x is a real number, attains a minimum at

Sir / Madam,
My questions is,

The function f(x) = |x – 2| + |2.5 – x| + |3.6 – x|, where x is a real number, attains a minimum at ??

Advance Thanks,
R.Rengaraj
{InfosysTrain-Q107 Pg26}

Replies

  • Saandeep Sreerambatla
    Saandeep Sreerambatla
    Is it 2.9? Notsure though!!
  • rengaraj
    rengaraj
    Dear English,
    Can you explain your answer?
    The choices are 2.5,2.7,2.3,None of These
    R.Rengaraj
  • limestone7000
    limestone7000
    my first step would be to club the 2nd and 3rd terms
    so,
    |2.5 - x| + |3.6 - x|
    = |6.1 - 2x|

    now,
    f(x) = |x - 2| + |6.1 - 2x|

    by observing, x shouldn't be negative if u want minimum value of f(x),
    so, x>0

    now,
    for x = 2.3, f(x) = 1.8
    for x = 2.5, f(x) = 1.6
    for x = 2.7, f(x) = 1.4
    [observe that as the value of x increases, value of f(x) decreases]
    2.7 could be the answer, but to verify, lets take x = 2.9
    so, f(x) = 1.2 for x = 2.9!!!!

    hence, the answer is NONE OF THESE!
    😀
  • rengaraj
    rengaraj
    Dear Limestone,
    Excellent reply.
    Keep it up.
    R.Rengaraj
  • tdave
    tdave
    "observe that as the value of x increases, value of f(x) decreases" so x=2.9!

    it really take me some time..
  • anu_mech
    anu_mech
    i suppose u cant club 2.5-x and 3.6-x. 'cause if x is between 2.5 and 3.6 one positive and the other negative
    observe the function its value is
    f(x)= 8.1-3x (for x<2)
    =4.1-x (for 2 =x-.9 (for 2.5 =3x-8.1 (for x>3.6)

    plot the graph and u get....2.9
  • HImanshu_Sharma
    HImanshu_Sharma
    yeah limestone is right

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