How much more each have to contribute ?

@rengaraj-89Rrct • Oct 22, 2024

Oct 22, 2024

1.3K

Sir / madam,
My question is

M men agree to purchase a gift for Rs.D. If three men drop out how much more will each have to contribute towards the purchase of the gift ?

a. D/(M-3)
b. MD/3
c. M/(D-3)
d. 3D/(M(square) - 3M)

Advance Thanks,
R.Rengaraj
{SCE 10/2008/Pg 6 of 85}
{On this forum my 11th Question.

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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 24, 2009

new share of each man = D/M-3

extra money they have to pay = (D/M-3)-(D/M)

= 3D/M*(M-3)

= 3D/(M(square) - 3M)

hence answer is

d). 3D/(M(square) - 3M)
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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 24, 2009

hi rengraj....

the above question is too basic ...please post the more tough questions ...may be 10 times more tough than this easy one...
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rengaraj

@rengaraj-89Rrct • Nov 25, 2009

Sir,
For you everything is easy. To test you I should search a question, which will be really challenge. That i will do...in very soon.
Until then please show your co-operation.
Thanks for your highly co-operative manner.
R.Rengaraj
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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 25, 2009

waiting for your challenge....
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rengaraj

@rengaraj-89Rrct • Nov 29, 2009

Sir,
I will get soon...with an challenging question
Thanks,
R.Rengaraj
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sarveshgupta

@sarveshgupta-txtmu5 • Nov 30, 2009

yadavundertaker
hi rengraj....

the above question is too basic ...please post the more tough questions ...may be 10 times more tough than this easy one...
yes the question was a basic one but still fun to solve
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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 30, 2009

rengaraj
Sir,
I will get soon...with an challenging question
Thanks,
R.Rengaraj

hi rengraj

i told you earlier also that don't say sir.....as i know you are a teacher and i am a 3rd year student....and we are here to help each other ...

so it is my kind request not to say sir..
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rengaraj

@rengaraj-89Rrct • Dec 1, 2009

Hi,
Did you go through my next question ?
How you feel abt this ?

#-Link-Snipped-#
R.Rengaraj

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rengaraj

@rengaraj-89Rrct • Dec 1, 2009

Hi,
Try my new question.

#-Link-Snipped-#

R.Rengaraj

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