What is the number of poles initially ?

Replies

• 

  yadavundertaker mohit

  length of gap with n poles = 1000/(n-1)
  
  new length of gap = 1000/(n-2)
  
  according to question
  
  1000/(n-2)= 5/3 + 1000/(n-1)
  
  1000(n-1-n+2)/(n-1)(n-2)=5/3
  
  
  on solving n = 26
  
  number of poles initially is 26.....
  1000/(n-1)(n-2)= 5/3
• 

  rengaraj

  Sir,
  I got the question from an book but, the solution was 25. But i can't get the steps worked.
  But i will try once more.
  R.Rengaraj
• 

  yadavundertaker mohit

  the no. of poles will be 25 after one pole is removed..
  
  steps
  
  length of gaps = total length in meter /(no. of ploes -1) [we minus 1 because a gap will be exist b/w two poles]
• 

  CIVILPRINCESS

  yes the number of poles initially is 26.by simplifying the equation yadav got we get
  n^2-3n-598=0
  26 solves it.
• 

  yadavundertaker mohit

  hi rengraj
  
  did you check the answer again?....
• 

  rengaraj

  Sir,
  The solution is 25.
  Thanks,
  R.Rengaraj
• 

  Anil Jain

  if n poles (n-1) gaps of each 1000/(n-1) width
  if n-1 poles (n-2) gaps of each 1000/(n-2) width
  so,
  1000/(n-2) -1000/(n-1)=5/3
  1000(1/(n-2) -1/(n-1))=5/3
  
  so number of poles initially would be 26 only.
• 

  rengaraj

  Sir,
  This is an Infosys question. The given answer is 25.
  R.Rengaraj