Old is Gold : Numberology!!!

@rajdeepce-7UdrG8 • Oct 25, 2024

Oct 25, 2024

1.2K

We will run two puzzle simultaneously,
1->>> Four fours problem : In this problem we have to make numbers starting from 1 by using only four 4, with any mathematical operation.
2->>> Four eights problem : This is same as above but instead of 4 we have to use 8.
We all have to follow some rules (including me cause I am with you in solving post):
1>> No thanks, no discussion, just post the answer.
2>> No double posting, let others solve the puzzle.
3>> We have to follow the sequence. That means that if I post the answer for 1, then the next one post the answer for 2 an the next 3, and so on.
4>> Post the answer for both 4 & 8. Single answer is not allowed.

Let us start and see how far we can go!!!!

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RajdeepCE

@rajdeepce-7UdrG8 • May 29, 2009

Here is the first one & remember the format.

1-> 4/4+4-4 = 1
2-> 8/8+8-8 = 1

now, go for 2...
0
shalini_goel14

@shalini-goel14-ASmC2J • May 29, 2009

Now for 2

4/4 + 4/4 =2
8/8 + 8/8 =2

Go for 3..
0
smita89

@smita89-e6e7FC • May 29, 2009

(4+4+4)/4 =3
(8+8+8)/8 =3

Next is four!!
0
RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

(4-4)/4+4 = 4
8*8/(8+8) = 4
Next is 5...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

4!/4 -(4/4) =5
8!!!!/8 + 8/8 =5

8!!!! = 8*4 =32

next 6
0
RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

English-Scared
8!!!! = 8*4 =32
I dont know about it. Anyway I have alternate solution it:
3√8+3√8+8/8=5.
For 6:
√4+4+4-4=6
8-(8+8)/8=6
next is 7...
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

4 + 4 - (4/4)= 7
8 - 8 [sup](8-8)[/sup] = 7

Doubt about 8 -Rajdeep . Please check if allowed or not

Next 8...
0
silverscorpion

@silverscorpion-iJKtdQ • May 30, 2009

4 + 4 + 4 - 4 = 8

8 + (8 - 8) / 8 = 8

Next is 9..
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

4 + 4 + (4/4)= 9
8 + 8 [sup](8-8)[/sup] = 9

Again Rajdeep . Please check for 8 if allowed or not 😁

Next 10...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

4+4+4 - sqrt 4 = 10

8 + (8+8)/8 = 10

next 11
0
RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

@Shalini, I am not getting you cause you are using 8(8-8), its simply a 0. So I am sorry to say that your calculation for both 7 & 9 is wrong. Here is a correct calculation:
8*Cos8-8/8=7
8*Cos8+8/8=9
here 8*Cos8=7.92≈8.
I am unable to found any other solution. If someone has more perfect solution than you are welcome!!!
For 11,
4+4+4-Cos4=11 (Cos4=0.997)
8+3√8+8/8=11
next is 12...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

Rajdeep Shalini is using 8 to the power of (8-8) that is zero so 8 power zero is 1 .

so the answers are correct .
0
RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

Either I am unable to view the sign '^' or she forgot to put the sign. Whatever it is. If 8^(8-8) is used than both answers is right. I apologize for the above post. And concerning about my alternate solution, I want to say that I went for longway and you went simple.
@ES, thanks for pointing out my error. Anyway now go for 12...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

4! -(4+4+4) = 12

8+8 -3√8-3√8 = 12

now 13 😀
0
RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

4+4+4+Cos4=13
8+8/√8+Cos8=13
Here Cos4=0.997≈1 & Cos8=0.99≈1.
Now go for 14...
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

@Rajdeep I need not to use '^' sign as CE provides a good facility of using a [sup ]b[/ sup] facility for displaying text in form a[sup]b[/sup]. 😀 You can refer this thread also #-Link-Snipped-#

4+4+4 + sqrt(4) =14

8+8 - sqrt(sqrt(8+8)) =14

Go for 15...

0
RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

May be this is due to my browser cause I am browsing CE from my mobile.
For 15,
4*4-4/4=15
8+8-8/8=15
Next is 16...
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

4 * 4 + (4-4) =16

8 + 8 + (8-8)=16

Go for 17...
0
pradeep_agrawal

@pradeep-agrawal-rhdX5z • May 30, 2009

4 * 4 + (4/4) = 17
8 + 8 + (8/8) = 17

Go for 18.

-Pradeep
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

4 * 4 + (4/4) = 17

8+8 + (8/8) = 17

now 18 😀
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

4 * 4 + sqrt(sqrt(4*4)) =18

8 + 8 + sqrt(sqrt(8+8)))=18

Go for 19..
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

shalini_goel14
4 * 4 + sqrt(4) =18

8 * 8 + sqrt(sqrt(8+8)))=18

Go for 19..

@Shalini : you have to use 4 ,4's
4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

English-Scared
@Shalini : you have to use 4 ,4's
4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18
Thanks for pointing out, edited.
0
pradeep_agrawal

@pradeep-agrawal-rhdX5z • May 30, 2009

shalini_goel14
8 * 8 + sqrt(sqrt(8+8)))=18
I feel yyou mean to say

8 + 8 + sqrt(sqrt(8+8)))=18

-Pradeep
0
shalini_goel14

@shalini-goel14-ASmC2J • May 30, 2009

pradeep_agrawal
I feel yyou mean to say

8 + 8 + sqrt(sqrt(8+8)))=18

-Pradeep
Oops Sorry, what is happening to me. Editing

Thanks for pointing out 😀
0
pradeep_agrawal

@pradeep-agrawal-rhdX5z • May 30, 2009

Do we allow operations like cube root and using sin, cos, etc. (for this we may need to take approximate values)?

-Pradeep
0
pradeep_agrawal

@pradeep-agrawal-rhdX5z • May 30, 2009

4! - 4 - (4/4) = 19
8 + 8 + cuberoot(8) + cos(8) = 19
((8 + cuberoot(8)) * cuberoot(8)) - cos(8) = 19

4! - 4 + (4-4) = 20
8 + 8 +√(8+8) = 20

4! - 4 + (4/4) = 21
((8 + cuberoot(8)) * cuberoot(8)) + cos(8) = 21

Go for 22.

-Pradeep
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

4! - sqrt 4 + 4 - 4 = 22

8+8+8 - Cuberoot (8) = 22

now 23 .
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RajdeepCE

@rajdeepce-7UdrG8 • May 30, 2009

@Pradeep. Yes we can. And one more thing that calculate only for one number only, cause we want to let others to solve. Anyway, for 23,
4!-Cos4+(4-4)=23
(8+8+8)-Cos8=23
next is 24...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 30, 2009

4 * 4 +4 + 4 = 24

(8+8)*Cuberoot(8) -8 =24

so next 25 😀
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RajdeepCE

@rajdeepce-7UdrG8 • May 31, 2009

4!+(4^(4-4))=25
8+8+8+Cos8=25
Next is 26...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 31, 2009

4! + sqrt(4) +4 -4 = 26

8+8+8+ Cuberoot(8) = 26
next 27
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shalini_goel14

@shalini-goel14-ASmC2J • May 31, 2009

Hey Rajdeep, is use of numbers other than 4 and 8 allowed? I guess you have used '3' while giving answer for 11. I am still not clear what you want from us.

Anyways if allowed here goes my solution for 27 😁

4! + sqrt(4) + 4/4 =27

8+8+8+ log[sub]2[/sub]8=27
or
8+8+8+(ln 8) =27 (assuming base root is 2)

Go for 28..
0
RajdeepCE

@rajdeepce-7UdrG8 • May 31, 2009

@Shalini. I used qube root there.
For 28,
4!+4+4-4=28
(8/quberoot(8))! + sqrt(8+8)=28
Next is 29...
0
Anil Jain

@CrazyBoy • May 31, 2009

RajdeepCE
(4-4)/4+4 = 4
This is wrong...
(4-4)/4+4 = 0

-CB
0
Anil Jain

@CrazyBoy • May 31, 2009

4!+4+(4/4) = 24+4+1 = 29
(log(base2)8)*(log(base2)8)*(log(base2)8)+cuberoot(8) = 3*3*3+2 = 29

Next is 30...

-CB
0
shalini_goel14

@shalini-goel14-ASmC2J • May 31, 2009

@CB I guess he meant

((4-4)/4 )+4=4

Anyways for 29

4! + 4 + (4/4) =29

For 8
Assuming base root is 2
( 8 * cube root of (8) ) + 8 - ln 8 = 29

Go for 30..

PS: Rajdeep for 8 , please tell any other option if you know. It couldn't strike to my mind.

