Hi All I am new to CE
hi
This is Binod from India. I am so glad to find this and I like to make friends to share my thoughts. I am currently working in an IT company. if you have any question about this, please let me know. I believe we will have a nice talk here.
This is Binod from India. I am so glad to find this and I like to make friends to share my thoughts. I am currently working in an IT company. if you have any question about this, please let me know. I believe we will have a nice talk here.
Replies
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Kaustubh KatdareWelcome to CE, Binod 😀 Tell us how did you discover CE?
PS: Do not forget to participate in our ongoing CE Grand Quiz 👍
You are reading an archived discussion.
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From figure we have,
[1] PR = QR
[2] QS = SR
-----------------------------------------------
In Figure 2, parallel to PQ, we draw SU
Because [1] and PQ || SU, we get...