2->>> Four eights problem : This is same as above but instead of 4 we have to use 8.
We all have to follow some rules (including me cause I am with you in solving post):
1>> No thanks, no discussion, just post the answer.
2>> No double posting, let others solve the puzzle.
3>> We have to follow the sequence. That means that if I post the answer for 1, then the next one post the answer for 2 an the next 3, and so on.
4>> Post the answer for both 4 & 8. Single answer is not allowed.

Let us start and see how far we can go!!!!

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  • RajdeepCE

    @rajdeepce-7UdrG8 • May 29, 2009

    Here is the first one & remember the format.

    1-> 4/4+4-4 = 1
    2-> 8/8+8-8 = 1

    now, go for 2...

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 29, 2009

    Now for 2

    4/4 + 4/4 =2
    8/8 + 8/8 =2

    Go for 3..

  • smita89

    @smita89-e6e7FC • May 29, 2009

    (4+4+4)/4 =3
    (8+8+8)/8 =3

    Next is four!!

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    (4-4)/4+4 = 4
    8*8/(8+8) = 4
    Next is 5...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    4!/4 -(4/4) =5
    8!!!!/8 + 8/8 =5

    8!!!! = 8*4 =32


    next 6

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    English-Scared8!!!! = 8*4 =32

    I dont know about it. Anyway I have alternate solution it:
    3โˆš8+3โˆš8+8/8=5.
    For 6:
    โˆš4+4+4-4=6
    8-(8+8)/8=6
    next is 7...

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    4 + 4 - (4/4)= 7
    8 - 8 [sup](8-8)[/sup] = 7

    Doubt about 8 -Rajdeep . Please check if allowed or not

    Next 8...

  • silverscorpion

    @silverscorpion-iJKtdQ • May 30, 2009

    4 + 4 + 4 - 4 = 8

    8 + (8 - 8) / 8 = 8

    Next is 9..

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    4 + 4 + (4/4)= 9
    8 + 8 [sup](8-8)[/sup] = 9

    Again Rajdeep . Please check for 8 if allowed or not ๐Ÿ˜

    Next 10...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    4+4+4 - sqrt 4 = 10

    8 + (8+8)/8 = 10

    next 11

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    @Shalini, I am not getting you cause you are using 8(8-8), its simply a 0. So I am sorry to say that your calculation for both 7 & 9 is wrong. Here is a correct calculation:
    8*Cos8-8/8=7
    8*Cos8+8/8=9
    here 8*Cos8=7.92โ‰ˆ8.
    I am unable to found any other solution. If someone has more perfect solution than you are welcome!!!
    For 11,
    4+4+4-Cos4=11 (Cos4=0.997)
    8+3โˆš8+8/8=11
    next is 12...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    Rajdeep Shalini is using 8 to the power of (8-8) that is zero so 8 power zero is 1 .

    so the answers are correct .

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    Either I am unable to view the sign '^' or she forgot to put the sign. Whatever it is. If 8^(8-8) is used than both answers is right. I apologize for the above post. And concerning about my alternate solution, I want to say that I went for longway and you went simple.
    @ES, thanks for pointing out my error. Anyway now go for 12...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    4! -(4+4+4) = 12

    8+8 -3โˆš8-3โˆš8 = 12


    now 13 ๐Ÿ˜€

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    4+4+4+Cos4=13
    8+8/โˆš8+Cos8=13
    Here Cos4=0.997โ‰ˆ1 & Cos8=0.99โ‰ˆ1.
    Now go for 14...

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    @Rajdeep I need not to use '^' sign as CE provides a good facility of using a [sup ]b[/ sup] facility for displaying text in form a[sup]b[/sup]. ๐Ÿ˜€ You can refer this thread also #-Link-Snipped-#

    4+4+4 + sqrt(4) =14

    8+8 - sqrt(sqrt(8+8)) =14

    Go for 15...

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    May be this is due to my browser cause I am browsing CE from my mobile.
    For 15,
    4*4-4/4=15
    8+8-8/8=15
    Next is 16...

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    4 * 4 + (4-4) =16

    8 + 8 + (8-8)=16

    Go for 17...

  • pradeep_agrawal

    @pradeep-agrawal-rhdX5z • May 30, 2009

    4 * 4 + (4/4) = 17
    8 + 8 + (8/8) = 17

    Go for 18.

