Calculating impedence.

Ahsanul haque

Ahsanul haque

@ahsanul-haque-2o7iUb • Oct 16, 2024
Hello

I have three Led's with forward drop of 1.7 V and 10
milliamp current. I am using 9 V battery with 15 miliamp. I used this
website that gave me value of resistor to be used when LED in series or
in parallel.


For 3 led in Series, value is 390 ohms, i.e.
9V-(1.7*3)V/0.01= 390 Ohms

For 3 LED in 'Parallel', it states voltage drop of 243.33 Ohms ??
Can anyone please advise me on what formula i need to use to LED in parallel to derive this value?
Like 0 Replies 1

Replies

Welcome, guest

Join CrazyEngineers to reply, ask questions, and participate in conversations.

Sign up Log in

CrazyEngineers powered by Jatra Community Platform

  • Ahsanul haque

    Ahsanul haque

    @ahsanul-haque-2o7iUb • Sep 17, 2013

    V=IR

    Parallel:
    V = 9 - 1.7
    I = 3 * 0.01

    Series:
    V = 9 - (1.7 * 3)
    I = 0.01

    Solve for R. may be it will work.
    0