Which bowl does he choose to pour their taster from?

Replies

• 

  akash.kasina

  the bowl which we filled with with fruit cocktail contains the highest concentration among both bowls!😀
• 

  KenJackson

  I'm missing something here.
  
  "A pint bowl of water" sounds like a container that has a capacity of one pint and is full. If you start with two bowls that are full of their respective fluids and pour one into the other, the other will overflow. Is that part of the puzzle, or do I just misunderstand?
• 

  Vassilya

  Assuming they didn't overflow (see previous) then they would be equal after the first exchange, methinks
• 

  silverscorpion

  After the first swapping, the concentrations of water and the cocktail in both glasses will be equal, I think.. Similarly after the 2nd time too..
• 

  Sagar07

  Bowl b...
• 

  ashie

  Bowl A
• 

  KenJackson

  Since I didn't get an answer to my question, I'm going to make some assumptions:
  

  1. The phrase "a pint bowl of" means a container that holds exactly one pint and is exactly full,
  2. "Fruit cocktail" is a liquid with similar properties to water (no chunks),
  3. When something is poured into a full bowl, it's quickly poured into the center of the bowl such that only the existing fluid overflows, none of the fluid being poured in overflows, and
  4. It's somehow possible to thoroughly mix a full bowl without spilling any.

  Let's start:
  
  1) Pour half a pint from water (A) into cocktail (b) and mix.
  Overflow: 1/2 pint of cocktail, leaving:
  (A) 1/2 pint of water
  (b) 1 pint of 50% water
  
  2) Pour 1 pint from (b) to (A) and mix.
  Overflow: 1/2 pint of water, leaving:
  (A) 1 pint of 50% water
  (b) empty
  
  3) Pour 1/4 pint from (A) to (b) and mix.
  (A) 3/4 pint of 50% water
  (b) 1/4 pint of 50% water
  
  4) Pour 1/4 pint from (b) to (A) and mix.
  (A) 1 pint of 50% water
  (b) empty
  
  Answer: Bowl (A) has the "strong" fruit cocktail, 50%, because bowl (b) is empty.
• 

  Sagar07

  Well, let me justify my ans...
  Suppose both bowls contain 64 liters each..
  
  Now, 32 liters of water is poured into bowl b...
  
  So, bowl b=32 liters of water+ 64 liters of cocktail= 96 liters in the ratio of 1:2 of water and cocktail...
  
  
  Now, 48 liters(16 liters of water and 32 liters of cocktail) of bowl b is poured into bowl A...
  
  So, bowl A=32 liters of water+ 32 liters of cocktail + 16 liters of water= 80 liters in the ratio of 3:2 of water and cocktail...
  
  
  Now, 20 liters(12 liters of water and 8 liters of cocktail) of bowl A is poured into bowl b...
  
  So, bowl b=16 liters of water+32 liters of cocktail+ 12 liters of water + 8 liters of cocktail= 68 liters in the ratio of 7:10 of water and cocktail...
  
  
  Now, 17 liters(7 liters of water and 10 liters of cocktail) of bowl b is poured into bowl A...
  
  So, bowl A=36 liters of water+24 liters of cocktail+ 7 liters of water + 10 liters of cocktail= 77 liters in the ratio of 43:34 of water and cocktail...
  
  
  Ratio of water and cocktail
  Bowl A= 43:34
  Bowl b=7:10
  
  So, Bowl b contains stronger fruit cocktail...
  
  Note: Assuming bowls didn't overflow...
• 

  Ramani Aswath

  Given that the volumes of both bowls are equal after the double exchange, the concentration of of fruit cocktail in the water bowl and the concentration of water in the fruit bowl will be the same. This is true for every exchange. Curiously this is true even if there was no mixing at all.
  In my opinion both will reach equal dilution asymptotically. In real terms the original cocktail bowl will always have the higher concentration of the cocktail
• 

  KenJackson

  Sagar07

  Suppose both bowls contain 64 liters each..

  That contradicts the problem statement. Each container was described as "a pint bowl."
  A Pint is two cups or 16 floz (about 474 mL).
• 

  Sagar07

  KenJackson

  That contradicts the problem statement. Each container was described as "a pint bowl."
  A Pint is two cups or 16 floz (about 474 mL).

  Well, then consider mL instead of Liters......