How to use differential pressure sensors to measure the hydrostatic level of a liquid in a vented or

@ramani-VR4O43 • Oct 26, 2024

Oct 26, 2024

1.6K

This article from American Sensors gives the basics of how differential pressure sensors can be used to monitor liquid levels in both vented and sealed tanks. Precautions to be observed for sealed tank measurements are also given.

Nothing fancy but useful.

<a href="https://www.designfax.net/cms/dfx/opens/article-view-dfx.php?nid=4&bid=264&et=featurearticle&pn=06" target="_blank" rel="nofollow noopener noreferrer">Designfax – Technology for OEM Design Engineers</a>

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chithrachennai

@chithrachennai-Xvts5V • Aug 7, 2013

sir ,

once i was asked in an interview why the industrial standards are 4-20 mA for current , voltage 0-30 V (i am not sure about voltage standard)?

can you please explain this concept

thanks in advance .
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Jeffrey Arulraj

@jeffrey-xA7lUP • Aug 7, 2013

Sub 1W criteria will be met in those condition for sure

And also most electronic Component operate in the 0 to 30 V region with about 20mA current through them
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Ramani Aswath

@ramani-VR4O43 • Aug 7, 2013

chithrachennai
once i was asked in an interview why the industrial standards are 4-20 mA for current , voltage 0-30 V (i am not sure about voltage standard)? can you please explain this concept
The advantage of a current loop is that the resistance of the connecting leads especially over long signal transmission lines does not affect analog signals. The electronics will adjust the voltage to ensure that the analog signal retains the accuracy. In an industrial environment with varying electro-magnetic loads, current loops have very good reliability.
The 4ma zero value has a bonus in that it tells if there is a break in the leads.
Here is a good article on current loops from National Instruments:
#-Link-Snipped-#

A voltage analog output has to be used with a high impedance measuring circuit.
I do not know why 0-30V is specified. If I may hazard a guess the higher voltage is likely to be more accurate than millivolt signals because of lead impedance.

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Surya Neo

@surya-neo-7IKptT • Aug 10, 2013

thanks
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