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@rengaraj • 19 Dec, 2009
Sir / madam,
My question is
A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
Advance Thanks,
R.Rengaraj
{3i Infotech}
My question is
A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
Advance Thanks,
R.Rengaraj
{3i Infotech}
@yadavundertaker mohit • 19 Dec, 2009
liquid after mixing = 12/5 + 3 = 5.4ltr
% of liquid = (5.4/22)*100
= 24.5%
% of water = 100 - 24.5
=75.5%
% of liquid = (5.4/22)*100
= 24.5%
% of water = 100 - 24.5
=75.5%
@rengaraj • 20 Dec, 2009
Hi,
Thanks for your quick reply,
R.Rengaraj
Thanks for your quick reply,
R.Rengaraj
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