Thanks !
0
RajdeepCE

@rajdeepce-7UdrG8 • May 31, 2009

crazyboy
This is wrong...
(4-4)/4+4 = 0

-CB
lol, you just forgot the rule of priority, cause division & multiplication has higher priority than addition & subtraction. So the equation first becomes,
0/4+4,
and then it will bf,
0+4=4.

For 30,
4! + 4 + (4/sqrt(4)) = 30
(8/cuberoot(8))! + 8 - cuberoot(8)=30
next is 31...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 31, 2009

4! + sqrt(4)+sqrt(4)+sqrt(4) = 30

(8* (Cuberoot(8)+Cuberoot(8)))-Cuberoot(8) =30

next 31.
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RajdeepCE

@rajdeepce-7UdrG8 • May 31, 2009

@Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
(8 / cuberoot(8))! + 8 - ln 8 = 29,
assuming base 2, ln 8=3.
For 31,
4! + 4 + 4 - Cos 4 = 31,
(8 / cuberoot(8))! + 8 - Cos 8 = 31
next is 32...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 31, 2009

its easy 😀

(4*4)+ (4*4) = 32

8+8+8+8 =32

now 33 😀
0
RajdeepCE

@rajdeepce-7UdrG8 • May 31, 2009

Here is 33,
(4*4)*sqrt(4)+Cos 4=33
(8+8)*quberoot(8)+Cos 8 = 33
next is 34...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • May 31, 2009

4*4*Sqrt(4) + sqrt(4) = 34

8*Cuberoot(8)*cuberoot(8) +cuberoot(8) = 34

next 35 😀
0
RajdeepCE

@rajdeepce-7UdrG8 • May 31, 2009

For 35,
4! + Cot 4 - sqrt(4) - Cos 4 = 35,
(8/quberoot(8))! + 8 + log 8 = 35,
assuming base 2 for log 8.
Cot 4 = 14.1
next is 36,..
0
shalini_goel14

@shalini-goel14-ASmC2J • Jun 1, 2009

RajdeepCE
@Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
(8 / cuberoot(8))! + 8 - ln 8 = 29,
Oh yes, you are 100% right. I messed up in hurry. Sorry

Anyways for 36

4! + 4 + 4 + 4 =36

[( 8 * 8 ) + 8 ]/ (cube root of 8) =36

Go for 37.. 😀

PS: I guess use of trignometry and logs should not be allowed, it gives approximate results ?
0
Yamini L

@yamini-uMEVDQ • Jun 1, 2009

For 37,

((4+4)*4)+4+(4/4))

((8/cube root(8))! + 8 + ((8/cube root(8)) +(8/8)

next 38..
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 1, 2009

@Miniy: You havent read the rules.
You are supposed to use exactly 4 4's and 4 8's no more and no less are allowed.
0
Yamini L

@yamini-uMEVDQ • Jun 1, 2009

Completely missed it😔.Thanks for alerting me ES.I will edit that post.
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 1, 2009

shalini_goel14
PS: I guess use of trignometry and logs should not be allowed, it gives approximate results.
You are absolutely right, but sometime it is impossible to find a number without using trignometric or logrethmic functions. Consider for 37, I messed myself about half an hour but I was unable to find the answer with simple arithmetic functions, than I tried with trignometric functions and answer comes within 10 minutes. If anyone have better solution than feel free to repost. So here is my answer for 37,
Cot 4 + 4! - (4/4) = 37,
Cot (Cos 8) - (8/cuberoot(8))! + log[sub]2[/sub]8 = 37,
here,
Cot 4 ≈ 14, & Cot (Cos 8) ≈ 58.
Next is 38.
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 1, 2009

4! +(4*4) -sqrt(4) =38

x = log8 to the base2 =3
so 8*(x+cuberoot(8))-cuberoot(8) = 8*(2+3) -2 =38

anyways next numebr is 39 😀
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 1, 2009

4! + (4*4) - Cos 4 = 39,
((8*8)/cuberoot(8)) + Cot 8 = 39,
Cot 8 ≈ 7.
Next is 40.
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 1, 2009

4* (4+4+sqrt(4)) =40

(8/cuberoot(8))!+8+8 =40

Next 41

A small suggestion guys , if Cot 4 = 14.12 you can use a function called Int cot 4 which gives 14.
for values below 1 there is no excuse we need to go with the approximation as of now.
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 2, 2009

