Member • Jun 23, 2012
Member • Jun 24, 2012
Member • Jun 24, 2012
Member • Jun 24, 2012
SYED BASEERULLAHI don't understand whether you are asking your doubts or testing others knowledge.
sorry if you get hurt by my words[/quo...i goi was asking that there are four component in vcr system...just tell me that what is the specific component to which if u will remove from that system then its c.o.p will become zero and it will stop working....SYED BASEERULLAHI don't understand whether you are asking your doubts or testing others knowledge.
sorry if you get hurt by my words
Member • Jun 24, 2012
u r not getting my question...i am explaning again that i was asking that what is the specific component in vcr system to which if u will remove from this system then its c.o.p will be equal to "zero" then obviously it will stop working...and i want to tell u one thing more that except that specific component if u will remove other component then it will work but will not be useful for refrigeration purpose,,,and it is very intresting question sir...pradeep74mI don't know what kind of question is this?. If you remove a component from a system and if its still working then its either a back up or dead weight. As far as i know backups are not essential for refrigerating units and dead weights in any industry just adds to the cost.
Member • Jun 24, 2012
Member • Jun 24, 2012
Member • Jun 25, 2012
If any one of the components is not present then the system wont work.nibhaniu are not g
u r not getting my question...i am explaning again that i was asking that what is the specific component in vcr system to which if u will remove from this system then its c.o.p will be equal to "zero" then obviously it will stop working...and i want to tell u one thing more that except that specific component if u will remove other component then it will work but will not be useful for refrigeration purpose,,,and it is very intresting question sir...
Member • Jun 25, 2012
sysyem will work but will not give required effect...white_hatIf any one of the components is not present then the system wont work.
Member • Jun 25, 2012
i think that if u will remove expansion valve then the system will stop working because its c.o.p will become zero..and except expansion valve if u will remove any another component then it will not stop working but will not give desired effect...pradeep74mI guess you are not understanding the concept well, if you remove either of the four the system would stop working.
Member • Jun 25, 2012
degree of randomness of molecule is called entropy of any system...if randomness will increase then entropy will also increase and if it will decrease then entropy will also decrease...ESSAexplain entropy please
Member • Jun 25, 2012
Member • Jun 25, 2012
A system is said to be working only when it gives the desired output. Otherwise no matter what it does it wont be considered working. Achieving a compression or expansion alone is not the function of vcrs system. As far as technical terms concern the system wont work even if you remove any one of the four basic components of vcrs.nibhanii think that if u will remove expansion valve then the system will stop working because its c.o.p will become zero..and except expansion valve if u will remove any another component then it will not stop working but will not give desired effect...
Member • Jun 26, 2012
ok..working of a system and desired output both are different things...i was asking about stop working totaly...and there is only one component named expansion valve to which if u will remove it will stop working totaly...but if u will remove any another component then it will not give desired output but it will work....pradeep74mA system is said to be working only when it gives the desired output. Otherwise no matter what it does it wont be considered working. Achieving a compression or expansion alone is not the function of vcrs system. As far as technical terms concern the system wont work even if you remove any one of the four basic components of vcrs.
Member • Jun 26, 2012
adiabatic process is a process in which there no heat transfer takes place and reversible adiabatic process is called isentropic process in which entopy remains constant ..........both are ideal process which are not possible in practical life...ESSAexplain adiabatic isotropic isentropic process
Member • Jun 26, 2012
and ok pradeep sir just stop discusson on this matter...a/c to me its possible and a/c to u its not possible..so thanks sir for ur coorporation...thanks a lot...nibhaniadia
adiabatic process is a process in which there no heat transfer takes place and reversible adiabatic process is called isentropic process in which entopy remains constant ..........both are ideal process which are not possible in practical life...
Member • Jun 26, 2012
Member • Jun 26, 2012
So what output are we expecting?nibhanisysyem will work but will not give required effect...
Member • Jun 26, 2012
we are expecting higher c.o.p as output...white_hatSo what output are we expecting?
Member • Jun 26, 2012
about which question u are talking zaveri?zaveri#-Link-Snipped-#
now that is one interesting question. you can give the answer, and explain it in more detail.
Member • Jun 26, 2012
Your concept of working itself is a misunderstanding i think. Each component of the system is capable of functioning alone but without the output from the previous component the system will never work. For example if you take the compressor from the unit out there wont be anything for the expansion valve to expand and the system would cease to work. The same is the case with each component.nibhaniok..working of a system and desired output both are different things...i was asking about stop working totaly...and there is only one component named expansion valve to which if u will remove it will stop working totaly...but if u will remove any another component then it will not give desired output but it will work....
