@rengaraj • 25 Nov, 2009

Sir / madam,

My question is

A 1 KM long wire is held by 'n' poles. If one pole is removed the length of the gap increases by 5/3 meters. What is the number of poles initially ?

Advance Thanks,

R.Rengaraj

{NIT 23/2007/Pg 3 (Infosys Part-1)}

{On this forum my 12th Question.

My question is

A 1 KM long wire is held by 'n' poles. If one pole is removed the length of the gap increases by 5/3 meters. What is the number of poles initially ?

Advance Thanks,

R.Rengaraj

{NIT 23/2007/Pg 3 (Infosys Part-1)}

{On this forum my 12th Question.

@yadavundertaker mohit • 25 Nov, 2009
length of gap with n poles = 1000/(n-1)

new length of gap = 1000/(n-2)

according to question

1000/(n-2)= 5/3 + 1000/(n-1)

1000(n-1-n+2)/(n-1)(n-2)=5/3

on solving n = 26

number of poles initially is 26.....

1000/(n-1)(n-2)= 5/3

new length of gap = 1000/(n-2)

according to question

1000/(n-2)= 5/3 + 1000/(n-1)

1000(n-1-n+2)/(n-1)(n-2)=5/3

on solving n = 26

number of poles initially is 26.....

1000/(n-1)(n-2)= 5/3

@rengaraj • 26 Nov, 2009
Sir,

I got the question from an book but, the solution was 25. But i can't get the steps worked.

But i will try once more.

R.Rengaraj

I got the question from an book but, the solution was 25. But i can't get the steps worked.

But i will try once more.

R.Rengaraj

@yadavundertaker mohit • 26 Nov, 2009
the no. of poles will be 25 after one pole is removed..

steps

length of gaps = total length in meter /(no. of ploes -1) [we minus 1 because a gap will be exist b/w two poles]

steps

length of gaps = total length in meter /(no. of ploes -1) [we minus 1 because a gap will be exist b/w two poles]

@CIVILPRINCESS • 27 Nov, 2009
yes the number of poles initially is 26.by simplifying the equation yadav got we get

n^2-3n-598=0

26 solves it.

n^2-3n-598=0

26 solves it.

@yadavundertaker mohit • 29 Nov, 2009
hi rengraj

did you check the answer again?....

did you check the answer again?....

@rengaraj • 29 Nov, 2009
Sir,

The solution is 25.

Thanks,

R.Rengaraj

The solution is 25.

Thanks,

R.Rengaraj

@Anil Jain • 30 Nov, 2009
if n poles (n-1) gaps of each 1000/(n-1) width

if n-1 poles (n-2) gaps of each 1000/(n-2) width

so,

1000/(n-2) -1000/(n-1)=5/3

1000(1/(n-2) -1/(n-1))=5/3

so number of poles initially would be 26 only.

if n-1 poles (n-2) gaps of each 1000/(n-2) width

so,

1000/(n-2) -1000/(n-1)=5/3

1000(1/(n-2) -1/(n-1))=5/3

so number of poles initially would be 26 only.

@rengaraj • 30 Nov, 2009
Sir,

This is an Infosys question. The given answer is 25.

R.Rengaraj

This is an Infosys question. The given answer is 25.

R.Rengaraj

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