What is the number of poles initially ?

What is the number of poles initially ?

rengaraj
@rengaraj-89Rrct

Updated: Oct 25, 2024

Views: 2.3K

Sir / madam,
My question is

A 1 KM long wire is held by 'n' poles. If one pole is removed the length of the gap increases by 5/3 meters. What is the number of poles initially ?

Advance Thanks,
R.Rengaraj
{NIT 23/2007/Pg 3 (Infosys Part-1)}
{On this forum my 12th Question.

0

Replies

Howdy guest!

Dear guest, you must be logged-in to participate on CrazyEngineers. We would love to have you as a member of our community. Consider creating an account or login.

Replies

yadavundertaker mohit

Member • Nov 25, 2009

length of gap with n poles = 1000/(n-1)

new length of gap = 1000/(n-2)

according to question

1000/(n-2)= 5/3 + 1000/(n-1)

1000(n-1-n+2)/(n-1)(n-2)=5/3

on solving n = 26

number of poles initially is 26.....
1000/(n-1)(n-2)= 5/3

Are you sure? This action cannot be undone.
Cancel
rengaraj

Member • Nov 25, 2009

Sir,
I got the question from an book but, the solution was 25. But i can't get the steps worked.
But i will try once more.
R.Rengaraj

Are you sure? This action cannot be undone.
Cancel
yadavundertaker mohit

Member • Nov 25, 2009

the no. of poles will be 25 after one pole is removed..

steps

length of gaps = total length in meter /(no. of ploes -1) [we minus 1 because a gap will be exist b/w two poles]

Are you sure? This action cannot be undone.
Cancel
CIVILPRINCESS

Member • Nov 26, 2009

yes the number of poles initially is 26.by simplifying the equation yadav got we get
n^2-3n-598=0
26 solves it.

Are you sure? This action cannot be undone.
Cancel
yadavundertaker mohit

Member • Nov 28, 2009

hi rengraj

did you check the answer again?....

Are you sure? This action cannot be undone.
Cancel
rengaraj

Member • Nov 29, 2009

Sir,
The solution is 25.
Thanks,
R.Rengaraj

Are you sure? This action cannot be undone.
Cancel
Anil Jain

Member • Nov 29, 2009

if n poles (n-1) gaps of each 1000/(n-1) width
if n-1 poles (n-2) gaps of each 1000/(n-2) width
so,
1000/(n-2) -1000/(n-1)=5/3
1000(1/(n-2) -1/(n-1))=5/3

so number of poles initially would be 26 only.

Are you sure? This action cannot be undone.
Cancel
rengaraj

Member • Nov 30, 2009

Sir,
This is an Infosys question. The given answer is 25.
R.Rengaraj

Are you sure? This action cannot be undone.
Cancel