4! +(4*4) +cos(4) =41

x = log8 to the base2 =3
so 8*(x+cuberoot(8))+cos8 =41

Cos4 and Cos8 are approximately 1

So next 42
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 2, 2009

4! +(4*4) +sqrt(4) =42

x = log8 to the base2 =3
so 8*(x+cuberoot(8))+cuberoot8 =42

next 43 ??
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 2, 2009

@ES, I think you haven't read the rule. No double posting allowed cause we want others to take part here. So be patient next time.
For 43,
4! + 4! - 4 - Cos 4 = 43,
(8 - cuberoot(8)) * Cot 8 + Tan 8 = 43,
here, the total value is around 42.9, so by rounding up we get 43.
Next is 44...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 2, 2009

4! + (4*4) + 4 = 44

(8 - cuberoot(8)) * Cot 8 +Cuberoot (8) = 44

next 45 ..
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 2, 2009

For 45,
4! + 4! - 4 + Cos 4 = 45,
( 8 + 8 ) * Log[sub]2[/sub]8 - Log[sub]2[/sub]8 = 45,
here, Log[sub]2[/sub]8=3
next is 46.
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 2, 2009

@Rajdeep edit your last post it is 8+8 not 8 * 8 thanks

for 46..

4!+4!+Sqrt(4)-4 = 46

(8+8)*Log8to the base2 - Cuberoot(8) =46

Next 47..
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 2, 2009

Thanks ES!!
For 47,
4! + 4! - ( 4 / 4 ) = 47,
( 8 / cuberoot(8) )! * cuberoot(8) - Cos 8 = 47.
Next is 48.
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 2, 2009

4! + 4! +4 -4 = 48

8 * (cuberoot(8)+cuberoot(8)+cuberoot(8)) =48

Next 49

@Rajdeep : 😀
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 2, 2009

4! + 4! + ( 4 / 4 ) = 49,
( 8 / cuberoot(8) )! * cuberoot(8) + Cos 8 = 49.
Waiting for half century!!!!
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 2, 2009

4!+4!+4-Sqrt(4) =50

(8+8) *Log8tothebase2 + Cuberoot(8) =50

haha Half century sandy 😀

Next 51 😀
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

4! + 4! + sqrt(4) + Cos 4 = 51,
(8 / cuberoot(8) )! * cuberoot(8) + Log[sub]2[/sub]8 = 51,
Greas ES!!!
Next is 52,
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4!+4!+Sqrt(4)+Sqrt(4) =52

8*cot8 -(8/Cuberoot(8))= 52

next 53
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

4! + 4! + 4 + Cos4 = 53
8 * 8 - 8 - Log[sub]2[/sub]8 = 53
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4!+4!+4+Sqrt(4) = 54

8*8 -8-Cuberoot(8) =54

next 55
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

4! + 4! + ( Cot 4 / sqrt(4) ) = 55,
( 8 * 8 ) - 8 - Cos 8 = 55,
next is 56,
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shalini_goel14

@shalini-goel14-ASmC2J • Jun 3, 2009

4! + 4! + 4 + 4 =56

(8 * 8 ) + sqrt(8*8) =56

Go for 57..
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

Cot ( Cos 4 ) + 4 * ( 4 - 4 ) = 57,
( 8 * 8 ) - 8 + Cos 8 = 57,
here Cot ( Cos 4 ) = 57.4, so by rounding of we get the answer.
0
Harshad Italiya

@harshad-ukH5ww • Jun 3, 2009

4! + 4! + Cot4-4 = 58
8*8-8+cuberoot(8)=58
Next one 59...
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

Cot ( Cos 4 ) + ( 4 + 4 ) / 4 = 59,
8 * 8 + Cot 8 - quberoot(8) = 59,
here, Cot(Cos 4) = 57 approx. and Cot 8 = 7 appox.
Next is 60...
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4!+4! + Int(cot4) -cos4 =61

8*8 -(Cos8+Cuberoot(8))= 61

Next 62
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Harshad Italiya

@harshad-ukH5ww • Jun 3, 2009

4*4*4-sqrt(4)=62,
8*8-cuberoot(8)-Sin(Sin8)=62,
Sin(Sin8)=0.
Go for 63...
0
RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

4 * 4 * 4 - Cos 4 = 63,
8 * 8 - ( 8 / 8 ) = 63,
next is 64, easy one...
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4! +4! +(4*4) = 64

