Calculating impedence.
Hello
I have three Led's with forward drop of 1.7 V and 10
milliamp current. I am using 9 V battery with 15 miliamp. I used this
website that gave me value of resistor to be used when LED in series or
in parallel.
For 3 led in Series, value is 390 ohms, i.e.
9V-(1.7*3)V/0.01= 390 Ohms
For 3 LED in 'Parallel', it states voltage drop of 243.33 Ohms ??
Can anyone please advise me on what formula i need to use to LED in parallel to derive this value?
I have three Led's with forward drop of 1.7 V and 10
milliamp current. I am using 9 V battery with 15 miliamp. I used this
website that gave me value of resistor to be used when LED in series or
in parallel.
For 3 led in Series, value is 390 ohms, i.e.
9V-(1.7*3)V/0.01= 390 Ohms
For 3 LED in 'Parallel', it states voltage drop of 243.33 Ohms ??
Can anyone please advise me on what formula i need to use to LED in parallel to derive this value?
Replies
-
Ahsanul haqueV=IR
Parallel:
V = 9 - 1.7
I = 3 * 0.01
Series:
V = 9 - (1.7 * 3)
I = 0.01
Solve for R. may be it will work.
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