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  • All about Pointers

    Manish Goyal

    Manish Goyal

    @manish-r2Hoep
    Updated: Jan 15, 2011
    Views: 964
    Let us discuss everything about pointers, starting from basic definition to each and every error that generally occurs while doing programming in c++ through this thread


    I am sure it will help a lot of students
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  • Manish Goyal

    Member • Jan 16, 2011

    No reply so far

    come on guys ,didn't you find any problem while working with pointers?If yes, then share it
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  • sachin bankar

    Member • Jan 20, 2011

    Pointer is a variable which holds address of another variable
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  • Ankita Katdare

    Administrator • Jan 20, 2011

    Thank you Goyal for starting this thread.
    Everyone learning C or C++ faces problems with pointers at the beginner level.

    Could someone start with explaining the basics of pointers and their various forms?
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  • Deepika Bansal

    Member • Jan 20, 2011

    Pointers have some relation with with 1D and 2D arrays. I'm quoting the example of a C++ program.
    void main()
{
int a[5];    //creating an integer array to store upto 5 integers
cout<<a;   //output is the memory address of the element a[0] ie starting address of array

//one way to access elements of array
for(int i=0;i<5;i++)
  cout<<a[i];

//another way using pointers
for(int i=0;i<5;i++)
  cout<<*(a+i);   //*(a+i) is equivalent to a[i]
}
    This was the case of static sized arrays ie size of the array is known at the compile time.
    eg:- consider the following code-->
    //this is okay
const int size=5;   //creating a constant variable
int a[size];

//but this is wrong
int size=5;
int a[size];
    so to create dynamic arrays (eg when size has to be known from the user), we make use of pointers as-->
    int size;
int *a;   //uninitialized pointer
cout<<"Enter the size of the array: ";
cin>>size;   //got the array size from the user
a=new int[size];  //a can now hold upto 'size' number of variables

//now the elements of 'a' can be accessed in any of the 2 ways discussed above.
    Also there is a difference between int a=new int[size]; and int a=new int(size);
    int a=new int[size]; will create an array 'a' of size/length='size'.
    but int a=new int(size); will create an int variable ie only 2 bytes will be allocated to 'a' whose value or memory content will be='size'.


    PS: It's been very long that I've revised my C++ concepts. If anyone finds any error or ambiguity, please do let me know.😀 Will try to post the maximum of my knowledge about pointers.😛
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