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@pratap-singh-6xlmve • May 24, 2012
Assuming that you know the difference between a forward biased diode and a reverse biased diode.
in order to solve such problems there are two approaches
- ideal case
- non-ideal case
however in non-ideal case, replace the forward biased diodes with short wires and add a battery of value equal to the pinch off voltage(nearly 0.7 volts for germanium and 1.1 volts for silicon) in such a way that on moving in direction of current positive plate of the battery is incurred first. Reverse biased diodes are simply replaced by an open circuit.
it looks like non-ideal approach has to be followed
Do inform me if you get the correct results on solving the transformed circuit. -
@enghussein-i1SU2y • May 24, 2012
You are right bro it is a non-ideal case and we should determine the current by using Kirchoff voltage law for each loop but my major concerned is about the diodes when it will be converted to a voltage source and applying VKL are they will be summed with the regular Voltage source like any electrical circuit if they are in the same direction and subtracted if they are in opposite ?
By the way I had my final exam couple days a go and I did well 👍
Thanks respectfully -
@pratap-singh-6xlmve • May 25, 2012
but I did give you the way to connect the diode equivalent voltage sources; just use it to find out the solutioneng.husseinYou are right bro it is a non-ideal case and we should determine the current by using Kirchoff voltage law for each loop but my major concerned is about the diodes when it will be converted to a voltage source and applying VKL are they will be summed with the regular Voltage source like any electrical circuit if they are in the same direction and subtracted if they are in opposite ?
By the way I had my final exam couple days a go and I did well 👍
Thanks respectfully
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