combination of ac and dc

amanoverworked

@amanoverworked-ISRQkL • Oct 26, 2024

Oct 26, 2024

1.5K

V=10 v + 5sin(wt) v
what will be the nature of the above voltage?
whether it would be dc or ac ?

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imnitsy

@imnitsy-VRNV82 • Jan 30, 2010

it nature is AC!!
adding a dc in ac signal will increase the magnitude by the dc voltage!!😁

correct me if i am wrong!!
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imnitsy

@imnitsy-VRNV82 • Jan 30, 2010

also the magnitude of the resultant voltage must be sqrt(100+25)!!!!
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ankita15

@ankita15-7zSWG6 • Jan 31, 2010

it will be ac,,,,,,,,as sin function is there,,,,,,,,
correct ,,,,if it is wrong ans.
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nitin_sharma

@nitin-sharma-W1sln9 • Feb 1, 2010

It will be an ac signal which will fluctuate about the 10V DC level instead of ground level.
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sanks85

@sanks85-20puY7 • Feb 1, 2010

if we draw the graph of both the DC as well as AC function then the resultant will be in AC form with the magnitude around 10v so it will be purely an AC signal...
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amanoverworked

@amanoverworked-ISRQkL • Feb 3, 2010

but according to the definition of alternating current its direction changes , but here it is fixed.
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Rifaa

@rifaa-NaWZZ4 • Feb 3, 2010

With 10VDC and 5VAC together means AV is super imposed on DC.
Resultant will be a DC Voltage with an AC component ( like a ripple in DC).

Graph will look like an AC sine wave via a scope provided the DC function is enabled, with a reference at 10V instead of 0V as a pure sine wave would look like.

Rifaa
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360degrees

@360degrees-8U1wAp • Feb 8, 2010

I think its dc in nature.Not a perfect DC but a pulsating one.I think so because when (wt)=0,its value =10;wt=90,its value=15,wt=180 it again becomes 10 and wt=270 it is 5.
So it varies from +5 to +15V.
So it is a DC.
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360degrees

@360degrees-8U1wAp • Feb 8, 2010

This is basically the output of a clamper circuit.It is used in DC insertion in Television etc..
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shahrul

@shahrul-Ex12xz • Feb 11, 2010

Rifaa
With 10VDC and 5VAC together means AV is super imposed on DC.
Resultant will be a DC Voltage with an AC component ( like a ripple in DC).

Graph will look like an AC sine wave via a scope provided the DC function is enabled, with a reference at 10V instead of 0V as a pure sine wave would look like.

Rifaa
Agree, the DC voltage greater than the AC amplitude. So, the adding result is all the value will be positif. So, no alternating voltage. It's DC signal.
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roxy_1001

@roxy-1001-6yiSLX • Feb 13, 2010

i hope this diagram will help you to clear you doubt ...

things you can see...

1) It's normal sinewave shifted 10 v above the 0v level...
2) It will have no -ve cycles..
3) It will fluctauate above and below 10v refernce level...
4) If you add -10v instead of adding +10v the whole graph will be shifted below the 0v.
5) This kind of waveforms are called as Fluctuating DC's ..not AC...😁
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