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Here is the first one & remember the format.
1-> 4/4+4-4 = 1
2-> 8/8+8-8 = 1
now, go for 2...
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Now for 2
4/4 + 4/4 =2
8/8 + 8/8 =2
Go for 3..
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(4+4+4)/4 =3
(8+8+8)/8 =3
Next is four!!
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(4-4)/4+4 = 4
8*8/(8+8) = 4
Next is 5...
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4!/4 -(4/4) =5
8!!!!/8 + 8/8 =5
8!!!! = 8*4 =32
next 6
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English-Scared
8!!!! = 8*4 =32
I dont know about it. Anyway I have alternate solution it:
3√8+3√8+8/8=5.
For 6:
√4+4+4-4=6
8-(8+8)/8=6
next is 7...
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4 + 4 - (4/4)= 7
8 - 8 [sup](8-8)[/sup] = 7
Doubt about 8 -Rajdeep . Please check if allowed or not
Next 8...
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4 + 4 + 4 - 4 = 8
8 + (8 - 8) / 8 = 8
Next is 9..
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4 + 4 + (4/4)= 9
8 + 8 [sup](8-8)[/sup] = 9
Again Rajdeep . Please check for 8 if allowed or not 😁
Next 10...
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4+4+4 - sqrt 4 = 10
8 + (8+8)/8 = 10
next 11
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@Shalini, I am not getting you cause you are using 8(8-8), its simply a 0. So I am sorry to say that your calculation for both 7 & 9 is wrong. Here is a correct calculation:
8*Cos8-8/8=7
8*Cos8+8/8=9
here 8*Cos8=7.92≈8.
I am unable to found any other solution. If someone has more perfect solution than you are welcome!!!
For 11,
4+4+4-Cos4=11 (Cos4=0.997)
8+3√8+8/8=11
next is 12...
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Rajdeep Shalini is using 8 to the power of (8-8) that is zero so 8 power zero is 1 .
so the answers are correct .
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Either I am unable to view the sign '^' or she forgot to put the sign. Whatever it is. If 8^(8-8) is used than both answers is right. I apologize for the above post. And concerning about my alternate solution, I want to say that I went for longway and you went simple.
@ES, thanks for pointing out my error. Anyway now go for 12...
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4! -(4+4+4) = 12
8+8 -3√8-3√8 = 12
now 13 😀
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4+4+4+Cos4=13
8+8/√8+Cos8=13
Here Cos4=0.997≈1 & Cos8=0.99≈1.
Now go for 14...
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@Rajdeep I need not to use '^' sign as CE provides a good facility of using a [sup ]b[/ sup] facility for displaying text in form a[sup]b[/sup]. 😀 You can refer this thread also #-Link-Snipped-#
4+4+4 + sqrt(4) =14
8+8 - sqrt(sqrt(8+8)) =14
Go for 15...
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May be this is due to my browser cause I am browsing CE from my mobile.
For 15,
4*4-4/4=15
8+8-8/8=15
Next is 16...
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4 * 4 + (4-4) =16
8 + 8 + (8-8)=16
Go for 17...
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4 * 4 + (4/4) = 17
8 + 8 + (8/8) = 17
Go for 18.
-Pradeep
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4 * 4 + (4/4) = 17
8+8 + (8/8) = 17
now 18 😀
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4 * 4 + sqrt(sqrt(4*4)) =18
8 + 8 + sqrt(sqrt(8+8)))=18
Go for 19..
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shalini_goel14
4 * 4 + sqrt(4) =18
8 * 8 + sqrt(sqrt(8+8)))=18
Go for 19..
@Shalini : you have to use 4 ,4's
4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18
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English-Scared
@Shalini : you have to use 4 ,4's
4! - (sqrt(4)+sqrt(4)+sqrt(4)) =18
Thanks for pointing out, edited.
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shalini_goel14
8 * 8 + sqrt(sqrt(8+8)))=18
I feel yyou mean to say
8 + 8 + sqrt(sqrt(8+8)))=18
-Pradeep
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pradeep_agrawal
I feel yyou mean to say
8 + 8 + sqrt(sqrt(8+8)))=18
-Pradeep
Oops Sorry, what is happening to me. Editing
Thanks for pointing out 😀
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Do we allow operations like cube root and using sin, cos, etc. (for this we may need to take approximate values)?
-Pradeep
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4! - 4 - (4/4) = 19
8 + 8 + cuberoot(8) + cos(8) = 19
((8 + cuberoot(8)) * cuberoot(8)) - cos(8) = 19
4! - 4 + (4-4) = 20
8 + 8 +√(8+8) = 20
4! - 4 + (4/4) = 21
((8 + cuberoot(8)) * cuberoot(8)) + cos(8) = 21
Go for 22.
