Find the digit ?

@rengaraj-89Rrct • Oct 22, 2024

Oct 22, 2024

1.1K

Sir / madam,
My question is

There is a 5 digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3rd digit is 3 less than the second. 4th digit is 4 more than second one. Find the digit

Advance Thanks,
R.Rengaraj
{SCE 38/2008/Pg 4 of 85}
{On this forum my 7th Question.}

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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 13, 2009

hi..can you please explain what "3 pairs of sum is 11 each" means.....only this condition is missing else the solution will be something like this

Let five digit no. = a b c d e

e=3a

c+3=b

d=b+2

if condition first become clear then I can solve this..Please write the complete question accurately...
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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 17, 2009

hi rengraj...where are you ?..please explain the first condition?....
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CIVILPRINCESS

@civilprincess-308hDv • Nov 18, 2009

rengaraj
3 pairs of sum is eleven each.
Does that mean any three pairs of digits which sum up to eleven?
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cooltwins

@cooltwins-I5yJpZ • Nov 19, 2009

assuming the number is abcde, the answer i got is 65292.
and this is purely based on trial and error method,along with the 3 simultaneous equations which are
e=3a
c+3=b
d=b+4

as there exist 3 pairs of digits summing up to eleven, a &e are surely not one of them as a+e=a+3a=4a (which is surely not a multiple of 11;-))
now c+d=c+4+b=2c+7
assuming this is equal to 11 =>c=2
so d=9
and b=5
now assuming d+e is also equal to 11 we get e=2 =>a=6
and the three pairs which sum up to 11 are :
(a,b)(c,d)(d,e)

P.S.i know this is fully suspended on assumptions and is prone to error....;-)
correct me if i am wrong😁
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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Nov 19, 2009

Your method and process is correct but the number is wrong.

e = 3a

6 = 3 * 2

So the number might be 25296.

😀
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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 19, 2009

yes ES is right ....
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cooltwins

@cooltwins-I5yJpZ • Nov 19, 2009

yes i made a mistake 😡

i took a=3e instead of 3a=e in the final step
thanks for pointing out.....:smile:

so there we have the answer:25296

hope atleast this is correct.😁
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yadavundertaker mohit

@yadavundertaker-0p3HBs • Nov 19, 2009

cooltwins
as there exist 3 pairs of digits summing up to eleven, a &e are surely not one of them as a+e=a+3a=4a (which is surely not a multiple of 11;-))
now c+d=c+4+b=2c+7
assuming this is equal to 11 =>c=2
so d=9
and b=5
now assuming d+e is also equal to 11 we get e=2 =>a=6
and the three pairs which sum up to 11 are :
(a,b)(c,d)(d,e)

you think one step ahead of everyone ..great..
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cooltwins

@cooltwins-I5yJpZ • Nov 19, 2009

yadavundertaker
you think one step ahead of everyone ..great..
thanks yadav:smile:
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rengaraj

@rengaraj-89Rrct • Nov 21, 2009

Sir,
My system didn't work properly for few days. So, I was not able to connect. Any how, thanks for the various responses.
Thanks,
R.Rengaraj
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