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@cranky-E9J79q • Jul 13, 2011
I am not too sure about this.But here is my take:
Consider the first input is A,followed by B,C and D.When (A ^ B ^ C^ D)'output is sent through "NOT" gate,the output would be the same as the question. It also states that the output is turned at every fourth clock cycle.So,we could use four registers( or a counter ) to send this signal.
Someone please clarify 😀 -
@adivy-4HW5my • Jul 13, 2011
Could you please explain in detail about considering ABCD as inputs?I dont get it?
Following is what I understood from the question:-
firstly since it is talking about serial data in so i think we need to use registers as you said.Secondly as it deals with previous clocks we need to design a sequential circuit.
As a whole, the output on nth clock is high if the data-in on clocks (n-1),(n-2),(n-3)&(n-4) has even number of ones. -
@adivy-4HW5my • Jul 18, 2011
Someone please help?? -
@mjwashere-Sz0Vgi • Aug 1, 2011
@Adivy : Did you get any answer to this question yet ? Mind sharing ? -
@adivy-4HW5my • Aug 5, 2011
I didnt get any answer.
CEans please help us out with this problem.