Leaf of Descartes
@aruwin-WQ7eeu
•
Oct 22, 2024
Oct 22, 2024
1.0K
Someone,I need help in this.I have the answer but I can't think of a solution.I have tried a few things,though...
Parameterization of the leaf of Descartes.
y=tx => x= (3at)/(1+t^3)
y= (3at^2)/(1+t^3) (-infinity<t<infinity)
And here are some things I have figured out,
When t<-1,
t+1<0, 1+t^3<0 and hence x>0
When 0>t>-1,
t+1>0, 1+t^3>0 and hence x<0
*Here are the hints my teacher gave me:
limx(t-->-1)= +/- infinity
limx(t-->-1,t<-1)=infinity
limx(t-->-1,t>-1)= -infinity
and here is the answer:
![[IMG]](proxy.php?image=http%3A%2F%2Fi594.photobucket.com%2Falbums%2Ftt26%2FPRINCESS_HALIZA_2009%2FIMG_1202.jpg&hash=5b43eb0f85ded25cf93d8fc86f573e4e)
Parameterization of the leaf of Descartes.
y=tx => x= (3at)/(1+t^3)
y= (3at^2)/(1+t^3) (-infinity<t<infinity)
And here are some things I have figured out,
When t<-1,
t+1<0, 1+t^3<0 and hence x>0
When 0>t>-1,
t+1>0, 1+t^3>0 and hence x<0
*Here are the hints my teacher gave me:
limx(t-->-1)= +/- infinity
limx(t-->-1,t<-1)=infinity
limx(t-->-1,t>-1)= -infinity
and here is the answer:
