@praky • 01 May, 2010

What will happen if afully charged ideal capacitor is short circuited with an ideal 0 resistance wire? Will the capacitor change polarity?

What will happen if an ideal ideal inductor is connected across a battery of say E volts. what will the variation of current?

What will happen if an ideal ideal inductor is connected across a battery of say E volts. what will the variation of current?

@lal • 01 May, 2010
I think the capacitor would discharge momentarily. Since there is no resistance to limit the current flow in this case.

An inductor is of no use in dc applications. If you connect an inductor across a battery, its same as short circuiting it!

An inductor is of no use in dc applications. If you connect an inductor across a battery, its same as short circuiting it!

@praky • 01 May, 2010

how will the capacitor discharge and if it discharges within a moment then where does the energy go since there is no resistance in the ckt?

inductor will short ckt battery at steady state only. When battery will be connected the inductor will behave as open switch. i am asking for the current variation till steady state...

lalI think the capacitor would discharge momentarily. Since there is no resistance to limit the current flow in this case.

An inductor is of no use in dc applications. If you connect an inductor across a battery, its same as short circuiting it!

how will the capacitor discharge and if it discharges within a moment then where does the energy go since there is no resistance in the ckt?

inductor will short ckt battery at steady state only. When battery will be connected the inductor will behave as open switch. i am asking for the current variation till steady state...

@sauravgoswami • 02 May, 2010
It will again charge the capacitor again,but polarity wont be changing,as for Inductor no effect on current since it is DC, it might effect little variation in voltage

prakyhow will the capacitor discharge and if it discharges within a moment then where does the energy go since there is no resistance in the ckt?

inductor will short ckt battery at steady state only. When battery will be connected the inductor will behave as open switch. i am asking for the current variation till steady state...

@Saandeep Sreerambatla • 02 May, 2010
Capacitor can discharge with the resistance of the Voltage source!

@reachrkata • 03 May, 2010
In fact the capacitors never charges again. All the electrons in the -ve terminal flow instantaneously to neutralise the positively charged terminal. The Energy is lost as EM waves. This is the same concept of EMP (electro magnetic pulse) heard in the Matrix movies.

-Karthik

😁

-Karthik

😁

@praky • 04 May, 2010

reachrkataIn fact the capacitors never charges again. All the electrons in the -ve terminal flow instantaneously to neutralise the positively charged terminal. The Energy is lost as EM waves. This is the same concept of EMP (electro magnetic pulse) heard in the Matrix movies.

satisfied.

In inductor problem, will the current never rise across inductor?

@reachrkata • 05 May, 2010
No it will rise, but not instantaneously. It will rise exponentially.

-Karthik

-Karthik

@praky • 05 May, 2010

I think the current should rise linearly since no resistance is there.reachrkataNo it will rise, but not instantaneously. It will rise exponentially.

-Karthik

@aj_onduty • 26 Aug, 2010

The inductor acts as an open circuit initially, and then it slowly, but exponentially, loses that property.

The reverse happens in capacitors.

prakyI think the current should rise linearly since no resistance is there.

The inductor acts as an open circuit initially, and then it slowly, but exponentially, loses that property.

The reverse happens in capacitors.

@bohar • 26 Aug, 2010
i think capacitor will discharge because ideal wire has no resistance to limit the current.

@Dave Hill • 02 Oct, 2015 • 1 like
If no external resistance is applied (short circuit) the capacitor will discharge at a rate only limited by it's own internal resistance. The amount of heat generated in the capacitor can be excessive when this happens and can be determined by the number of joules expended shorting a capacitor across its effective internal resistance.

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