What's the output of this C program?
main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
Replies
-
Kaustubh KatdareI added a better title to the question. I think you're asking about the output of this program, right? Why not just run it and check for yourself? -
rahul69
It will print 8,bhulaxmimain()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
After the printf statement is executed, the pointer ptr had move to next address, and the value at earlier address is incremented (ie, becomes 5), if u still got any doubts, plz do share 😀 -
Nayan GoenkaI think this program will generate output 10. Still working on it. Will give a definite output once I execute it on my side. But I guess you already know that this function is not just complete program. It needs prototypes or header files to run.
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