    -Pradeep

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    4 * 4 + (4/4) = 17

    8+8 + (8/8) = 17

    now 18 ๐Ÿ˜€

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    4 * 4 + sqrt(sqrt(4*4)) =18

    8 + 8 + sqrt(sqrt(8+8)))=18

    Go for 19..

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    shalini_goel144 * 4 + sqrt(4) =18

    8 * 8 + sqrt(sqrt(8+8)))=18

    Go for 19..



    @Shalini : you have to use 4 ,4's
    4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    English-Scared@Shalini : you have to use 4 ,4's
    4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18

    Thanks for pointing out, edited.

  • pradeep_agrawal

    @pradeep-agrawal-rhdX5z • May 30, 2009

    shalini_goel148 * 8 + sqrt(sqrt(8+8)))=18

    I feel yyou mean to say

    8 + 8 + sqrt(sqrt(8+8)))=18

    -Pradeep

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 30, 2009

    pradeep_agrawalI feel yyou mean to say

    8 + 8 + sqrt(sqrt(8+8)))=18

    -Pradeep

    Oops Sorry, what is happening to me. Editing

    Thanks for pointing out ๐Ÿ˜€

  • pradeep_agrawal

    @pradeep-agrawal-rhdX5z • May 30, 2009

    Do we allow operations like cube root and using sin, cos, etc. (for this we may need to take approximate values)?

    -Pradeep

  • pradeep_agrawal

    @pradeep-agrawal-rhdX5z • May 30, 2009

    4! - 4 - (4/4) = 19
    8 + 8 + cuberoot(8) + cos(8) = 19
    ((8 + cuberoot(8)) * cuberoot(8)) - cos(8) = 19

    4! - 4 + (4-4) = 20
    8 + 8 +โˆš(8+8) = 20

    4! - 4 + (4/4) = 21
    ((8 + cuberoot(8)) * cuberoot(8)) + cos(8) = 21

    Go for 22.

    -Pradeep

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    4! - sqrt 4 + 4 - 4 = 22


    8+8+8 - Cuberoot (8) = 22

    now 23 .

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 30, 2009

    @Pradeep. Yes we can. And one more thing that calculate only for one number only, cause we want to let others to solve. Anyway, for 23,
    4!-Cos4+(4-4)=23
    (8+8+8)-Cos8=23
    next is 24...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 30, 2009

    4 * 4 +4 + 4 = 24

    (8+8)*Cuberoot(8) -8 =24

    so next 25 ๐Ÿ˜€

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 31, 2009

    4!+(4^(4-4))=25
    8+8+8+Cos8=25
    Next is 26...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 31, 2009

    4! + sqrt(4) +4 -4 = 26

    8+8+8+ Cuberoot(8) = 26
    next 27

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 31, 2009

    Hey Rajdeep, is use of numbers other than 4 and 8 allowed? I guess you have used '3' while giving answer for 11. I am still not clear what you want from us.

    Anyways if allowed here goes my solution for 27 ๐Ÿ˜

    4! + sqrt(4) + 4/4 =27

    8+8+8+ log[sub]2[/sub]8=27
    or
    8+8+8+(ln 8) =27 (assuming base root is 2)

    Go for 28..

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 31, 2009

    @Shalini. I used qube root there.
    For 28,
    4!+4+4-4=28
    (8/quberoot(8))! + sqrt(8+8)=28
    Next is 29...

  • Anil Jain

    @CrazyBoy • May 31, 2009

    RajdeepCE(4-4)/4+4 = 4

    This is wrong...
    (4-4)/4+4 = 0

    -CB

  • Anil Jain

    @CrazyBoy • May 31, 2009

    4!+4+(4/4) = 24+4+1 = 29
    (log(base2)8)*(log(base2)8)*(log(base2)8)+cuberoot(8) = 3*3*3+2 = 29

    Next is 30...

    -CB

  • shalini_goel14

    @shalini-goel14-ASmC2J • May 31, 2009

    @CB I guess he meant

    ((4-4)/4 )+4=4

    Anyways for 29

    4! + 4 + (4/4) =29

    For 8
    Assuming base root is 2
    ( 8 * cube root of (8) ) + 8 - ln 8 = 29

    Go for 30..

