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HI CEans here a simple question for you people.....

Question asked by bharathkumarp in #Coffee Room on May 3, 2010
bharathkumarp
bharathkumarp 路 May 3, 2010
Rank D3 - MASTER
The average mark obtained by 120 candidates was 35.If the average mark of passed candidates was 39 and that of the failed candidates was 15,
how many candidates passed the examination?😕😕😕 Posted in: #Coffee Room
Saandeep Sreerambatla
Saandeep Sreerambatla 路 May 5, 2010
Rank A2 - PRO
By the given conditions we can have 2 equations.
x + y = 120
39x + 15y = 120 * 35
On solving these equations we get x = 100 and y = 20

So candidates passed = 100
failed = 20
bharathkumarp
bharathkumarp 路 May 5, 2010
Rank D3 - MASTER
hi Mr.English scared your brilliant, by taking the equation and solving....But it consume more time.. There is another way to answer, just think. with out paper work you can easily solve this........
Kaustubh Katdare
Kaustubh Katdare 路 May 5, 2010
Rank A1 - PRO
The total number of candidates will be divided in ratio 5:1 [pass:fail], which makes it 100:20, that means 100 passed and 20 failed.
sherya mathur
sherya mathur 路 May 5, 2010
Rank C3 - EXPERT
given total number of passed students are =120
let the number of pass students=x
and let the number of fail students is=y
so from the questions
the equations will be
x+y=120 .............(1)
total number of marks get by all the students=120*35
=4200
now the second equation will be
39x + 15y= 4200.........(2)
putting the value of x in equation (2) from the first equation ie. x=120-y
39(120-y)+15y=4200
4680-39y+15y=4200
24y=480
y=20
by solving it we will get
y=20
x=100
so the number of passed students =100
sp the number of failed students =20

Never let your sense of morals get in the way of doing what's right

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