-Pradeep
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4! - sqrt 4 + 4 - 4 = 22
8+8+8 - Cuberoot (8) = 22
now 23 .
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@Pradeep. Yes we can. And one more thing that calculate only for one number only, cause we want to let others to solve. Anyway, for 23,
4!-Cos4+(4-4)=23
(8+8+8)-Cos8=23
next is 24...
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4 * 4 +4 + 4 = 24
(8+8)*Cuberoot(8) -8 =24
so next 25 😀
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4!+(4^(4-4))=25
8+8+8+Cos8=25
Next is 26...
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4! + sqrt(4) +4 -4 = 26
8+8+8+ Cuberoot(8) = 26
next 27
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Hey Rajdeep, is use of numbers other than 4 and 8 allowed? I guess you have used '3' while giving answer for 11. I am still not clear what you want from us.
Anyways if allowed here goes my solution for 27 😁
4! + sqrt(4) + 4/4 =27
8+8+8+ log[sub]2[/sub]8=27
or
8+8+8+(ln 8) =27 (assuming base root is 2)
Go for 28..
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@Shalini. I used qube root there.
For 28,
4!+4+4-4=28
(8/quberoot(8))! + sqrt(8+8)=28
Next is 29...
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RajdeepCE
(4-4)/4+4 = 4
This is wrong...
(4-4)/4+4 =
0
-CB
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4!+4+(4/4) = 24+4+1 = 29
(log(base2)8)*(log(base2)8)*(log(base2)8)+cuberoot(8) = 3*3*3+2 = 29
Next is 30...
-CB
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@CB I guess he meant
((4-4)/4 )+4=4
Anyways for 29
4! + 4 + (4/4) =29
For 8
Assuming base root is 2
( 8 * cube root of (8) ) + 8 - ln 8 = 29
Go for 30..
PS: Rajdeep for 8 , please tell any other option if you know. It couldn't strike to my mind.
Thanks !
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crazyboy
This is wrong...
(4-4)/4+4 = 0
-CB
lol, you just forgot the rule of priority, cause division & multiplication has higher priority than addition & subtraction. So the equation first becomes,
0/4+4,
and then it will bf,
0+4=4.
For 30,
4! + 4 + (4/sqrt(4)) = 30
(8/cuberoot(8))! + 8 - cuberoot(8)=30
next is 31...
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4! + sqrt(4)+sqrt(4)+sqrt(4) = 30
(8* (Cuberoot(8)+Cuberoot(8)))-Cuberoot(8) =30
next 31.
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@Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
(8 / cuberoot(8))! + 8 - ln 8 = 29,
assuming base 2, ln 8=3.
For 31,
4! + 4 + 4 - Cos 4 = 31,
(8 / cuberoot(8))! + 8 - Cos 8 = 31
next is 32...
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its easy 😀
(4*4)+ (4*4) = 32
8+8+8+8 =32
now 33 😀
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Here is 33,
(4*4)*sqrt(4)+Cos 4=33
(8+8)*quberoot(8)+Cos 8 = 33
next is 34...
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4*4*Sqrt(4) + sqrt(4) = 34
8*Cuberoot(8)*cuberoot(8) +cuberoot(8) = 34
next 35 😀
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For 35,
4! + Cot 4 - sqrt(4) - Cos 4 = 35,
(8/quberoot(8))! + 8 + log 8 = 35,
assuming base 2 for log 8.
Cot 4 = 14.1
next is 36,..
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RajdeepCE
@Shalini, I think your answer is wrong, cause it gives us 21, here is another solution for it,
(8 / cuberoot(8))! + 8 - ln 8 = 29,
Oh yes, you are 100% right. I messed up in hurry. Sorry
Anyways for 36
4! + 4 + 4 + 4 =36
[( 8 * 8 ) + 8 ]/ (cube root of 8) =36
Go for 37.. 😀
PS: I guess use of trignometry and logs should not be allowed, it gives approximate results ?
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For 37,
((4+4)*4)+4+(4/4))
((8/cube root(8))! + 8 + ((8/cube root(8)) +(8/8)
next 38..
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@Miniy: You havent read the rules.
You are supposed to use exactly 4 4's and 4 8's no more and no less are allowed.
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Completely missed it😔.Thanks for alerting me ES.I will edit that post.
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shalini_goel14
PS: I guess use of trignometry and logs should not be allowed, it gives approximate results.