8*8 +log(8/8) =64

next 65
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

4 * 4 * 4 + Cos 4 = 65,
8 * 8 + ( 8 / 8 ) = 65,
next is 66.
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4 * 4 * 4 + Sqrt(4) =66

8 * 8 +cos8+cos8 =66

next 67
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

Cot ( Cos 4 ) + 4 + 4 + sqrt(4) = 67,
8 * 8 + cuberoot(8) + Cos 8 = 67,
next is 68...
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4*4*4 +4 =68

8*8+Cuberoot(8)+Cuberoot(8) =68

next 69?
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

Cot ( Cos 4 ) + 4 + 4 + 4 = 69,
8 * 8 + 8 - Log[sub]2[/sub]8 = 69,
next is 70.,
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shalini_goel14

@shalini-goel14-ASmC2J • Jun 3, 2009

Guys where is 60 gone? 😕
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

It was my error to ignore 60 and go for 61 Sorry guys.

4! + 4! +Int(cot4) -sqrt(4) =60

8*8 -Cuberoot(8)-Cuberoot(8) =60

Thanks shalini for pointing it out.

Guys 61 to 69 are done..
So next go for 70.
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

For 70,
4! + 4! + 4! - sqrt(4) = 70
8 * 8 + 8 - quberoot(8) = 70,
next is 71.
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shalini_goel14

@shalini-goel14-ASmC2J • Jun 3, 2009

4! + 4! + 4! -( log[sub]4[/sub]4 ) = 71

8 * 8 + 8 -( log[sub]8[/sub]8 ) = 71

log[sub]n[/sub]n=1

Go for 72..
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4! * (4-(4/4)) =72

8 * (8+(8/8)) = 72

next 73
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

4! + 4! + 4! + Cos 4 = 73,
( 8 * 8 ) + 8 + Cos 8 = 73,
next is 74...
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 3, 2009

4! + 4! + 4! + Sqrt(4) =74

8*8 +8 +Cuberoot(8) =74

next 75
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 3, 2009

Cot ( Cos 4 ) + 4! - 4 - sqrt(4) = 75,
( 8 * 8 ) + 8 + Log[sub]2[/sub]8 =75,
next is 76...
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 4, 2009

4! +4! +4! + 4 = 76

Int(Cot(cos8)) =57+log8tothe base2 + (8+8) = 76

next 77

PS.Thanks Rajdeep for correcting me
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 4, 2009

ES, you need to correct second one. Instead of (8*8) use (8+8).
For 77,
Cot(Cos 4) + ( 4 * 4 ) + 4 = 77,
8 ( 8 + cuberoot(8) - Log[sub]2[/sub]8 = 77,
next is 78...
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 4, 2009

Int(Cot(cos(4!))-Log(4)) +4*4 =Int(62.71-0.6020)+16 =62+16 = 78

(8* (8+cuberoot(8)))-Cuberoot(8) =78

This took lot of time for me.

next 79 😀
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 4, 2009

ES, it was not so hard.
( 4 * 4! ) - Cot 4 - 4 = 78.
For 79,
Cot(Cos 4) + 4! - 4 + sqrt(4) = 79,
( 8 * 8 ) + 8 + Cot 8 = 79,
next is 80...
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 4, 2009

Oh! rajdeep ok.. thanks 😀

4! *4 - (4*4) =80

(8*8)+8+8 =80

next 81
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 4, 2009

( 4! * 4 ) - Cot 4 - Cos 4 = 81,
8 * ( 8 + cuberoot(8) ) + Cos 8 = 81,
next is 82...
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sheeko

@sheeko-REBJf1 • Jun 4, 2009

sorry i posted a wrong answer then delete it
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jun 4, 2009

Int(Cot(cos(4!)))+4*4+4 =Int(62.71)+16+4 =62+16+4 = 82

8*(8+cuberoot(8))+Cuberoot(8) = 82

Next 83 😀
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 5, 2009

( 4! * 4 ) - Cot 4 + Cos 4 = 83,
( 8 * ( 8 + cuberoot(8) ) + Log[sub]2[/sub]8 = 83,
next is 84,
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RajdeepCE

@rajdeepce-7UdrG8 • Jun 26, 2009

* bump *
4! * 4 + sqrt(4) - Cot 4 = 84,
8 * ( 8 + sqrt(Cot 8) ) - Cos 8 = 84,
next is 85...
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