Write a Program to Calculate Time Value of Money and get Paid

Replies

• 

  Manish Goyal

  no one??
  
  Come on Guys Please help me I have already developed the logic the only thing that I am not able to crack is this increase rate,
  
  Please I am ready to pay even, your efforts and time will be compensated
  
  Thanks in advance
• 

  ManojKiran Eda

  can u please explain me the question more elaborately so that i can help u...as i am good as these type of problems..
• 

  Manish Goyal

  you can google this, the only difference is increase rate on payment, i just need change for that in the actual formula for time value of money
• 

  Kaustubh Katdare

  Looks like we'll have to tag a few people: @#-Link-Snipped-# , @#-Link-Snipped-#
• 

  Manish Goyal

  I think here only a guy with great knowledge of finance related formula can help me, I can develop program myself, only I need formula for this type of calcultion
  
  Anyone here in CE???
• 

  ManojKiran Eda

  Hai #-Link-Snipped-#,
  I have ur code ready ..I am a beginner so I wrote the code in C (gcc in Linux)language....
  
  Code#
  ####################################################################
  
  #include
  #include
  void main(void)
  {float pay_per,pay,rate,inc_rate,incr_per_months,amount,t;
  int u,i;
  printf("Enter the total amount to be paid :");//given pay=200$
  scanf("%f",&pay);
  printf("Enter the amount that u want to pay per time :");//given u will pay 50$
  scanf("%f",&pay_per);
  printf("Interest amount per time:");//interest rate=16.5$
  scanf("%f",&rate);
  printf("Time after which the rate is increased (months):");// half year(6 months) rate is increased
  scanf("%f",&incr_per_months);//incr_per_months=6
  printf("Increse in rate in(%):");//Increased in rate=5%
  scanf("%f",&inc_rate);//inc_rate=5
  rate=(rate*100)/pay;//conversion of interest rate=16.5$ interms of percentage
  t=0.0;
  incr_per_months=incr_per_months/12;//converting months into years
  u=pay/pay_per;
  for(i=0;i<=(u-1);i++)
  {t=t+((pay-(i*pay_per))*pow((1+(inc_rate/100)),i));
  }
  amount=pay+(incr_per_months*(rate/100)*t);
  printf("Total Amount is :%f\n",amount);
  }
  
  ##########################################################################
  
  I have attached the output screen...
  
  If u have any further clarification ask me...
• 

  simplycoder

  @BigK, Thanks for tagging me.
  
  Hi Manish,
  For semi annual rate of increase, you can divide the rate by 2 and multiply the period by 2.
  Hence amount=pow(P*[1+r/2], (2*n))
  
  Share your thoughts here. It would be more helpful if you can share a complete use-case with us with input and the expected output values.
  
  Thanks.
• 

  Uday Bidkar

  public class TimeValueOfMoney {
      public static void main(String[] args){
          double futureValue = 0;
          float monthlyPayment = 200, monthlyInterestRate = 16.5f/12, incrementInMonthlyInterest = 5.0f/12;
          int totalPayments = 50;
          int incrementIntervalInMonths = 6;
          for(int i=1; i<=totalPayments;i++){
              futureValue += monthlyPayment;
              futureValue = futureValue + (futureValue*(monthlyInterestRate/100));
              if((i % incrementIntervalInMonths) == 0){
                  monthlyInterestRate += incrementInMonthlyInterest;
              }
          }
          System.out.println("Final amount = " + futureValue);
      }
  }

• 

  Uday Bidkar

  @#-Link-Snipped-# , I think amount=pow(P*[1+r/2], (2*n)) won't work as it doesn't take into account the increase in interest rate after every six months. It will work only when the interest rate is constant and interest is calculated and accumulated every six months.
• 

  Manish Goyal

  OK Here is one test case
  
  Assuming I gave someone loan (of amount ?)on date : 2/21/2014
  
  and he started returning me payment back on 12/12/2014 in installments of 25
  
  At nominal rate 16.50 and increase rate of 5% Semi annually.
  
  Now I want to calculate loan amount?
  
  For the above case it will be 1972.05
  
  For more information: Please refer this link : #-Link-Snipped-#
  
  I am trying to develop web version of this software
  
  Thanks