You are absolutely right, but sometime it is impossible to find a number without using trignometric or logrethmic functions. Consider for 37, I messed myself about half an hour but I was unable to find the answer with simple arithmetic functions, than I tried with trignometric functions and answer comes within 10 minutes. If anyone have better solution than feel free to repost. So here is my answer for 37,
Cot 4 + 4! - (4/4) = 37,
Cot (Cos 8) - (8/cuberoot(8))! + log[sub]2[/sub]8 = 37,
here,
Cot 4 ≈ 14, & Cot (Cos 8) ≈ 58.
Next is 38.
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4! +(4*4) -sqrt(4) =38
x = log8 to the base2 =3
so 8*(x+cuberoot(8))-cuberoot(8) = 8*(2+3) -2 =38
anyways next numebr is 39 😀
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4! + (4*4) - Cos 4 = 39,
((8*8)/cuberoot(8)) + Cot 8 = 39,
Cot 8 ≈ 7.
Next is 40.
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4* (4+4+sqrt(4)) =40
(8/cuberoot(8))!+8+8 =40
Next 41
A small suggestion guys , if Cot 4 = 14.12 you can use a function called Int cot 4 which gives 14.
for values below 1 there is no excuse we need to go with the approximation as of now.
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4! +(4*4) +cos(4) =41
x = log8 to the base2 =3
so 8*(x+cuberoot(8))+cos8 =41
Cos4 and Cos8 are approximately 1
So next 42
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4! +(4*4) +sqrt(4) =42
x = log8 to the base2 =3
so 8*(x+cuberoot(8))+cuberoot8 =42
next 43 ??
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@ES, I think you haven't read the rule. No double posting allowed cause we want others to take part here. So be patient next time.
For 43,
4! + 4! - 4 - Cos 4 = 43,
(8 - cuberoot(8)) * Cot 8 + Tan 8 = 43,
here, the total value is around 42.9, so by rounding up we get 43.
Next is 44...
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4! + (4*4) + 4 = 44
(8 - cuberoot(8)) * Cot 8 +Cuberoot (8) = 44
next 45 ..
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For 45,
4! + 4! - 4 + Cos 4 = 45,
( 8 + 8 ) * Log[sub]2[/sub]8 - Log[sub]2[/sub]8 = 45,
here, Log[sub]2[/sub]8=3
next is 46.
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@Rajdeep edit your last post it is 8+8 not 8 * 8 thanks
for 46..
4!+4!+Sqrt(4)-4 = 46
(8+8)*Log8to the base2 - Cuberoot(8) =46
Next 47..
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Thanks ES!!
For 47,
4! + 4! - ( 4 / 4 ) = 47,
( 8 / cuberoot(8) )! * cuberoot(8) - Cos 8 = 47.
Next is 48.
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4! + 4! +4 -4 = 48
8 * (cuberoot(8)+cuberoot(8)+cuberoot(8)) =48
Next 49
@Rajdeep : 😀
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4! + 4! + ( 4 / 4 ) = 49,
( 8 / cuberoot(8) )! * cuberoot(8) + Cos 8 = 49.
Waiting for half century!!!!
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4!+4!+4-Sqrt(4) =50
(8+8) *Log8tothebase2 + Cuberoot(8) =50
haha Half century sandy 😀
Next 51 😀
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4! + 4! + sqrt(4) + Cos 4 = 51,
(8 / cuberoot(8) )! * cuberoot(8) + Log[sub]2[/sub]8 = 51,
Greas ES!!!
Next is 52,
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4!+4!+Sqrt(4)+Sqrt(4) =52
8*cot8 -(8/Cuberoot(8))= 52
next 53
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4! + 4! + 4 + Cos4 = 53
8 * 8 - 8 - Log[sub]2[/sub]8 = 53
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4!+4!+4+Sqrt(4) = 54
8*8 -8-Cuberoot(8) =54
next 55
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4! + 4! + ( Cot 4 / sqrt(4) ) = 55,
( 8 * 8 ) - 8 - Cos 8 = 55,
next is 56,
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4! + 4! + 4 + 4 =56
(8 * 8 ) + sqrt(8*8) =56
Go for 57..
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Cot ( Cos 4 ) + 4 * ( 4 - 4 ) = 57,
( 8 * 8 ) - 8 + Cos 8 = 57,
here Cot ( Cos 4 ) = 57.4, so by rounding of we get the answer.
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4! + 4! + Cot4-4 = 58
8*8-8+cuberoot(8)=58
Next one 59...
