Member • Aug 12, 2013
Capacitor as loading device
The book pointed that the capacitor in the input of a transistor acts as a loading capacitor. How and what it loads and where does it load?
Some insight in any form will be really helpful.
Member • Aug 12, 2013
Member • Aug 22, 2013
Member • Aug 22, 2013
Member • Aug 22, 2013
Member • Aug 22, 2013
Yup true But David Bell states That capacitors serve 3 purposepinankAhh...no...they are primarily used as filters...either to filter out harmonics or as a lpf, hpf etc etc
Member • Aug 22, 2013
Member • Aug 22, 2013
mreccentricloading circuits? ... doesn't that mean it works as a load?
Member • Aug 23, 2013
Member • Aug 24, 2013
A fully discharged capacitor can act as a DC load till it is fully charged. It has effectively zero resistance to start with. After this its equivalent resistance increases and it just blocks DC. It will let through AC signals.ConquerorWell I am not sure load is connected in the input section of the circuit right
Loading occurs in the input and not in the output side where we use a loading resistance to increase or decrease the output impedance
Member • Aug 24, 2013
Sir but won't that be for a very small fraction of time..as the capacitor will charge up almost instantaneously(at least theoretically)A.V.RamaniA fully discharged capacitor can act as a DC load till it is fully charged. It has effectively zero resistance to start with. After this its equivalent resistance increases and it just blocks DC. It will let through AC signals.
I am not sure if this behaviour is what is referred to by David Bell.
Member • Aug 24, 2013
You are right. Often that is all that is required.pinankSir but won't that be for a very small fraction of time..as the capacitor will charge up almost instantaneously(at least theoretically)
Member • Aug 26, 2013
i counter this... It's not always a fraction of time. The rate of charging can be altered. So, i guess, it can be made so that the capacitor may act as a DC load for long time (in other words infinite time).pinankSir but won't that be for a very small fraction of time..as the capacitor will charge up almost instantaneously(at least theoretically)
Member • Aug 26, 2013
Every capacitor has an RC value, which is a function for charging time. The R restricts the charging current. the total charge that can be held is decided by the C value. infinite time is possible only with infinite R. That is open circuit. Otherwise it is finite.mreccentrici counter this... It's not always a fraction of time. The rate of charging can be altered. So, i guess, it can be made so that the capacitor may act as a DC load for long time (in other words infinite time).
Member • Aug 26, 2013
The capacitor will always tend to reach its steady state value ie once it is fully charged it acts as a open switch and the rate can be altered by changing the time constant value.. But at say time equals infinity it will eventually act as a open switchmreccentrici counter this... It's not always a fraction of time. The rate of charging can be altered. So, i guess, it can be made so that the capacitor may act as a DC load for long time (in other words infinite time).
Member • Sep 3, 2013
Member • Sep 5, 2013
Member • Sep 6, 2013
Can you be more specific Cos How is the capacitor going to affect the impedance of the circuittanmoyacapacitors prevents loading effect means...... 'loading effect' means short circuiting of input source. if the circuit has low input impedence then the circuit will draw maximum current and this will result on short circuiting of input source.
Member • Sep 6, 2013
Member • Apr 29, 2014
Member • May 1, 2014
Member • May 1, 2014
Member • May 1, 2014
capacitors are also used for timming purpose in an electronic cktsJeffrey SamuelWhat exactly is the loading effect of capacitor? I found this as one of the main applications of the capacitor in electronic circuits.
The book pointed that the capacitor in the input of a transistor acts as a loading capacitor. How and what it loads and where does it load?
Some insight in any form will be really helpful.
Member • May 1, 2014
Member • Jun 12, 2014
Member • Jun 13, 2014
Member • Jun 13, 2014
Yeah u r pretty much right..I got it all wrong.. :/Jeffrey SamuelSource has some reactive impedance so I am not sure what you are implying
Can you pls post a little schematic here to explain the scenario little more clearly?
And Load is generally at the output side and the trans impedance effect of it on the input source is really less in case of Semi conductors right