    PS: Rajdeep for 8 , please tell any other option if you know. It couldn't strike to my mind.

    Thanks !

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 31, 2009

    crazyboyThis is wrong...
    (4-4)/4+4 = 0

    -CB

    lol, you just forgot the rule of priority, cause division & multiplication has higher priority than addition & subtraction. So the equation first becomes,
    0/4+4,
    and then it will bf,
    0+4=4.

    For 30,
    4! + 4 + (4/sqrt(4)) = 30
    (8/cuberoot(8))! + 8 - cuberoot(8)=30
    next is 31...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 31, 2009

    4! + sqrt(4)+sqrt(4)+sqrt(4) = 30


    (8* (Cuberoot(8)+Cuberoot(8)))-Cuberoot(8) =30


    next 31.

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 31, 2009

    @Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
    (8 / cuberoot(8))! + 8 - ln 8 = 29,
    assuming base 2, ln 8=3.
    For 31,
    4! + 4 + 4 - Cos 4 = 31,
    (8 / cuberoot(8))! + 8 - Cos 8 = 31
    next is 32...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 31, 2009

    its easy ๐Ÿ˜€

    (4*4)+ (4*4) = 32

    8+8+8+8 =32


    now 33 ๐Ÿ˜€

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 31, 2009

    Here is 33,
    (4*4)*sqrt(4)+Cos 4=33
    (8+8)*quberoot(8)+Cos 8 = 33
    next is 34...

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • May 31, 2009

    4*4*Sqrt(4) + sqrt(4) = 34

    8*Cuberoot(8)*cuberoot(8) +cuberoot(8) = 34

    next 35 ๐Ÿ˜€

  • RajdeepCE

    @rajdeepce-7UdrG8 • May 31, 2009

    For 35,
    4! + Cot 4 - sqrt(4) - Cos 4 = 35,
    (8/quberoot(8))! + 8 + log 8 = 35,
    assuming base 2 for log 8.
    Cot 4 = 14.1
    next is 36,..

  • shalini_goel14

    @shalini-goel14-ASmC2J • Jun 1, 2009

    RajdeepCE@Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
    (8 / cuberoot(8))! + 8 - ln 8 = 29,

    Oh yes, you are 100% right. I messed up in hurry. Sorry

    Anyways for 36

    4! + 4 + 4 + 4 =36

    [( 8 * 8 ) + 8 ]/ (cube root of 8) =36

    Go for 37.. ๐Ÿ˜€

    PS: I guess use of trignometry and logs should not be allowed, it gives approximate results ?

  • Yamini L

    @yamini-uMEVDQ • Jun 1, 2009

    For 37,

    ((4+4)*4)+4+(4/4))

    ((8/cube root(8))! + 8 + ((8/cube root(8)) +(8/8)

    next 38..

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • Jun 1, 2009

    @Miniy: You havent read the rules.
    You are supposed to use exactly 4 4's and 4 8's no more and no less are allowed.

  • Yamini L

    @yamini-uMEVDQ • Jun 1, 2009

    Completely missed it๐Ÿ˜”.Thanks for alerting me ES.I will edit that post.

  • RajdeepCE

    @rajdeepce-7UdrG8 • Jun 1, 2009

    shalini_goel14PS: I guess use of trignometry and logs should not be allowed, it gives approximate results.

    You are absolutely right, but sometime it is impossible to find a number without using trignometric or logrethmic functions. Consider for 37, I messed myself about half an hour but I was unable to find the answer with simple arithmetic functions, than I tried with trignometric functions and answer comes within 10 minutes. If anyone have better solution than feel free to repost. So here is my answer for 37,
    Cot 4 + 4! - (4/4) = 37,
    Cot (Cos 8) - (8/cuberoot(8))! + log[sub]2[/sub]8 = 37,
    here,
    Cot 4 โ‰ˆ 14, & Cot (Cos 8) โ‰ˆ 58.
    Next is 38.

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • Jun 1, 2009

    4! +(4*4) -sqrt(4) =38

    x = log8 to the base2 =3
    so 8*(x+cuberoot(8))-cuberoot(8) = 8*(2+3) -2 =38

    anyways next numebr is 39 ๐Ÿ˜€