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Cot ( Cos 4 ) + ( 4 + 4 ) / 4 = 59,
8 * 8 + Cot 8 - quberoot(8) = 59,
here, Cot(Cos 4) = 57 approx. and Cot 8 = 7 appox.
Next is 60...
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4!+4! + Int(cot4) -cos4 =61
8*8 -(Cos8+Cuberoot(8))= 61
Next 62
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4*4*4-sqrt(4)=62,
8*8-cuberoot(8)-Sin(Sin8)=62,
Sin(Sin8)=0.
Go for 63...
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4 * 4 * 4 - Cos 4 = 63,
8 * 8 - ( 8 / 8 ) = 63,
next is 64, easy one...
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4! +4! +(4*4) = 64
8*8 +log(8/8) =64
next 65
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4 * 4 * 4 + Cos 4 = 65,
8 * 8 + ( 8 / 8 ) = 65,
next is 66.
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4 * 4 * 4 + Sqrt(4) =66
8 * 8 +cos8+cos8 =66
next 67
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Cot ( Cos 4 ) + 4 + 4 + sqrt(4) = 67,
8 * 8 + cuberoot(8) + Cos 8 = 67,
next is 68...
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4*4*4 +4 =68
8*8+Cuberoot(8)+Cuberoot(8) =68
next 69?
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Cot ( Cos 4 ) + 4 + 4 + 4 = 69,
8 * 8 + 8 - Log[sub]2[/sub]8 = 69,
next is 70.,
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Guys where is 60 gone? 😕
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It was my error to ignore 60 and go for 61 Sorry guys.
4! + 4! +Int(cot4) -sqrt(4) =60
8*8 -Cuberoot(8)-Cuberoot(8) =60
Thanks shalini for pointing it out.
Guys 61 to 69 are done..
So next go for 70.
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For 70,
4! + 4! + 4! - sqrt(4) = 70
8 * 8 + 8 - quberoot(8) = 70,
next is 71.
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4! + 4! + 4! -( log[sub]4[/sub]4 ) = 71
8 * 8 + 8 -( log[sub]8[/sub]8 ) = 71
log[sub]n[/sub]n=1
Go for 72..
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4! * (4-(4/4)) =72
8 * (8+(8/8)) = 72
next 73
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4! + 4! + 4! + Cos 4 = 73,
( 8 * 8 ) + 8 + Cos 8 = 73,
next is 74...
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4! + 4! + 4! + Sqrt(4) =74
8*8 +8 +Cuberoot(8) =74
next 75
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Cot ( Cos 4 ) + 4! - 4 - sqrt(4) = 75,
( 8 * 8 ) + 8 + Log[sub]2[/sub]8 =75,
next is 76...
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4! +4! +4! + 4 = 76
Int(Cot(cos8)) =57+log8tothe base2 + (8+8) = 76
next 77
PS.Thanks Rajdeep for correcting me
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ES, you need to correct second one. Instead of (8*8) use (8+8).
For 77,
Cot(Cos 4) + ( 4 * 4 ) + 4 = 77,
8 ( 8 + cuberoot(8) - Log[sub]2[/sub]8 = 77,
next is 78...
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Int(Cot(cos(4!))-Log(4)) +4*4 =Int(62.71-0.6020)+16 =62+16 = 78
(8* (8+cuberoot(8)))-Cuberoot(8) =78
This took lot of time for me.
next 79 😀
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ES, it was not so hard.
( 4 * 4! ) - Cot 4 - 4 = 78.
For 79,
Cot(Cos 4) + 4! - 4 + sqrt(4) = 79,
( 8 * 8 ) + 8 + Cot 8 = 79,
next is 80...
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Oh! rajdeep ok.. thanks 😀
4! *4 - (4*4) =80
(8*8)+8+8 =80
next 81
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( 4! * 4 ) - Cot 4 - Cos 4 = 81,
8 * ( 8 + cuberoot(8) ) + Cos 8 = 81,
next is 82...
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sorry i posted a wrong answer then delete it
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Int(Cot(cos(4!)))+4*4+4 =Int(62.71)+16+4 =62+16+4 = 82
8*(8+cuberoot(8))+Cuberoot(8) = 82
Next 83 😀
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( 4! * 4 ) - Cot 4 + Cos 4 = 83,
( 8 * ( 8 + cuberoot(8) ) + Log[sub]2[/sub]8 = 83,
next is 84,
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* bump *
4! * 4 + sqrt(4) - Cot 4 = 84,
8 * ( 8 + sqrt(Cot 8) ) - Cos 8 = 84,
next is 85...
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